(a)
A
Answer to Problem 4.6.9P
Explanation of Solution
Given information:
Calculation:
Assume
Try the web size
Effective slenderness ratio is given by
Check for slenderness ratio
Nominal compressive strength is given by
Check for web buckling from dimensions and properties table in the manual the width thickness ratio of the web is given by
From the AISC section we have the equation
Since
Local buckling should be checked
Width of the web is given by
Effective width is given by
Calculate effective area
Critical stress is given by
Calculate the critical buckling stress as below
Calculate nominal compressive strength of column
Try the web size
Effective slenderness ratio is given by
Calculate buckling stress
Calculate nominal compressive strength of column
Check for web buckling from dimensions and properties table in the manual the width thickness ratio of the web is given by
From the AISC section we have the equation
Since
Local buckling should be checked
Width of the web is given by
Effective width is given by
Calculate effective area
Critical stress is given by,
Calculate the critical buckling stress as below
Calculate nominal compressive strength of column
Try the web size
Conclusion:
Therefore, size
(b)
Select a
Answer to Problem 4.6.9P
Explanation of Solution
Given information:
Calculation:
Assume
Try the web size
Effective slenderness ratio is given by
Check for slenderness ratio
Check for web buckling from dimensions and properties table in the manual the width thickness ratio of the web is given by
From the AISC section we have the equation
Since,
Local buckling should be checked
Width of the web is given by
Effective width is given by
Calculate effective area
Critical stress is given by
Calculate the critical buckling stress as below
Calculate nominal compressive strength of column
Conclusion:
Therefore, size
Want to see more full solutions like this?
Chapter 4 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
- The beam shown in Figure has lateral support only at the ends. The uniform load is a superimposed dead load, and the concentrated load is a live load. Use A992 steel and select a W shape. The live load deflection must not exceed L/360. a. Use LRFD.b. Use ASD.arrow_forwardFor the conditions shown in Figure 3, use LRFD and (a) Select a W18 of A992 steel. (b) Select a steel pipe. (c) Select a square HSS. (d) Select a rectangular HSS. 15' - 4" D = 100 k L = 300 k Figure 3arrow_forwardFor the conditions shown in Figure , use LRFD and a. select a W16 of A992 steel. b. select a steel pipe. c. select a square HSS. d. select a rectangular HSSarrow_forward
- Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage Learning