Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
8th Edition
ISBN: 9780134421377
Author: Charles H Corwin
Publisher: PEARSON
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Chapter 7, Problem 73E
Interpretation Introduction

(a)

Interpretation:

The complete balanced chemical equation for the reaction of MgSO4 with BaCl2 is to be stated.

Concept introduction:

The process in which the reactants combine to form a new product is called a chemical reaction. The chemical and physical properties of the products are different from the reactants. The different types of chemical reactions are combination reaction, decomposition reaction and displacement reaction.

Expert Solution
Check Mark

Answer to Problem 73E

The complete balanced chemical equation for the reaction of MgSO4 with BaCl2 is given below.

MgSO4(aq)+BaCl2(aq)BaSO4(s)+MgCl2(aq)

Explanation of Solution

The reaction in which the ions of two reactants get exchanged to form products is known as double-replacement reaction.

The balanced equation follows the law of conservation of mass. The unbalanced equation means that number of the atoms of an element present in the reactant is not equal to the product side.

The given chemical equation is shown below.

MgSO4(aq)+BaCl2(aq)

It is stated by law of conservation of mass that, “during any chemical reaction, the mass of product must be equal to mass of the reactants”.

Therefore, the complete balanced chemical equation for the reaction of MgSO4 with BaCl2 is given below.

MgSO4(aq)+BaCl2(aq)BaSO4(s)+MgCl2(aq)

Conclusion

The complete balanced chemical equation for the reaction of MgSO4 with BaCl2 is given below.

MgSO4(aq)+BaCl2(aq)BaSO4(s)+MgCl2(aq)

Interpretation Introduction

(b)

Interpretation:

The complete balanced chemical equation for the reaction of FeSO4 with Ca(OH)2 is to be stated.

Concept introduction:

The process in which the reactants combine to form a new product is called a chemical reaction. The chemical and physical properties of the products are different from the reactants. The different types of chemical reactions are combination reaction, decomposition reaction and displacement reaction.

Expert Solution
Check Mark

Answer to Problem 73E

The complete balanced chemical equation for the reaction of FeSO4 with Ca(OH)2 is given below.

FeSO4(aq)+Ca(OH)2(aq)Fe(OH)2(s)+CaSO4(s)

Explanation of Solution

The reaction in which the ions of two reactants get exchanged to form products is known as double-replacement reaction.

The balanced equation follows the law of conservation of mass. The unbalanced equation means that number of the atoms of an element present in the reactant is not equal to the product side.

The given chemical equation is shown below.

FeSO4(aq)+Ca(OH)2(aq)

It is stated by law of conservation of mass that, “during any chemical reaction, the mass of product must be equal to mass of the reactants”.

Therefore, the complete balanced chemical equation for the reaction of FeSO4 with Ca(OH)2 is given below.

FeSO4(aq)+Ca(OH)2(aq)Fe(OH)2(s)+CaSO4(s)

Conclusion

The complete balanced chemical equation for the reaction of FeSO4 with Ca(OH)2 is given below.

FeSO4(aq)+Ca(OH)2(aq)Fe(OH)2(s)+CaSO4(s)

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Chapter 7 Solutions

Introductory Chemistry: Concepts and Critical Thinking (8th Edition)

Ch. 7 - Prob. 11CECh. 7 - Prob. 12CECh. 7 - Prob. 13CECh. 7 - Prob. 14CECh. 7 - Prob. 15CECh. 7 - Prob. 16CECh. 7 - Prob. 1KTCh. 7 - Prob. 2KTCh. 7 - Prob. 3KTCh. 7 - Prob. 4KTCh. 7 - Prob. 5KTCh. 7 - Prob. 6KTCh. 7 - Prob. 7KTCh. 7 - Prob. 8KTCh. 7 - Prob. 9KTCh. 7 - Prob. 10KTCh. 7 - Prob. 11KTCh. 7 - Prob. 12KTCh. 7 - Prob. 13KTCh. 7 - Prob. 14KTCh. 7 - Prob. 15KTCh. 7 - Prob. 16KTCh. 7 - Prob. 17KTCh. 7 - Prob. 18KTCh. 7 - Prob. 19KTCh. 7 - Prob. 20KTCh. 7 - Prob. 21KTCh. 7 - Prob. 22KTCh. 7 - Prob. 1ECh. 7 - Prob. 2ECh. 7 - Prob. 3ECh. 7 - Prob. 4ECh. 7 - Prob. 5ECh. 7 - Prob. 6ECh. 7 - Prob. 7ECh. 7 - Prob. 8ECh. 7 - Prob. 9ECh. 7 - Prob. 10ECh. 7 - Prob. 11ECh. 7 - Prob. 12ECh. 7 - Prob. 13ECh. 7 - Prob. 14ECh. 7 - Prob. 15ECh. 7 - Prob. 16ECh. 7 - Prob. 17ECh. 7 - Prob. 18ECh. 7 - Prob. 19ECh. 7 - Prob. 20ECh. 7 - Prob. 21ECh. 7 - Prob. 22ECh. 7 - Prob. 23ECh. 7 - Prob. 24ECh. 7 - Prob. 25ECh. 7 - Prob. 26ECh. 7 - Prob. 27ECh. 7 - Prob. 28ECh. 7 - Prob. 29ECh. 7 - Prob. 30ECh. 7 - Prob. 31ECh. 7 - Prob. 32ECh. 7 - Prob. 33ECh. 7 - Prob. 34ECh. 7 - Prob. 35ECh. 7 - Prob. 36ECh. 7 - Prob. 37ECh. 7 - Prob. 38ECh. 7 - Prob. 39ECh. 7 - Prob. 40ECh. 7 - Prob. 41ECh. 7 - Prob. 42ECh. 7 - Prob. 43ECh. 7 - Prob. 44ECh. 7 - Prob. 45ECh. 7 - Prob. 46ECh. 7 - Prob. 47ECh. 7 - Prob. 48ECh. 7 - Prob. 49ECh. 7 - Prob. 50ECh. 7 - Prob. 51ECh. 7 - Prob. 52ECh. 7 - Prob. 53ECh. 7 - Prob. 54ECh. 7 - Prob. 55ECh. 7 - Prob. 56ECh. 7 - Prob. 57ECh. 7 - Prob. 58ECh. 7 - Prob. 59ECh. 7 - Prob. 60ECh. 7 - Prob. 61ECh. 7 - Prob. 62ECh. 7 - Prob. 63ECh. 7 - Prob. 64ECh. 7 - Prob. 65ECh. 7 - Prob. 66ECh. 7 - Prob. 67ECh. 7 - Prob. 68ECh. 7 - Prob. 69ECh. 7 - Prob. 70ECh. 7 - Prob. 71ECh. 7 - Prob. 72ECh. 7 - Prob. 73ECh. 7 - Prob. 74ECh. 7 - Prob. 75ECh. 7 - Prob. 76ECh. 7 - Prob. 77ECh. 7 - Prob. 78ECh. 7 - Prob. 79ECh. 7 - Prob. 80ECh. 7 - Prob. 81ECh. 7 - Prob. 82ECh. 7 - Prob. 83ECh. 7 - Prob. 84ECh. 7 - Prob. 85ECh. 7 - Prob. 86ECh. 7 - Prob. 87ECh. 7 - Prob. 88ECh. 7 - Prob. 1STCh. 7 - Prob. 2STCh. 7 - Prob. 3STCh. 7 - Prob. 4STCh. 7 - Prob. 5STCh. 7 - Prob. 6STCh. 7 - Prob. 7STCh. 7 - Prob. 8STCh. 7 - Prob. 9STCh. 7 - Prob. 10STCh. 7 - Prob. 11STCh. 7 - Prob. 12STCh. 7 - Prob. 13STCh. 7 - Prob. 14STCh. 7 - Prob. 15STCh. 7 - Prob. 16STCh. 7 - Prob. 17STCh. 7 - Prob. 18ST
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