Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840544
Author: George F. Limbrunner, Craig D'Allaird, Leonard Spiegel
Publisher: PEARSON
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Chapter 16, Problem 16.12P
Design simply supported timber beams (S4S) for the following uniformly distributed line loads and spans:
a. eastern white pine, 5.0 kN/m, 7-m span length
b. southern pine, 6.3 kN/m, 8-m span length
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Design a timber beam of hem-fir (S4S) to support a uniformly distributed line load of 250 Ib/ft on a simply supported span of 6 ft. Deflection is not to exceed span/300.
1. SIMPLE BEAM: UNIFORMLY DISTRIBUTED LOAD
TABLE E.1 U.S. Customary units
R=V
Nominal Size in.
Dressed Size in.
A in.2
Wt. Ib/ft
I, in.4
S, in.
2 x 4
1} × 3}
5.25
1.46
5.36
3.06
V,
x 5
x 7
x 6
8.25
2.29
20.8
7.56
M max (at center)
x 8
10.9
3.02
47.6
13.1
x 10
13.9
3.85
98.9
21.4
M,
Shear
x 11
x 13
x 12
16.9
4.68
178
31.6
Amux (at center).
384EI
x 14
19.9
5.52
291
43.9
M max
x 16
x 15
22.9
6.35
443
58.2
4,
24
Moment
x 18
x 17
25.9
7.17
642
74.5
3 x 4
2} x 3)
8.75
2.42
8.93
5.10
x 5}
x 7
TABLE F.1 U.S. Customary units
x 6
13.8
3.82
34.7
12.6
x 8
18.1
5.04
79.4
21.9
Allowable Stress" (psi)
Modulus of
x 10
x9}
23.1
6.42
165
35.6
Elasticity E
(ksi)
Species
Fc
F,
Fo
F,
x 12
x 11}
28.1
7.81
297
52.7
x 13
x 15
x 17
Douglas fir
1050
550
625
900
180
1700
x 14
33.1
9.20
485
73.2
Southern pine
1250
410
825
1400
175
1700
x 16
38.1…
2. Design a timber beam (S4S) made of Douglas fir to support the load shown
below.
500 lbs/ft
Ju
12'-0
Identify the arrangement for the beam of shear
force diagram shown here.
Simply supported beam subjected to
UVL for entire span
Cantilever beam subjected to UDL for
entire span
Cantilever beam subjected to point load at
free end
Simply supported beam subjected to UDL
for entire span
Chapter 16 Solutions
Applied Statics and Strength of Materials (6th Edition)
Ch. 16 - Prob. 16.1PCh. 16 - A simply supported beam is to support a uniformly...Ch. 16 - Rework Problem 16.1 given a load of 1.0 kip/ft and...Ch. 16 - Select the lightest W shape to support a...Ch. 16 - Select the lightest W shape to support a...Ch. 16 - 16.6 A simply supported beam is to span 15 ft. It...Ch. 16 - 16.7 A simply supported beam is to span 24 ft. It...Ch. 16 - 16.8 Design a timber beam of hem-fir (S4S) to...Ch. 16 - Select simply supported timber beams (S4S) for the...Ch. 16 - 16.10 Select a southern pine (S4S) timber beam for...
Ch. 16 - 16.11 Select simply supported hem-fir (S4S) joists...Ch. 16 - Design simply supported timber beams (S4S) for the...Ch. 16 - For the following computer problems, any...Ch. 16 - 16.16 Select the lightest W shape to support a...Ch. 16 - 16.17 Select the lightest W shape for the beam...Ch. 16 - Select the lightest W shape for the cantilever...Ch. 16 - 16.19 Select the lightest W shape to support a...Ch. 16 - 16.20 Select the lightest W shape for the beams...Ch. 16 - 16.21 The structural steel floor system shown is...Ch. 16 - 16.22 The structural steel framing plan shown...Ch. 16 - 16.23 Select the lightest steel wide-flange...Ch. 16 - 16.24 Select the lightest steel wide-flange...Ch. 16 - 16.25 Design the lightest W-shape beams to support...Ch. 16 - 16.26 In Problem 16.18, assume that the 500 lb/ft...Ch. 16 - 16.27 Select a southern pine (S4S) simply...Ch. 16 - 16.28 A redwood beam is to support a uniformly...Ch. 16 - 16.29 A partial plan view for a residential floor...Ch. 16 - 16.30 For the floor framing of Problem 16.29,...Ch. 16 - 16.31 Select a Douglas fir (S4S) beam for the...Ch. 16 - 16.32 Select southern pine (S4S) simply supported...Ch. 16 - 16.33 Rework Problem 16.32 using joists spaced 12...Ch. 16 - 16.34 Select Douglas fir (S4S) simply supported...Ch. 16 - 16.35 Select southern pine (S4S) simply supported...Ch. 16 - 16.36 A 15-ft-span simply supported hem-fir (S4S)...Ch. 16 - 16.37 Select a timber beam (S4S) of Southern pine...Ch. 16 - 16.38 A series of 14-ft-long Douglas fir (S4S)...Ch. 16 - 16.39 A cantilever beam 3 m long is to be made...Ch. 16 - 16.40 Select an eastern white pine (S4S) beam for...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Analysis and design of continuous beams: Q1/ Draw the load pattern for the beams B1&B2, If imposed dead load equal to (2.5 kN/m?), and live load equal to (4.8 kN/m?),are applied on the floor ,Assume all beams have the same dimensions and the beams supports as a simply span? Y. = 24 kN / m' ,all columns are (400*400) mm the secondary beam in the middle of span B2? 8m 180mm B1 5m 300mm 200mm B2arrow_forwardA 10 × 10 beam of Douglas fir–larch select structural gradesupports a single concentrated load of 10 kips at the center of the span. Investigate the beam for sheararrow_forwardWhat are the W shapes that would be used for unbraced lengths? A W shape is to be used for a uniformly loaded simple beamcarrying a total dead load of 26 kips and a total live load of 26 kips on a36-ft span. Select the lightest weight shape for unbraced lengths of (1) 9 ft, (2) 12 ft, and (3) 18 ft. A W shape is to be used for a uniformly loaded simple beamcarrying a total dead load of 30 kips and a total live load of 40 kips on a 24-ft span. Select the lightest weight shape for unbraced lengths of (1) 6 ft, (2) 8 ft, and (3) 12 ft.arrow_forward
- Select the lightest wide flange steel section for simple beam of 10 ft span that will carry a uniform load of 10 kips/ft. Use A36 and assume that the beam is supported laterally for its entire length. [Hint: V max = WL/2; M max = L WL²/8]arrow_forwardtask 01 part c An encase beam with uniform distributed load shown in following figure. W= 250N/m and L= 5m. Draw the shear force and B.M. diagrams for the beam with necessary calculations.arrow_forwardFigure 14.20 Full Alternative Text 14.21 A solid rectangular simply supported timber beam 6 in. wide, 20 in. deep, and 10 ft long carries a concentrated load of 16,000 lb at midspan. Use nominal dimensions. a. Compute the maximum horizontal shear stress at the neutral axis. b. Compute the shear stress 4 in. and 8 in. above and below the neutral axis. Neglect the weight of the beam.arrow_forward
- Compute the reactions of the supports of beams; 1. AB 2. CD 3. EF 4.GH 5. IJ 6. KLarrow_forwardA simply supported beam of length 7m is carrying a uniformly distributed load of 1.25N/m for its entire length. What will be the total load on the beam? Select one: a. 8.75N b. 5.75N c. 87.5m d. 8.75marrow_forwardplease translate the following problem descriptions into al diagrammatic representation, solve for/draw the shear force and bending moment diagrams and find the deflection and/or slope as indicated: 3. A 16 ft. long simply supported beam is loaded by a 1 k/ft uniform distributed load for the first 6 ft. and (2) point loads, 3 kips each, at 9 ft. and 12 ft. A Structural No. 1 timber (E = 1,600,000 psi) is specified with nominal dimensions of 6x12. Find the magnitude and location of the maximum deflection.arrow_forward
- Activity 1 Calculate the shear force and the maximum bending moment of beams using for the construction bridge and building. An Encastre /Built-in beam has a span of 3 m and carries the loading system shown in figure 1 (a). 40KN 30kN/m 1.8m -1.2m Figure 1(a): Encastre / Built-in In addition, you should be able to calculate the shear force and the maximum bending moment of a cantilever beam, with a hollow cross-section of Dout: 0.2 m, wall thickness of 0.02 m, and the length of 3 (m). The beam is subjected to a point load of 50 kN at its free end as shown in Figure 1 (b). Dout 50KN 3m Figure 1(b): Cantilever beamarrow_forwardQuestion 5 a) What is the importance of SFD and BMDs for structural engineers? b) For the beam and loading shown in Fig 5-1. i. iii. 2 kN/m -3 m- Figure 5-1 4 kN/m 1.5 m- B Page 5 of 6 Determine the support reactions at A. Draw the shear force diagrams (SFD), clearly indicating the shear force along the span at AB. Draw the bending moment diagrams (BMD), clearly indicating the moments along the span AB.arrow_forward4. A simply supported beam with a span of 5 m is built with the isolated T-section shown in Fig. (4). The beam is used to support a uniformly distributed dead load (including self-weight) of 20 kN/m and uniformly distributed live load of 25 kN/m. If the simply supported beam is part of floor attached to partition not likely to be damaged by the deflection, check if the deflection in the beam within the permissible limits of ACI318 code? ( Assume 20% of the live load is sustained after 5- years). Given: fc=21 MPa, and f,=420 MPa, and n = 9. 700 mm |75 mm Stirrups #10 5#32 400 mm 300 mm Fig. (4)arrow_forward
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