Principles of Physics: A Calculus-Based Text
5th Edition
ISBN: 9781133104261
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 11, Problem 14OQ
(a)
To determine
The kinetic energy of the electron.
(b)
To determine
The potential energy of the atom.
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One model for the potential energy of a two-atom molecule, where the atoms are separated by a distance r, is U(r) = U0 [(r0 / r)16 - (r0 / r)9] where r0 = 0.70 nm and U0 = 7.0 eV. Note: 1 eV = 1.6*10-19 J. You can use SI units, but CAPA will also accept these units that will simplify your calculations: [Force] = eV/nm[Energy] = eV[distance] = nm
r_eq = 7.6 *10^-1 nm
If the distance between the atoms increases from equilibrium by r1 = 0.20 nm, then what is the force from one atom on the other associated with this potential energy? (Enter your answer as postive if they repel each other, and negative if they attract). F_r (r_eq +r_1) = ?
The atoms are oscillating back and forth. The maximum separation of the atoms is r2 = 2.2 nm. What is the kinetic energy of the atoms when they are separated by the equilibrium distance? K(r_eq) = ?
One model for the potential energy of a two-atom molecule, where the atoms are separated by a distance r, is
U(r)=U0[(r0/r)12−(r0/r)4]
where r0 = 0.65 nm and U0 = 7.4 eV.Note: 1 eV = 1.6×10−19 J.Some helpful units:[Force] = eV/nm[Energy] = eV[distance] = nm
Here is what I am having trouble with:
You can choose where the potential energy equals zero anywhere you want (you can add or subtract any constant to it). For this function, U(∞) = 0. This is very common for electromagnetic problems like you will see in Physics 2. If the potential energy function were defined as
U(r)=U0[(r0/r)12−(r0/r)4]+U1
where U1 = 4.5 eV, reanswer all of the previous questions using this new potential energy function.
req= ?
Fr(req+r1)= ?
K(req)= ?
(NOTE: these are all part of the same question)
I got .957026 nm for req, and -1.4348 eV/nm for Fr(req+r1), and I couldnt get an answer for K(req). My answers are wrong. Where am I not understanding?
In another two-atom molecule that is breaking apart, the force from one atom to the other is given by
F12= F0(r/r2)e^-(r/r2)^2
where F0 = 15.6 eV/nm and r2 = 2.2 nm. Find the change in potential energy of the molecule due to this force if the separation of the atoms changes from r = 2.5 nm to r = 4.1 nm.
Chapter 11 Solutions
Principles of Physics: A Calculus-Based Text
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- One model for the potential energy of a two-atom molecule, where the atoms are separated by a distance r, is U(r)=U0[(r0/r)12−(r0/r)4] where r0 = 0.65 nm and U0 = 7.4 eV.Note: 1 eV = 1.6×10−19 J.Some helpful units:[Force] = eV/nm[Energy] = eV[distance] = nm Here is what I am having trouble with: What is the distance between the atoms when the molecule is in stable equilibrium? If the distance between the atoms increases from equilibrium by r1 = 0.2 nm, then what is the force from one atom on the other associated with this potential energy? (Enter your answer as postive if they repel each other, and negative if they attract.)arrow_forwardOne model for the potential energy of a two-atom molecule, where the atoms are separated by a distance r, is U(r) = Uo[()13 – (4)1 where ro = 0.7 nm and Ug = 7.1 ev. Note: 1 eV = 1.6 × 10–19 J. Some helpful units: [Force] = eV/nm [Energy] = eV [distance] = nmarrow_forwardOne model for the potential energy of a two-atom molecule, where the atoms are separated by a distance r, is U (r) = Uo[()¹5 (70)6] where ro = 0.6 nm and U₁ = 7.7 eV. Note: 1 eV = 1.6 x 10-¹⁹ J. Some helpful units: [Force] = eV/nm [Energy] = eV [distance] = nm Equilibrium Distance Force Kinetic Energy AddedConstant AnotherMolecule In another two-atom molecule that is breaking apart, the force from one atom to the other is given by F12 Fo (r/r₂) e-(1/₂)² = where Io = 12.7 eV/nm and r₂ = 2 nm. Find the change in potential energy of the molecule due to this force if the separation of the atoms changes from r = 3 nm to r = 4.3 nm. Click here for a hint AU= = <arrow_forward
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