Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN: 9781133939146
Author: Katz, Debora M.
Publisher: Cengage Learning
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Chapter 18, Problem 11PQ
To determine
How emitting a sound pulse can allow a creature to locate other objects.
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Sperm whales, just like bats, use echolocation to find prey. A sperm whale’s vocal system creates a single sharp click, but the emitted sound consists of several equally spaced clicks of decreasing intensity. Researchers use the time interval between the clicks to estimate the size of the whale that created them. Explain how this might be done.
Although we can't hear them, the ultrasonic pulses are very loud. In order not to be deafened by the
sound they emit, bats can temporarily turn off their hearing. Muscles in the ear cause the bones in their
middle ear to separate slightly, so that they don't transmit vibrations to the inner ear. After an
ultrasound pulse ends, a bat can hear an echo from an object a minimum of 1 m away. Approximately
how much time after a pulse is emitted is the bat ready to hear its echo?
A. 0.5 ms
B. 1 ms
C. 3 ms
D. 6 ms
The bellow of a territorial bull hippopotamus is measured at 110 dB above the threshold of hearing. What is the sound intensity? Hint:
The threshold of human hearing is lo = 1.00 x 10 12 W/m2.
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Chapter 18 Solutions
Physics for Scientists and Engineers: Foundations and Connections
Ch. 18.1 - As shown in Figure 18.3, two pulses trawling along...Ch. 18.1 - Prob. 18.2CECh. 18.2 - A wave pulse travels to the left on a rope as...Ch. 18.3 - Noise cancellation headphones use a microphone to...Ch. 18.8 - Tuning the Guitar Before a performance, a piano is...Ch. 18 - Prob. 1PQCh. 18 - Two pulses travel in opposite directions along a...Ch. 18 - Prob. 3PQCh. 18 - Prob. 4PQCh. 18 - Prob. 5PQ
Ch. 18 - The wave function for a pulse on a rope is given...Ch. 18 - Prob. 7PQCh. 18 - Prob. 8PQCh. 18 - Prob. 9PQCh. 18 - Prob. 10PQCh. 18 - Prob. 11PQCh. 18 - Two speakers, facing each other and separated by a...Ch. 18 - Prob. 13PQCh. 18 - Prob. 14PQCh. 18 - Prob. 15PQCh. 18 - As in Figure P18.16, a simple harmonic oscillator...Ch. 18 - A standing wave on a string is described by the...Ch. 18 - The resultant wave from the interference of two...Ch. 18 - A standing transverse wave on a string of length...Ch. 18 - Prob. 20PQCh. 18 - Prob. 21PQCh. 18 - Prob. 22PQCh. 18 - Prob. 23PQCh. 18 - A violin string vibrates at 294 Hz when its full...Ch. 18 - Two successive harmonics on a string fixed at both...Ch. 18 - Prob. 26PQCh. 18 - When a string fixed at both ends resonates in its...Ch. 18 - Prob. 28PQCh. 18 - Prob. 29PQCh. 18 - A string fixed at both ends resonates in its...Ch. 18 - Prob. 31PQCh. 18 - Prob. 32PQCh. 18 - Prob. 33PQCh. 18 - If you touch the string in Problem 33 at an...Ch. 18 - A 0.530-g nylon guitar string 58.5 cm in length...Ch. 18 - Prob. 36PQCh. 18 - Prob. 37PQCh. 18 - A barrel organ is shown in Figure P18.38. Such...Ch. 18 - Prob. 39PQCh. 18 - Prob. 40PQCh. 18 - The Channel Tunnel, or Chunnel, stretches 37.9 km...Ch. 18 - Prob. 42PQCh. 18 - Prob. 43PQCh. 18 - Prob. 44PQCh. 18 - If the aluminum rod in Example 18.6 were free at...Ch. 18 - Prob. 46PQCh. 18 - Prob. 47PQCh. 18 - Prob. 48PQCh. 18 - Prob. 49PQCh. 18 - Prob. 50PQCh. 18 - Prob. 51PQCh. 18 - Prob. 52PQCh. 18 - Prob. 53PQCh. 18 - Dog whistles operate at frequencies above the...Ch. 18 - Prob. 55PQCh. 18 - Prob. 56PQCh. 18 - Prob. 57PQCh. 18 - Prob. 58PQCh. 18 - Prob. 59PQCh. 18 - Prob. 60PQCh. 18 - Prob. 61PQCh. 18 - Prob. 62PQCh. 18 - The functions y1=2(2x+5t)2+4andy2=2(2x5t3)2+4...Ch. 18 - Prob. 64PQCh. 18 - Prob. 65PQCh. 18 - Prob. 66PQCh. 18 - Prob. 67PQCh. 18 - Prob. 68PQCh. 18 - Two successive harmonic frequencies of vibration...Ch. 18 - Prob. 70PQCh. 18 - Prob. 71PQCh. 18 - Prob. 72PQCh. 18 - A pipe is observed to have a fundamental frequency...Ch. 18 - The wave function for a standing wave on a...Ch. 18 - Prob. 75PQCh. 18 - Prob. 76PQCh. 18 - Prob. 77PQCh. 18 - Prob. 78PQCh. 18 - Prob. 79PQCh. 18 - Prob. 80PQ
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Female Aedes aegypti mosquitoes emit a buzz at about 4.00102 Hz, whereas male A. aegypti mosquitoes typically emit a buzz at about 6.00102 Hz. As a female mosquito is approaching a stationary male mosquito, is it possible that he mistakes the female for a male because of the Doppler shift of the sound she emits? How fast would the female have to be traveling relative to the male for him to make this mistake? Assume the speed of sound in the air is 343 m/s.arrow_forwardEver since seeing Figure 16.22 in the previous chapter, you have been fascinated with the hearing response in humans. You have set up an apparatus that allows you to determine your own threshold of hearing as a function of frequency. After performing the experiment and recording the results, you graph the results, which look like Figure P17.22. You are intrigued by the two dips in the curve at the right-hand side of the graph. You measure carefully and find that the minimum values of these dips occur at 3 800 Hz and 11 500 Hz. Performing some online research, you discover that the outer canal of the human ear can be modeled as an air column open at the outer end and closed at the inner end by the eardrum. You use this information to determine the length of the outer canal in your car. Figure P17.22arrow_forwardAn interstate highway has been built through a neighborhood in a city. In the afternoon, the sound level in an apartment in the neighborhood is 80.0 dB as 100 cars pass outside the window every minute. Late at night, the traffic flow is only five cars per minute. What is the average late-night sound level?arrow_forward
- A source of sound vibrates with constant frequency. Rank the frequency of sound observed in the following cases from highest to the lowest. If two frequencies are equal, show their equality in your ranking. All the motions mentioned have the same speed, 25 m/s. (a) The source and observer are stationary. (b) The source is moving toward a stationary observer. (c) The source is moving away from a stationary observer. (d) The observer is moving toward a stationary source. (e) The observer is moving away from a stationary source.arrow_forwardOn a particular day the speed of sound in air is 340 m/s. If a plane flies at a speed of 680 m/s, is its Mach number (a) 1.5, (b) 2.0, (c) 2.5, or (d) 2.7?arrow_forwardOf the following sounds, which one is most likely to have a sound level of 60 dB? (a) a rock concert (b) the turning of a page in this textbook (c) dinner-table conversation (d) a cheering crowd at a football gamearrow_forward
- With a sensitive sound-level meter, you measure the sound of a running spider as -10 dB. What does the negative sign imply? (a) The spider is moving away from you. (b) The frequency of the sound is too low to be audible to humans. (c) The intensity of the sound is too faint to be audible to humans. (d) You have made a mistake; negative signs do not fit with logarithms.arrow_forwardA sound wave traveling in air has a pressure amplitude of 0.5 Pa. What is the intensity of the wave?arrow_forwardWhat is the sound level of a sound wave with intensity 6.40 105 W/m2?arrow_forward
- Owls communicate using long-wavelength hoots, while songbirds use short-wavelength tweets. Which of the sounds can be heard over a greater distance in a forest? Neither the hoot nor the tweet will be able to penetrate the forest. Both the hoot and tweet will travel the same distance through the forest. hoot of the owl tweet of the songbirdarrow_forwardSound is detected when a sound wave causes the eardrum to vibrate (as shown). Typically, the diameter of the eardrum is about 8.4 mm in humans. When someone speaks to you in a normal tone of voice, the sound intensity at your ear is approximately 1.0 × 10-6 W/m2. How much energy is delivered to your eardrum each second?arrow_forwardAs discussed in the chapter, many species of bats find flying insects by emitting pulses of ultrasound and listening for the reflections. This technique is called echolocation. Bats possess several adaptations that allow them to echolocate very effectively. Although we can’t hear them, the ultrasonic pulses are very loud. In order not to be deafened by the sound they emit, bats can temporarily turn off their hearing. Muscles in the ear cause the bones in their middle ear to separate slightly, so that they don’t transmit vibrations to the inner ear. After an ultrasound pulse ends, a bat can hear an echo from an object a minimum of1 m away. Approximately how much time after a pulse is emitted is the bat ready to hear its echo?A. 0.5 ms B. 1 ms C. 3 ms D. 6 msarrow_forward
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What Are Sound Wave Properties? | Physics in Motion; Author: GPB Education;https://www.youtube.com/watch?v=GW6_U553sK8;License: Standard YouTube License, CC-BY