Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
Experiment 1 Fulcrum Position → (m) Mass Position Object 0.3369 m Distance to Fulcrum Diagram 62→ (kg) (m) (m) M1 0.1179 kg 0.1 m 0.2369 m mg forende)=7x mg MSTICK 0.1459 kg 0.4999 m 0.1630 m CCW = mgd2 (1=3932 Experiment 2 Fulcrum Position → 0.4999 m Diagram (m) Mass Position Object Distance to Fulcrum Diagram 2 N (kg) (m) 0.48m (m) K ΜΙ 0.1179 kg 0.25 m 0.2499 m T M2 0.2179 kg 0.75 m 0.2501 m mig my (29) I fulcrum mzg M3 0.0679 kg 0.0198 m 0.4801 m Experiment 3 Fulcrum Position → 0.5547 m Diagram Distance to Mass Position Object Fulcrum Diagram 3 0.055m (kg) (m) (m) ΜΙ 0.1179 kg 0.25 m 0.3047 m A fuerunt M2 0.2179 kg 0.75 m 0.1953 m mg m₂g MSTICK 0.1459 kg 0.4999 m 0.0548 m

Experiment 1 Fulcrum Position → (m) Mass Position Object 0.3369 m Distance to Fulcrum Diagram 62→ (kg) (m) (m) M1 0.1179 kg 0.1 m 0.2369 m mg forende)=7x mg MSTICK 0.1459 kg 0.4999 m 0.1630 m CCW = mgd2 (1=3932 Experiment 2 Fulcrum Position → 0.4999 m Diagram (m) Mass Position Object Distance to Fulcrum Diagram 2 N (kg) (m) 0.48m (m) K ΜΙ 0.1179 kg 0.25 m 0.2499 m T M2 0.2179 kg 0.75 m 0.2501 m mig my (29) I fulcrum mzg M3 0.0679 kg 0.0198 m 0.4801 m Experiment 3 Fulcrum Position → 0.5547 m Diagram Distance to Mass Position Object Fulcrum Diagram 3 0.055m (kg) (m) (m) ΜΙ 0.1179 kg 0.25 m 0.3047 m A fuerunt M2 0.2179 kg 0.75 m 0.1953 m mg m₂g MSTICK 0.1459 kg 0.4999 m 0.0548 m

icon
Related questions
Question

University Physics 1 - Rotation, Angular momentum, and Torque

I need help with this problem and an explanation of the solutions described below:

- A torque meter stick experiment

 

 For each 3 experiments (Image of the data is below), calculate the net clockwise and counterclockwise torques acting on the meterstick. Show the full calculation being done with all numbers identified.

 

Experiment 1                                      Experiment 2                                     Experiment 3

 

Experiment 1 Fulcrum Position → (m) Mass Position Object (kg) (m) 0.3369 m Distance to Fulcrum (m) Diagram LJ1 √2 → M1 0.1179 kg 0.1 m 0.2369 m FO mg forend=x m₂g MSTICK 0.1459 kg 0.4999 m 0.1630 m (Cw=mgd2 (1=2932 Experiment 2 Fulcrum Position → (m) 0.4999 m Diagram Distance to Mass Position Object Fulcrum Diagram 2 N 0.48m (kg) (m) (m) KE Μ1 0.1179 kg 0.25 m 0.2499 m M2 0.2179 kg 0.75 m 0.2501 m mig (m₂9) ↑ fulcrum mzg M3 0.0679 kg 0.0198 m 0.4801 m Experiment 3 Fulcrum Position → 0.5547 m Diagram (III) Distance to Mass Position Diagram 3 0.055m Object Fulcrum (kg) (m) (m) M1 0.1179 kg 0.25 m 0.3047 m A fulltan M2 0.2179 kg 0.75 m 0.1953 m mg m₂g MSTICK 0.1459 kg 0.4999 m 0.0548 m
Transcribed Image Text:Experiment 1 Fulcrum Position → (m) Mass Position Object (kg) (m) 0.3369 m Distance to Fulcrum (m) Diagram LJ1 √2 → M1 0.1179 kg 0.1 m 0.2369 m FO mg forend=x m₂g MSTICK 0.1459 kg 0.4999 m 0.1630 m (Cw=mgd2 (1=2932 Experiment 2 Fulcrum Position → (m) 0.4999 m Diagram Distance to Mass Position Object Fulcrum Diagram 2 N 0.48m (kg) (m) (m) KE Μ1 0.1179 kg 0.25 m 0.2499 m M2 0.2179 kg 0.75 m 0.2501 m mig (m₂9) ↑ fulcrum mzg M3 0.0679 kg 0.0198 m 0.4801 m Experiment 3 Fulcrum Position → 0.5547 m Diagram (III) Distance to Mass Position Diagram 3 0.055m Object Fulcrum (kg) (m) (m) M1 0.1179 kg 0.25 m 0.3047 m A fulltan M2 0.2179 kg 0.75 m 0.1953 m mg m₂g MSTICK 0.1459 kg 0.4999 m 0.0548 m
Expert Solution
steps

Step by step

Solved in 4 steps with 5 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer