Database Concepts (7th Edition)
7th Edition
ISBN: 9780133544626
Author: David M. Kroenke, David J. Auer
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Expert Solution & Answer
Chapter 5, Problem 5.13RQ
Explanation of Solution
Join in SQL:
In DBMS (
- The join clause creates a set that can be saved as a table.
SQL code for joining two tables:
SELECT * FROM HOD P JOIN Department T ON P.HOD_ID = T.HOD_ID;
Explanation:
- The above query is used to join all the data of “HOD” table and “Department” table in question 5...
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Write SQL code for
To Extend the code in ( Perform a LEFT OUTER JOIN between the tables Wicketkeeping and Batting. You may select any column(s). Look at the result and state how many wicketkeepers have not played as batsmen (no need to write code for this part) To show the name of the wicketkeeper(s) who have not played as a batsman. (syntax to check a NULL value in a column is: WHERE ColumnName IS NULL ) ?
Write an SQL query that will show all data from the Customers table andOrder By State.
PLz help with the following
Please implement the following using Oracle live/SQL Developer:
1- Create the DONORS table with the following columns: donor_id ( PRIMARY KEY), donor_name (Not Null), donor_age. Then Create DONATIONS table with the following columns: pledge_id (PRIMARY KEY), pledge_date, amount_pledged, amount_paid, Is_paid, donor_id that REFERENCES to DONORS table (donor_id).
2- Populate every relation with three rows.
3- Now, your supervisor has asked you to modify the donor_age column in the DONORS table. He wants the column to be configured to accept a value that must be >=20. Which statement should you issue to accomplish this task?
4- Create a Trigger to update Is_paid column to 1 when the amount_paid equal to amount_pledged.
Chapter 5 Solutions
Database Concepts (7th Edition)
Ch. 5 - Explain how entities are transformed into tables.Ch. 5 - Prob. 5.2RQCh. 5 - Prob. 5.3RQCh. 5 - What is denormalization?Ch. 5 - Prob. 5.5RQCh. 5 - Explain the problems that denormalized tables may...Ch. 5 - Explain how the representation of weak entities...Ch. 5 - Explain how supertype and subtype entities are...Ch. 5 - Prob. 5.9RQCh. 5 - Prob. 5.10RQ
Ch. 5 - Show two different ways to represent the 1:1...Ch. 5 - Prob. 5.12RQCh. 5 - Prob. 5.13RQCh. 5 - Prob. 5.14RQCh. 5 - Prob. 5.15RQCh. 5 - Prob. 5.16RQCh. 5 - For your answer to question 5.15, code an SQL...Ch. 5 - Prob. 5.18RQCh. 5 - Prob. 5.20RQCh. 5 - Prob. 5.21RQCh. 5 - Explain how the terms parent table and child table...Ch. 5 - For your answers to questions 5.20, 5.21, and...Ch. 5 - Prob. 5.24RQCh. 5 - Prob. 5.25RQCh. 5 - Prob. 5.26RQCh. 5 - Prob. 5.27RQCh. 5 - Prob. 5.28RQCh. 5 - Define the three types of recursive binary...Ch. 5 - Prob. 5.30RQCh. 5 - Prob. 5.31RQCh. 5 - Prob. 5.32RQCh. 5 - Prob. 5.33RQCh. 5 - Prob. 5.34RQCh. 5 - Code an SQL statement that creates a table with...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.Similar questions
- in pl/sql ,use Cursor to get all the records from table job_history for employee_id 121arrow_forwardWrite SQL queries DDL Queries to implement the following Relational Model i.e. create the Nurse and Care_Center relations (including primary key and foreign key). Intelligently write data types.arrow_forwardBuild the Students Table that is shown in the picture using python SQL hint: The SQL command to build the table is create table student( SID int primary key not null, Name varchar(20), GPA char(3), Major varchar(25))arrow_forward
- #below is the SQL Script: You can copy and paste to run create database pharmacy; use pharmacy; create table branch (id int (3) not null auto_increment primary key, name varchar (50) not null); create table transaction_type (id int (1) not null auto_increment primary key, type varchar (15) not null); create table network (id int (2) not null auto_increment primary key, name varchar (30) not null) ; create table worker (id int (3) zerofill not null auto_increment primary key, fname varchar (30) not null, Iname varchar (30) not null, contact varchar (13) not null); create table worker_branch (worker_id int (3) not null references worker (id), branch_id int (3) not null references branch (id), primary key (worker_id,branch_id)); create table transaction (id int not null auto increment primary key, worker id int (3) not null references worker (id), branch_id int (3) not null, customer_no varchar (13) not null, customer_id int (25)); You have been tasked to use the SQL script provided above…arrow_forwardWrite the SQL code that will produce the same information that was shown in Problem 2, but sorted by the employee’s last name. The results of running that query are shown in Figure P7.3.arrow_forwardWrite and execute a SQL query to list all patient numbers and encounter ids which do not have any data (missing rows) in VisitSummary table. Order the result by patient number, encounter id. Write and execute a SQL query to list all patients whose information about race or gender has changed during their future visits. A future visit is defined as T1.encounter_id < T2.encounter_id. Your output should have patient number, old and new race values, old and new gender values, and the encounter ids. Write and execute a SQL query to list all the patient data for all encounters. Even if patient data is missing in other tables, you still need to list the patient_nbr and encounter_id in your output. Your output should list all the columns (without repeating them) starting with encounter_id, patient_nbr... and it should be ordered by patient_nbr and then encounter_id. Write and execute a SQL query to list all the patient data for all encounters. If the patient data is missing…arrow_forward
- Write a SQL query using their schema to find out who hasn't taken a course at the university. There should be no subqueries or set actions (use an outer join).arrow_forwardwrite SQL queries to create procedures for a database called Saleco. The database contains the following tables: customer, invoice, line, product, and vendor. A procedure called get_customer_invoices that takes a customer ID as input and returns a list of all invoices for that customer, along with the total amount due for each invoice. A procedure called get_vendor_products that takes a vendor ID as input and returns a list of all products sold by that vendor, along with the number of units sold and the total revenue generated for each product. A procedure called get_invoice_details that takes an invoice ID as input and returns a list of all products purchased on that invoice, along with the quantity purchased, the unit price, and the total price for each product.arrow_forwardUse FOR loop for your cursor. Write a PL/SQL block to read and display the job_id and number of employees per job_id. Accept input from the user to get the number of employees he wants to see in the output. Display also the number of records returned by your PL/SQL block.arrow_forward
- My SQL WORKBENCH **Please note that you may actually use as many tables as you need. You are not limited to use only twotables.Example:SELECT *FROM DEPARTMENTS;SELECT *FROM EMPLOYEES;Now join departments and employees tables.SELECT FIRST_NAME, DEPARTMENT_NAMEFROM EMPLOYEES, DEPARTMENTSWHERE EMPLOYEES.DEPARTMENT_ID = DEPARTMENTS.DEPARTMENT_ID;NOTE: If you omit the join condition, the result will be the Cartesian Product of the two tables. A CartesianProduct joins all rows of the first table with all rows of the second table.That is if the first table has n rows and the second table has m rows, the output will have n*m rows.The following query will produce a Cartesian Product:SELECT FIRST_NAME, DEPARTMENT_NAMEFROM EMPLOYEES, DEPARTMENTS;**When table names are long, qualifying column names might be very time consuming. Usually peopleprefer to use table aliases for this purpose.Example: List the name of all employees who work for 'Purchasing' departmentSELECT E.FIRST_NAME "EMPLOYEE…arrow_forwardYou are working with a database table that contains customer data. The table includes columns about customer location such as city, state, country, and postal_code. You want to check for postal codes that are greater than 7 characters long. You write the SQL query below. Add a LENGTH function that will return any postal codes that are greater than 7 characters long.arrow_forwardMy SQL WORKBENCH **Please note that you may actually use as many tables as you need. You are not limited to use only twotables.Example:SELECT *FROM DEPARTMENTS;SELECT *FROM EMPLOYEES;Now join departments and employees tables.SELECT FIRST_NAME, DEPARTMENT_NAMEFROM EMPLOYEES, DEPARTMENTSWHERE EMPLOYEES.DEPARTMENT_ID = DEPARTMENTS.DEPARTMENT_ID;NOTE: If you omit the join condition, the result will be the Cartesian Product of the two tables. A CartesianProduct joins all rows of the first table with all rows of the second table.That is if the first table has n rows and the second table has m rows, the output will have n*m rows.The following query will produce a Cartesian Product:SELECT FIRST_NAME, DEPARTMENT_NAMEFROM EMPLOYEES, DEPARTMENTS;**When table names are long, qualifying column names might be very time consuming. Usually peopleprefer to use table aliases for this purpose.Example: List the name of all employees who work for 'Purchasing' departmentSELECT E.FIRST_NAME "EMPLOYEE…arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
A Guide to SQLComputer ScienceISBN:9781111527273Author:Philip J. PrattPublisher:Course Technology Ptr
A Guide to SQL
Computer Science
ISBN:9781111527273
Author:Philip J. Pratt
Publisher:Course Technology Ptr