Concept explainers
Two converging lenses having focal lengths of f1 = 10.0 cm and f2 = 20.0 cm are placed a distance d = 50.0 cm apart as shown in Figure P35.48. The image due to light passing through both lenses is to be located between the lenses at the position x = 31.0 cm indicated. (a) At what value of p should the object be positioned to the left of the first lens? (b) What is the magnification of the final image? (c) Is the final image upright or inverted? (d) Is the final image real or virtual?
(a)
Answer to Problem 36.78AP
Explanation of Solution
Given info: The focal length of first lens
Write the expression for the final image distance
Here,
Substitute
Write the expression for the thin lens equation.
Here,
Substitute
The image distance to the first lens
Here,
Substitute
Formula to calculate the thin lens equation is,
Here,
Substitute
Conclusion:
Therefore, the value of
(b)
Answer to Problem 36.78AP
Explanation of Solution
Given info: The focal length of first lens
Write the equation for magnification of the first lens.
Write the equation for magnification of the second lens.
Write the equation for magnification of the final image.
Substitute
Substitute
Conclusion:
Therefore, the magnification of the final image is
(c)
Answer to Problem 36.78AP
Explanation of Solution
Given info: The focal length of first lens is
Here, the value of magnification of the final image is
If the magnification is found to be negative
Thus, the image formed is an inverted image.
Conclusion:
Therefore, the final image is inverted.
(d)
Answer to Problem 36.78AP
Explanation of Solution
Given info: The focal length of first lens is
Here, the value of final image distance is
If the value of final image is found to be negative
Thus, the image formed is a virtual image.
Conclusion:
Therefore, the final image is virtual.
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Chapter 36 Solutions
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
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