Structural Steel Design (6th Edition)
6th Edition
ISBN: 9780134589657
Author: Jack C. McCormac, Stephen F. Csernak
Publisher: PEARSON
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Chapter 4, Problem 4.2PFS
To determine
The lightest section of
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Instructions:-Write down each step clearly in calculation suggestion what you are doing.( you need to tell why you selected particular value ofø (phi) and U). What and why you are calculating certain step
Consider R= 433.5
PROBLEM
A welded tension member is consisting of two channels placed 400mm back to back with flanges turned out. Select a channel for factored tensile of 4RKN using A36 steel and AISC specifications.The member is to be 15m long.
PLASE USE THE EXAMPLE AS GUIDE OF ALL STEPS AND FORMULAS TO BE USE
SOLVE FOR THE FORCE IN MEMBERS AB, AC, BC, CD, BD, BE, DE, DF & EF. SHOW SOLUTIONS CLEARLY
USING METHOD OF JOINTS AND WRITE WELL ALSO SEE LINK UNDER WEEK7
0.8m
2.4m
-6KN
MEMBER
AB
AC
BC
CD
BD
BE
2m
ED
DF
EF
1m
8KN
Av REACTION hinge)
EX REACTION @roller)
3m
SUMMARY OF RESULTS
FORCE
1m
10KN
2.4m
3KN
NATURE(I or C)
W3D 25
Y= 155
%31
1oow= 2500 KN
27=310mm
X= 475
Z= 60
%3D
102=600mm
Chapter 4 Solutions
Structural Steel Design (6th Edition)
Ch. 4 - Prob. 4.1PFSCh. 4 - Prob. 4.2PFSCh. 4 - Prob. 4.3PFSCh. 4 - Prob. 4.4PFSCh. 4 - Prob. 4.5PFSCh. 4 - Prob. 4.6PFSCh. 4 - Prob. 4.7PFSCh. 4 - Prob. 4.8PFSCh. 4 - Prob. 4.9PFSCh. 4 - Prob. 4.10PFS
Ch. 4 - Prob. 4.11PFSCh. 4 - Prob. 4.12PFSCh. 4 - Prob. 4.13PFSCh. 4 - Prob. 4.14PFSCh. 4 - Prob. 4.15PFSCh. 4 - Prob. 4.16PFSCh. 4 - Prob. 4.17PFSCh. 4 - Prob. 4.18PFSCh. 4 - Prob. 4.19PFSCh. 4 - Prob. 4.20PFSCh. 4 - Prob. 4.21PFSCh. 4 - Prob. 4.22PFSCh. 4 - Prob. 4.23PFSCh. 4 - Prob. 4.24PFSCh. 4 - Prob. 4.25PFSCh. 4 - Prob. 4.26PFS
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- 5 A flanged bolt coupling has ten 12-mm di ameter steel bolts on 500 mm diameter b olt circle and six 16 mm diameter aluminu m bolts on 300 mm diameter bolt circle. Determine the maximum torque that can be applied without exceeding the shear s tress of 60 MPa in steel or 40 MPa in alu minum. Use G = 80 GPa for steel and 30 GPa for aluminum. Drawing not included in this problem.(arrow_forward2. A vertical member of a steel truss is subjected to a live load of 25 kN and a service dead load of 50 KN. The flat bar is welded to the guzzette plate with sufficient weld length such that the reduction factor "U" is equal to 1.0. Determine if a 10mm x 100mm plate is safe to carry the load. Given: Ag = 1000 sq mm width = 100mm thickness = 10 mm U = 1.0arrow_forwardANALY 2 THE STATICALLY METHOD DRAW SHEAP AND BENDING MOMENT INDETERMINATE BEAM SHOWN BY TA E DIAGRAM A @= 10tt W=2k/# ~! P=30k ↓ L=18pt b=8ft SLOPE DEFLECTIONarrow_forward
- A W14X120 is used as a tension member in atruss. The flanges of the member are connected to a gusset plate by ¾ inch boltas shown below. Use A36 steel with Fy=36 ksi and Fu=58 ksi A. Determine the Yielding Capacity of the section based on LRFD (kips) Round your answer to 2 decimal places. c. Determine the Tensile Rupture capacity of the section based on LRFD need answer pleasearrow_forwardThe lap joint shown is fastened by 6 – 20mm diameter rivets. Assuming that P = 200KN, determine (a) the shearing stress in each rivet, (b) the bearing stress in each plate 25mm thick and 100mm wide. Assume thatarrow_forwardProblem 2 Given is a truss structure: Where: • Working shear stress for the rivets is 70 MPa • Working bearing stress due to rivets is 140 Mpa • Thickness of the member is 5 mm • Thickness of the Gusset plate is 6 mm Rivet diameter is 15 mm Determine the no. of rivets to fasten the member BD 80 N 120 N 200 N 4 Pands 4m - 16 marrow_forward
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