Integrated Science
7th Edition
ISBN: 9780077862602
Author: Tillery, Bill W.
Publisher: Mcgraw-hill,
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Chapter 6.5, Problem 10SC
To determine
The reason for the permanent magnet to have magnetic properties.
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Integrated Science
Ch. 6.1 - Prob. 1SCCh. 6.1 - Prob. 2SCCh. 6.1 - Prob. 3SCCh. 6.2 - Compared to a thick wire, a thin wire of the same...Ch. 6.3 - Prob. 5SCCh. 6.3 - Prob. 6SCCh. 6.3 - Prob. 7SCCh. 6.3 - Prob. 8SCCh. 6.4 - If you multiply amps volts, the answer will be in...Ch. 6.5 - Prob. 10SC
Ch. 6.5 - Prob. 11SCCh. 6.5 - Prob. 12SCCh. 6 - Explain why a balloon that has been rubbed might...Ch. 6 - Prob. 2CQCh. 6 - Why does a positively or negatively charged object...Ch. 6 - Prob. 4CQCh. 6 - Prob. 5CQCh. 6 - Prob. 6CQCh. 6 - Prob. 7CQCh. 6 - How is an unmagnetized piece of iron different...Ch. 6 - Explain why the electric utility company increases...Ch. 6 - Describe how an electric generator is able to...Ch. 6 - Prob. 11CQCh. 6 - Explain what causes an electron to move toward one...Ch. 6 - Explain how the model of electricity as electrons...Ch. 6 - What are the significant similarities and...Ch. 6 - Prob. 15CQCh. 6 - Prob. 16CQCh. 6 - Analyze the apparent contradiction in the...Ch. 6 - Prob. 18CQCh. 6 - Prob. 1PEACh. 6 - Prob. 2PEACh. 6 - Prob. 3PEACh. 6 - What is the current in a 60.0 resistor when the...Ch. 6 - Prob. 5PEACh. 6 - Prob. 6PEACh. 6 - Prob. 7PEACh. 6 - Prob. 8PEACh. 6 - Prob. 9PEACh. 6 - Prob. 10PEACh. 6 - A power plant generator produces a 1,200 V, 40 A...Ch. 6 - Prob. 12PEACh. 6 - Prob. 1PEBCh. 6 - Prob. 2PEBCh. 6 - Prob. 3PEBCh. 6 - Prob. 4PEBCh. 6 - Prob. 5PEBCh. 6 - A lightbulb designed to operate in a 120.0 V...Ch. 6 - What is the monthly energy cost of leaving a 60 W...Ch. 6 - An electric motor draws a current of 11.5 A in a...Ch. 6 - A swimming pool requiring a 2.0 hp motor to filter...Ch. 6 - Prob. 10PEBCh. 6 - Prob. 11PEBCh. 6 - Prob. 12PEB
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- A charged particle is traveling through a uniform magnetic field. Which of the following statements are true of the magnetic field? There may be more than one correct statement. (a) It exerts a force on the particle parallel to the field. (b) It exerts a force on the particle along the direction of its motion. (c) It increases the kinetic energy of the particle. (d) It exerts a force that is perpendicular to the direction of motion. (e) It does not change the magnitude of the momentum of the particle.arrow_forwardIf a cosmic ray proton approaches the Earth from outer space along a line toward the center of the Earth that lies in the plane of the equator, in what direction will it be deflected by the Earth’s magnetic field? What about an electron? A neutron?arrow_forwardElectrons in Earths upper atmosphere have typical speeds near 6.00 105 m/s. (a) Calculate the magnitude of Earths magnetic field if an electrons velocity is perpendicular to the magnetic field and its circular path has a radius of 7.00 102 m. (b) Calculate the number of times per second that an electron circles around a magnetic field line.arrow_forward
- A proton and an alpha-particle have the same kinetic energy and both move in a plane perpendicular to a uniform magnetic field. Compare the pentodes of their orbits.arrow_forwardWhat creates a magnetic Hold? More than one answer may be correct, (a) a stationary object with electric charge (b) a moving object with electric charge (c) a stationary conductor carrying electric current (d) a difference in electric potential (e) a charged capacitor disconnected from a battery and at rest Note: In Chapter 34, we will see that a changing electric field also creates a magnetic field.arrow_forwardA proton of speed v=6105m/s enters a region of uniform magnetic field of B = 0.5 T at an angle of q = 30° to the magnetic field. In the region of magnetic field proton describes a helical path with radius R and pitch p (distance between loops.) Find R and p.arrow_forward
- A uniform horizontal wire with a linear mass density of 0.50 g/m carries a 2.0-A current. It is placed in a constant magnetic field with a strength of 4.0 103 T. The field is horizontal and perpendicular to the wire. As the wire moves upward starting from rest, (a) what is its acceleration and (b) how long does it take to rise 0.50 m? Neglect the magnetic field of Earth.arrow_forwardNeurons in our bodies carry weak currents that produce detectable magnetic fields. A technique called magnetoencephalography, or MEG, is used to study electrical activity in the brain using this concept This technique is capable of detecting magnetic fields as weak as 1.0 1015 T. Model the neuron as a long wire carrying a current and find the current it must carry to produce a field of this magnitude at a distance of 4.0 cm from the neuron.arrow_forwardA particle’s path is bent when it passes through a region of non-zero magnetic field although its speed remains unchanged. This is very useful for “beam steering’’ in particle accelerators. Consider a proton of speed 4106m/s entering a region of uniform magnetic field 0.2 T over a 5-cm-wide region. Magnetic field is perpendicular to the velocity of the particle. By how much angle will the path of the proton be bent? (Hint: the particle comes out tangent to a circle.arrow_forward
- The right-hand rule is a way to determine the direction of the magnetic field produced by moving charges. Imagine wrapping your right hand around the path of the charges so that the positive charges (or the current) flow from the little finger side of your fist to the thumb side (Figure 8.53). Then your fingers circle the path in the same direction as the magnetic field lines. Use this rule to verify the directions of the magnetic fields shown in Figures 8.8 and 8.10. How would you use the rule to find the direction of the magnetic field lines around a moving negative charge?arrow_forwardA wire carrying a 30.0-A current passes between the poles of a strong magnet that is perpendicular to its field and experiences a 2.16-N force on the 4.00 cm of wire in the field. What is the average field strength?arrow_forwardA 1.0-rn-long segment of wire lies along the x-axis and carries a current of 2.0 A in the positive x-direction. Around the sire Is the magnetic field of (3.0i4.0k)103T. Find the magnetic force on this segment.arrow_forward
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