Concept explainers
An ore deposit consisting of chert and hematite occurs in a deposit measuring 2,500 m long by 1.800 m wide by 75 m high. The deposit has an average specific gravity of 4.3. How many tonnes of iron can potentially be obtained from the mine? (Specific gravity can be converted to density by multiplying by the density of water. Assume SGhematite = 5.3, SGchert = 2.5. and g/cm3 = tonne/m3.)
The tonnes of iron can potentially be obtained from the mine, if hematite and chert occurs in a deposit measuring
Answer to Problem 10PEB
Solution:
Explanation of Solution
Given data:
Specific gravity of hematite is
Specific gravity of deposit is
Specific gravity of chert is
Length of the deposit is
Width of the deposit is
Height of the deposit is
Density of deposit is
Formula used:
Write the percent of hematite:
Here,
Write the formula for density
Here,
Write the formula for volume:
Here,
The mass of hematite in the deposit by multiplying the total mass of the deposit by the ore grade:
The mass of iron by multipling the mass of hematite by the mass percentage of iron in hematite:
Explanation:
Recall the percent of hematite:
Substitute
Recall the formula for density
Rearrange:
Recall the formula for volume:
Substitute
Substitute
Recall the mass of hematite in the deposit by multiplying the total mass of the deposit by the ore grade:
Substitute
For Hematite:
The formula:
The formula weight of Hematite:
Recall the mass percent of an element in a compound can be found from:
Substitute
Recall the mass of iron by multiplying the mass of hematite by the mass percentage of iron in hematite:
Substitute
Conclusion:
The mass of iron is
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