Essentials of Business Analytics (MindTap Course List)
Essentials of Business Analytics (MindTap Course List)
2nd Edition
ISBN: 9781305627734
Author: Jeffrey D. Camm, James J. Cochran, Michael J. Fry, Jeffrey W. Ohlmann, David R. Anderson
Publisher: Cengage Learning
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Chapter 6, Problem 8P

a.

To determine

Obtain the sampling distribution of mean x¯ for itemized deductions for the population of taxpayers.

a.

Expert Solution
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Answer to Problem 8P

The sampling distribution of the mean x¯ for itemized deductions for the random sample of 30 taxpayers with adjusted gross income between $30,000 and $60,000 is normal with mean E(x¯)=16,642 and standard deviation σx¯=438.18.

The sampling distribution of the mean x¯ for itemized deductions for the random sample of 50 taxpayers with adjusted gross income between $30,000 and $60,000 is normal with mean E(x¯)=16,642 and standard deviation σx¯=339.41.

The sampling distribution of the mean x¯ for itemized deductions for the random sample of 100 taxpayers with adjusted gross income between $30,000 and $60,000 is normal with mean E(x¯)=16,642 and standard deviation σx¯=240.

The sampling distribution of the mean x¯ for itemized deductions for the random sample of 400 taxpayers with adjusted gross income between $30,000 and $60,000 is normal with mean E(x¯)=16,642 and standard deviation σx¯=120.

Explanation of Solution

It is given that 33% of taxpayers in the year 2010 with adjusted gross incomes between $30,000 and $60,000 itemized deductions on their federal income tax return. The mean amount of deductions for the given population of taxpayers is μ=16,642 and standard deviation is σ=2400.

The sampling distribution of the mean is approximately normal when the sample size is large regardless of the underlying distribution of the population from where it is taken.

The mean of the x¯ is E(x¯)=μ  and standard deviation of x¯ is σx¯=σn

In this context, x¯ is the mean amount of itemized deductions for the given population of taxpayers.

For the random sample of 30 taxpayers, the mean and standard deviation is calculated as,

E(x¯)=μ=16,642

σx¯=σn=240030=438.18

Thus, for the random sample of 30 taxpayers with adjusted gross income between $30,000 and $60,000, the sampling distribution of the mean x¯ for itemized deductions is normal with mean E(x¯)=16,642 and standard deviation σx¯=438.18.

For the random sample of 50 taxpayers, the mean and standard deviation is calculated as,

E(x¯)=μ=16,642

σx¯=σn=240050=339.41

Thus, for the random sample of 50 taxpayers with adjusted gross income between $30,000 and $60,000, the sampling distribution of the mean x¯ for itemized deductions is normal with mean E(x¯)=16,642 and standard deviation σx¯=339.41

For the random sample of 100 taxpayers, the mean and standard deviation is calculated as,

E(x¯)=μ=16,642

σx¯=σn=2400100=240

Thus, for the random sample of 100 taxpayers with adjusted gross income between $30,000 and $60,000, the sampling distribution of the mean x¯ for itemized deductions is normal with mean E(x¯)=16,642 and standard deviation σx¯=240

For the random sample of 400 taxpayers, the mean and standard deviation is calculated as,

E(x¯)=μ=16,642

σx¯=σn=2400400=120

Thus, for the random sample of 400 taxpayers with adjusted gross income between $30,000 and $60,000, the sampling distribution of the mean x¯ for itemized deductions is normal with mean E(x¯)=16,642 and standard deviation σx¯=120

b.

To determine

Explain the advantage of using larger sample size.

b.

Expert Solution
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Explanation of Solution

From part (a), it can be observed that when sample size increases the standard error of the sample mean decreases.

Thus, larger sample reduces the standard error which results in a more accurate estimate of the population mean.

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Chapter 6 Solutions

Essentials of Business Analytics (MindTap Course List)

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