(a)
Calculate the probability distribution of two team’s scores.
(a)
Explanation of Solution
The probability distribution of scores is shown in below table.
Table 1
Home team | ||||
Visiting team | 0 | 1 | 2 | 3 |
0 | 0.14 | 0.11 | 0.09 | 0.10 |
1 | 0.12 | 0.10 | 0.05 | 0.02 |
2 | 0.09 | 0.07 | 0.04 | 0.01 |
3 | 0.03 | 0.02 | 0.01 | 0 |
Probability distribution of two team’s scoresis shown in below table.
P(T) | Probability distribution |
P(T=0) | 0.14 |
P(T=1) | 0.23 |
P(T=2) | 0.28 |
P(T=3) | 0.25 |
P(T=4) | 0.08 |
P(T=5) | 0.02 |
P(T=6) | 0 |
Probability distribution: The probability distribution shows the probabilities of incidence of different likely outcomes in a test.
(b)
Mean,variance and standard deviation.
(b)
Explanation of Solution
Mean of team’s scores is calculated as follows.
Mean value is 0.96.
Variance of team’s scores is calculated as follows.
Variance is 1.538.
Standard deviation (square root of variance) of team’s scores is calculated as follows.
Standard deviation is 1.240.
(c)
Covariance and coefficient of correlation.
(c)
Explanation of Solution
Covariance and coefficient of correlation of two team’s score is calculated as follows.
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Chapter 7 Solutions
Statistics for Management and Economics (Book Only)
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