Question 2: This diagram shows an example of memory configuration under dynamic partitioning, aftera number of placement and swapping-out operations have been carried out. Addresses go from left toright; gray areas indicate blocks occupied by processes; white areas indicate free memory blocks. Thelast process placed is 2-Mbyte and is marked with an X. Only one process was swapped out after that.4MM X 5M8M2M 4M3Ma. What was the maximum size of the swapped-out process?b. What was the size of the free block just before it was partitioned by X?C.A new 3-Mbyte allocation request must be satisfied next. Indicate the intervals of memorywhere a partition will be created for the new process under the following four placementalgorithms: best-fit, first-fit, next-fit, worst-fit. For each algorithm,

Certainly, I can provide a more detailed explanation of the memory configuration and the placement…

Answered: Question 2: This diagram shows an…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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2. Suppose we have the diagram of memory shown below under a dynamic partitioning scheme. Blue areas represent blocks occupied by processes, blanks are holes (with sizes in Mbytes as indicate), The cross-hatched region is the location of the most recently loaded process. It is the only process in that region of memory. Its size is 5 M-byte. Only one process was swapped out after that. What is the maximum size of the swapped-out process? What is the size of the free block just before it was portioned by the crosshatched process? What algorithm was used to place the 5 Mbyte process? Why? 12 34 3 4 06 20
4. The following is the memory configuration at a given point in time where dynamic partitioning scheme is used. The shaded areas indicate memory spaces already allocated to other processes, while the white spaces are holes (free memory spaces). The next FOUR (4) memory requests are 30M, followed by 50M, 20M and 40M (in order). Shade and indicate clearly which memory block will be allocated to each request using the first- fit and next-fit placement algorithms. (First-fit) 20M (Best-fit) 20M (Next-fit) 20M 80M 1 2 3 4 80M 80M b. Given a process segment table as follows: Segment 0 (X is the lastest allocated block) 20M Base 496 1202 232 2359 1877 20M 20M Length 691 85 198 109 258 50M 50M 50M 10M 10M 10M X 30M 30M 30M Explain the basic use of segment table in process segmentation and its difference with paging. Give one example on how the information in the given process segment table is used.
4. The following is the memory configuration at a given point in time where dynamic partitioning scheme is used. The shaded areas indicate memory spaces already allocated to other processes, while the white spaces are holes (free memory spaces). The next FOUR (4) memory requests are 30M, followed by 50M, 20M and 40M (in order). Shade and indicate clearly which memory block will be allocated to each request using the first- fit and next-fit placement algorithms. (First-fit) 20M (Best-fit) 20M (Next-fit) 20M 80M 80M 20M 80M 20M (X is the lastest allocated block) 20M 50M 50M 50M 10M 10M 10M X 30M 30M 30M
A disk has a capacity of two tera-byte size. Say the file system uses a multi-level inode structure for locating the data blocks of afile.The inode stores pointers to data blocks, including a single indirect block, a double indirect block, and several direct blocks in the 64 B of available space.Now, it is given that the disk has a block size of 512 B. The maximum file size that can be stored in such a file system in MB (round off upto 2 decimal places).
The following is the memory configuration at a given point in time where dynamic partitioning scheme is used. The shaded areas indicate memory spaces already allocated to other processes, while the white spaces are holes (free memory spaces). The next FOUR (4) memory requests are 10MB, followed by 50MB, 30MB and 40MB (in order). Shade and indicate clearly which memory block will be allocated to each request using the first-fit, best-fit and next-fit placement algorithms. 20 80 20 50 10 X 30 (All in MB) Complete the answer here: Muat-pertama (First-fit) X (All in MB) Muat-terbaik (Best-fit) (All in MB) Muat-berikut (Next-fit) (All in MB) X (X ialah blok terkini diperuntukkan) (X is the lastest allocated block) X
We use fixed partitioning for a main memory (M) of size 1GiB. Each same sized partition is of the same size 256KiB. The machine is a 32-bit architecture. 1. How many partitions do we have for M? 2. A logical address is thus split into a partition number and partition offset within that partition. How many bit for the partition number ? 3. A logical address is thus split into a partition number and partition offset within that partition. How many bit for the partition offset ? 4. We store the information related to the partitions in a table PaT. PaT has one entry per partition. Thus PaT[ i ] shows the PID of the process occupying that partition. PID are linux PIDs and we provided some information about them in Subject 3 when we discussed the Process List. A PID consists of a number of bit that is a power of two multiple of the number of bit of a byte i.e. 8bit, 16bit, 32bit, etc. What is the length of the PaT table/array ? 5. We store the information related to the partitions in…
We use fixed partitioning for a main memory (M) of size 1GiB. Each same sized partition is of the same size 256KiB. The machine is a 32-bit architecture.1. How many partitions do we have for M? 2. A logical address is thus split into a partition number and partition offset within that partition. How many bit for the partition number ? 3. A logical address is thus split into a partition number and partition offset within that partition. How many bit for the partition offset ? 4. We store the information related to the partitions in a table PaT. PaT has one entry per partition. Thus PaT[ i ] shows the PID of the process occupying that partition. PID are linux PIDs and we provided some information about them in Subject 3 when we discussed the Process List. A PID consists of a number of bit that is a power of two multiple of the number of bit of a byte i.e. 8bit, 16bit, 32bit, etc. What is the length of the PaT table/array ? 5. We store the information related to the partitions in a…
Consider a file system on a disk that has both logical and physical block sizes of 512 bytes. Assume that the information about each file is al ready in memory. For each of the three allocation strategies (contiguous, linked, and indexed), answer these questions: a. How is the logical-to-physical address mapping accomplished in this system? (For the indexed allocation, assume that a file is always less than 512 blocks long.) b. If we are currently at logical block 10 (the last block accessed was block 10) and want to access logical block 4, how many physical blocks must be read from the disk
Main memory size is 16 pages. Size of swap file on hard disk is 64 pages. Operating system locks down pages 0, 1, 2 and 7 in the main memory. Two programs are started and both are provided with a virtual address space of 10 pages. Initially operating system allocates 5 pages of main memory for each program and the rest from swap file. Virtual address space of each program starts from page 0. Construct page tables for both programs at program startup. A page table consists of P-bit which tells if the page is present in the main memory (1 = page is in main memory) and address of the page. Address tells either real address in main memory or the address of the page in swap file. b. A computer with a paged virtual memory system executes two load instructions that are adjacent to each other in memory. Describe the worst case scenario (in terms of performance) that can occur during the execution of the two instructions and explain under which conditions this case occurs. How does this affect…
Consider a filesystem that uses inodes to represent files. Each inode contains pointers to 12 direct disk blocks, as well as a single and double indirect blocks. Disk blocks are 1KB in size, and a pointer to a disk block requires 4 bytes. If we install this filesystem on a 4TB SSD, we have (select all that apply) the SSD cannot store more than 4 billion files the SSD cannot store more than 1 billion files the SSD at least can store about 650 files the SSD at least can store about 6,500 files none of above
iz Instructions through the questions for each of the sections. You may submit this exercise twice. Consider a memory of size 8KB (8192 bytes) that allows dynamic, variable sized partitioning among processes and uses a linked list to keep track of free spaces (hereafter referred to as the free list) in the memory at any given time. Assume that there are 6 processes and assume that their memory size requirements (in bytes) are as given below: P1: 500, P2: 600, P3: 1300, P4: 2000, P5: 100, P6: 200 Assume that the initial state of the free list is as shown below (BA is the base address and Sz is the size of each free space): BA: 0; Sz: 1100 BA: 1200: Sz: 600 BA: 2000; Sz: 1800→BA: 6000; Sz 400 in its initial state Assume that the next fit policy
7.6. This diagram shows an example of memory configuration under dynamic partition- ing, after a number of placement and swapping-out operations have been carried out. Addresses go from left to right; gray areas indicate blocks occupied by processes; white areas indicate free memory blocks. The last process placed is 2-Mbyte and is marked with an X. Only one process was swapped out after that. 2M 4M 4M X 5M 8M 3M a. What was the maximum size of the swapped-out process? b. What was the size of the free block just before it was partitioned by X? c. A new 3-Mbyte allocation request must be satisfied next. Indicate the intervals of memory where a partition will be created for the new process under the fol- lowing four placement algorithms: best-fit, first-fit, next-fit, and worst-fit. For each algorithm, draw a horizontal segment under the memory strip and label it clearly.

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