Explanation Given: The current changes from 0.1 mA to 10 mA . Concept used: The change in diode voltage if a change in current occurs is, V 2 − V 1 = V T ln I 2 I 1 ....... (1) Here, V 1 and V 2 are voltages, I 1 and I 2 are the currents and V T is the thermal voltage. Calculation: The value of thermal voltage V T at room temperature is approximately 26 mV . Substitute 10 for I 2 , 0.1 for I 1 and 26 for V T in equation (1) as, V 2 − V 1 = 26 ln 10 0

Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition

7th Edition

ISBN: 9780199339136

Author: Adel S. Sedra, Kenneth C. Smith

Publisher: Oxford University Press

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Chapter 4.2, Problem 4.6E

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The change in diode voltage.

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Chapter 4.1, Problem 4.5E

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Chapter 4 Solutions

Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition

Ch. 4.1 - Prob. 4.1E Ch. 4.1 - Prob. 4.2E Ch. 4.1 - Prob. 4.3E Ch. 4.1 - Prob. 4.4E Ch. 4.1 - Prob. 4.5E Ch. 4.2 - Prob. 4.6E Ch. 4.2 - Prob. 4.7E Ch. 4.2 - Prob. 4.8E Ch. 4.2 - Prob. 4.9E Ch. 4.3 - Prob. 4.10E

Ch. 4.3 - Prob. D4.11E Ch. 4.3 - Prob. 4.12E Ch. 4.3 - Prob. 4.13E Ch. 4.3 - Prob. 4.14E Ch. 4.3 - Prob. D4.15E Ch. 4.4 - Prob. 4.16E Ch. 4.4 - Prob. 4.17E Ch. 4.4 - Prob. 4.18E Ch. 4.5 - Prob. 4.19E Ch. 4.5 - Prob. 4.20E Ch. 4.5 - Prob. 4.21E Ch. 4.5 - Prob. 4.22E Ch. 4.5 - Prob. 4.23E Ch. 4.5 - Prob. 4.24E Ch. 4.5 - Prob. 4.25E Ch. 4.6 - Prob. 4.26E Ch. 4.6 - Prob. 4.27E Ch. 4 - Prob. 4.1P Ch. 4 - Prob. 4.2P Ch. 4 - Prob. 4.3P Ch. 4 - Prob. 4.4P Ch. 4 - Prob. 4.5P Ch. 4 - Prob. 4.6P Ch. 4 - Prob. D4.7P Ch. 4 - Prob. D4.8P Ch. 4 - Prob. 4.9P Ch. 4 - Prob. 4.10P Ch. 4 - Prob. D4.11P Ch. 4 - Prob. 4.12P Ch. 4 - Prob. 4.13P Ch. 4 - Prob. 4.14P Ch. 4 - Prob. D4.15P Ch. 4 - Prob. 4.16P Ch. 4 - Prob. 4.17P Ch. 4 - Prob. 4.18P Ch. 4 - Prob. 4.19P Ch. 4 - Prob. 4.20P Ch. 4 - Prob. 4.21P Ch. 4 - Prob. 4.22P Ch. 4 - Prob. 4.23P Ch. 4 - Prob. 4.24P Ch. 4 - Prob. 4.25P Ch. 4 - Prob. 4.26P Ch. 4 - Prob. 4.27P Ch. 4 - Prob. 4.28P Ch. 4 - Prob. 4.29P Ch. 4 - Prob. 4.30P Ch. 4 - Prob. 4.31P Ch. 4 - Prob. 4.32P Ch. 4 - Prob. 4.33P Ch. 4 - Prob. 4.34P Ch. 4 - Prob. 4.35P Ch. 4 - Prob. 4.36P Ch. 4 - Prob. D4.37P Ch. 4 - Prob. 4.38P Ch. 4 - Prob. 4.39P Ch. 4 - Prob. 4.40P Ch. 4 - Prob. 4.41P Ch. 4 - Prob. 4.42P Ch. 4 - Prob. 4.43P Ch. 4 - Prob. 4.44P Ch. 4 - Prob. D4.45P Ch. 4 - Prob. 4.46P Ch. 4 - Prob. 4.47P Ch. 4 - Prob. 4.48P Ch. 4 - Prob. 4.49P Ch. 4 - Prob. 4.50P Ch. 4 - Prob. 4.51P Ch. 4 - Prob. 4.52P Ch. 4 - Prob. 4.53P Ch. 4 - Prob. 4.54P Ch. 4 - Prob. 4.55P Ch. 4 - Prob. D4.56P Ch. 4 - Prob. D4.57P Ch. 4 - Prob. 4.58P Ch. 4 - Prob. 4.59P Ch. 4 - Prob. D4.60P Ch. 4 - Prob. 4.61P Ch. 4 - Prob. 4.62P Ch. 4 - Prob. D4.63P Ch. 4 - Prob. D4.64P Ch. 4 - Prob. D4.65P Ch. 4 - Prob. D4.66P Ch. 4 - Prob. 4.67P Ch. 4 - Prob. 4.68P Ch. 4 - Prob. 4.69P Ch. 4 - Prob. 4.70P Ch. 4 - Prob. 4.71P Ch. 4 - Prob. 4.72P Ch. 4 - Prob. D4.73P Ch. 4 - Prob. D4.74P Ch. 4 - Prob. D4.75P Ch. 4 - Prob. 4.76P Ch. 4 - Prob. 4.77P Ch. 4 - Prob. 4.78P Ch. 4 - Prob. 4.79P Ch. 4 - Prob. D4.80P Ch. 4 - Prob. D4.81P Ch. 4 - Prob. D4.82P Ch. 4 - Prob. D4.83P Ch. 4 - Prob. D4.84P Ch. 4 - Prob. 4.85P Ch. 4 - Prob. 4.86P Ch. 4 - Prob. 4.87P Ch. 4 - Prob. 4.88P Ch. 4 - Prob. 4.89P Ch. 4 - Prob. 4.90P Ch. 4 - Prob. 4.91P Ch. 4 - Prob. 4.92P Ch. 4 - Prob. 4.93P Ch. 4 - Prob. 4.94P Ch. 4 - Prob. 4.95P Ch. 4 - Prob. 4.96P Ch. 4 - Prob. 4.97P

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The change in diode voltage.

Solution Summary: The author explains the change in diode voltage, which is 120mV.

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