Astronomy
1st Edition
ISBN: 9781938168284
Author: Andrew Fraknoi; David Morrison; Sidney C. Wolff
Publisher: OpenStax
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Chapter 5, Problem 45E
If the emitted infrared
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The next four questions use this description.
Our Sun has a peak emission wavelength of about 500 nm and a radius of about 700,000 km. Your dark-adapted eye has a pupil diameter of about 7 mm and can detect light intensity down to about 1.5 x 10-11 W/m2. Assume the emissivity of the Sun is equal to 1.
First, given these numbers, what is the surface temperature of the Sun in Kelvin to 3 significant digits?
What is the power output of the Sun in moles of watts? (in other words, take the number of watts and divide it by Avogadro's number)
Assuming that all of the Sun's power is given off as 500 nm photons*, how many photons are given off by the Sun every second? Report your answer to the nearest power of 10 (e.g. if you got 7 x 1024, give your answer as 25).
How is the distance from the sun for planets in our
solar system related to the mean temperature of
each planet? To find out, a scatterplot that relates the
natural log of the distance of each planet (including
Pluto) from the sun in millions of miles and the
natural log of the mean planetary temperature in
Kelvin was created.
In(Temperature) vs. In(Distance)
6.8
6.6
6.4
6.2
6
5.8
5.6
5.4
5.2
4.8
4.6
4.4
4.2
4
4
6 7
8.
In(Distance)
Predictor
Coef
7.9009
SE Coef
P
Conatant
0.4381
18.03
0.000
In Distance
-0.4536
0.0706
-6.42
0.004
s = 0.3446
R-Sq = 85.5
R-8q (adj) = 83.2%
Based on the scatterplot and computer output, a
reasonable estimate of mean temperature in Kelvin
for Saturn, which is 886.7 million miles away from
the sun is:
O 4.822 degrees Kelvin because ý = -0.4536(In
886.7) + 7.9009 = 4.822.
O 124.2 degrees Kelvin because
in y = -0,4536(in 886,7) + 7.9009 =4,822
and e4.822 = 124.2.
O 709.0 degrees Kelvin because
In y = - 0.4536(log 886.7) + 7.9009 =6.564
and e6.564 = 709.0.
O…
Di O 11:PA
(1) Suppose a person is covered head to
foot by wool clothing with average thickness
of 2 cm and is transferring energy of 6000
joules by conduction through the clothing for
2 minutes. What is the temperature
difference across the clothing, given the
surface area is 1.4m?? (Given: Thermal
conductivity of wool is 0.04 W/mK)
The difference in
temperature =
(2) A 9.15 kg sample of water at 11°C is in a
calorimeter. You drop a piece of iron with a
mass of 0.41 kg at 260°C into it. After the
sizzling subsides, what is the final
equilibrium temperature? (Given: Sp. Heat
of water 1cal/g°C & Sp. Heat of iron is 0.106
cal/g°C)
Equilibrium temperature in
celcius =
Chapter 5 Solutions
Astronomy
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