Derive Kelvin’s formula and the maximum free energy formula: rd* = 2 σLV /nL RT ln S ΔG = 16 π σLV^3 / 3 (nL RT ln S)^2 where σLV =surface tension, nL = moles of liquid water per unit volume, R = universal gas constant, T = temperature S = supersaturation pure liquid water = e/es(T) : e = water vapor partial pressure The first equation can also be rearranged to give an expression for the supersaturation, S: ln S = 2 σLV /nL RT rd* or S = exp(2 σLV /nL RT rd*)
Derive Kelvin’s formula and the maximum free energy formula: rd* = 2 σLV /nL RT ln S ΔG = 16 π σLV^3 / 3 (nL RT ln S)^2 where σLV =surface tension, nL = moles of liquid water per unit volume, R = universal gas constant, T = temperature S = supersaturation pure liquid water = e/es(T) : e = water vapor partial pressure The first equation can also be rearranged to give an expression for the supersaturation, S: ln S = 2 σLV /nL RT rd* or S = exp(2 σLV /nL RT rd*)
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Derive Kelvin’s formula and the maximum free energy formula:
rd* = 2 σLV /nL RT ln S
ΔG = 16 π σLV^3 / 3 (nL RT ln S)^2
where
σLV =surface tension, nL = moles of liquid water per unit volume, R = universal gas constant, T = temperature
S = supersaturation pure liquid water = e/es(T) : e = water vapor partial pressure
The first equation can also be rearranged to give an expression for the supersaturation, S:
ln S = 2 σLV /nL RT rd* or S = exp(2 σLV /nL RT rd*)
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