Traffic and Highway Engineering
5th Edition
ISBN: 9781305156241
Author: Garber, Nicholas J.
Publisher: Cengage Learning
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Chapter 3, Problem 11P
To determine
The maximum acceleration of the vehicle.
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The driver of the vehicle on a level road determined that she could increase her speed from rest to 51 kph in 36.80 seconds and from rest to 66 kph in 96.80 seconds. If it can be assumed that the acceleration of the vehicle takes the form:du/dt = α - βutwhere u is the vehicle speed in m/sec. Determine the maximum acceleration of the vehicle
The driver of the vehicle on a level road determined that she could increase her speed from rest to 51 kph in 36.80 seconds and from rest to 66 kph in 96.80 seconds. If it can be assumed that the acceleration of the vehicle takes the form du/dt = - βut
where u is the vehicle speed in m/sec. Determine the maximum acceleration of the vehicle.
In traveling a distance of 2.0 km between points A and D, a car is driven at 106 km/h from A to B for t seconds and 47 km/h from C to D also for t seconds. If the brakes are applied for 3.7 seconds between B and C to give the car a uniform deceleration, calculate t and the distance s between A and B.
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Traffic and Highway Engineering
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- A car is travelling along a straight horizontal road with a constant acceleration of 0.75 m/3. The car is travelling at 8 m/s when it passes a pillar box. 12 seconds later it passes a lamp post. Find a the distance between the pillar box and the lamp post, b the speed with which the car passes the lamp post.arrow_forwardTwo automobiles A and B shown below are approaching each other in adjacent highway lanes. At t = 0, A and B are 1km apart, their speeds are vA = 25 km/h and vB = 20 km/h, and they are at points P and Q, respectively. Knowing that A passes point Q 42 s after B was there and that B passes point P 40 s after A was there, determine (a) the uniform accelerations of A and B, (b) when the vehicles pass each other, (c) the speed of B at that time. DA = 25 km/h Ug = 20 km/h B 1 kmarrow_forwardIn traveling a distance of 2.3 km between points A and D, a car is driven at 91 km/h from A to B for t seconds and 43 km/h from C to D also for t seconds. If the brakes are applied for 3.7 seconds between B and C to give the car a uniform deceleration, calculate t and the distances between A and B. Answers: t= S= 91 km/h i B 2.3 km 43 km/h S km Darrow_forward
- A car is moving at a speed of 72 km/hr on road having 2% upward gradient. The driver applies brakes when he sees an obstruction. If his reaciton time is 1.5 seconds, assuming that the co-efficient of friction between the pavement and tyre as 0.15, calculate the distance traversed before the car finally stops.arrow_forwardThe acceleration of a vehicle takes the form: du/dt = 1.1 0.03u where u is the vehicle speed in m/s. The vehicle is traveling at 14m/s at time To Determine the following: 2.1. Time at which the vehicle attains a speed of 26 m/s 2.2. Acceleration of the vehicle after 3 seconds 2.3. Distance travelled by the vehicle when accelerated to a speed of 26 m/sarrow_forwardThe gap between two consecutive automobiles (distance between the back of a vehicle and the front of the following vehicle) is 65 . At a certain time, the front vehicle is traveling at 45 mi/h, and the following vehicle at 35 mi/h. If both vehicles start accelerating at the same time, determine the gap between the two vehicles after 15 sec., if the acceleration of the vehicles can be assumed as follows, where u, in the equation is vehicle speed in ft /sec. du 3.4-0.07u, (leading vehicle) dt du 3.3-0.065 dt = (following vehicle) ₂ 2arrow_forward
- In traveling a distance of 2.3 km between points A and D, a car is driven at 91 km/h from A to B for t seconds and 43 km/h from C to D also for t seconds. If the brakes are applied for 3.7 seconds between B and C to give the car a uniform deceleration, calculate t and the distances between A and B. Answers: t = 91 km/h S= 59.94 i 2300 B T C 2.3 km 43 km/h S kmarrow_forwardAn driver (t₁=1 sec) used brakes to avoid an accident when suddenly a person steps from behind parked car in the path of driver at distance 35m. can the drivers avoids the accident if he drive at velocity of: 45 km/hr, 55km/hr, 65 km/hr, 75 km/hr? (F= 0.45).arrow_forwardA car starts from rest, and accelerates at a uniform rate to a velocity of 40 m/s in 15 secs. If the car is moving in a circular track with a diameter equal to 1.5 mi, and assuming constant tangential acceleration, 1. Determine the car's tangential acceleration at the instant when the velocity is 40 m/s. 2. Determine the car's normal acceleration at the instant when the velocity is 40 m/s. 1 3. What was the car's acceleration?arrow_forward
- During a braking test, a car is brought to rest beginning from an initial speed of 54 mi/hr in a distance of 143 ft. With the same constant deceleration, what would be the stopping distance s from an initial speed of 83 mi/hr? Answer:s = i ftarrow_forwardAn impatient car driver stuck behind a slow-moving truck traveling at 25 mi/h decides to overtake the truck. The accelerating characteristic of the car is given by: dv/dt=3-0.05v where v is the speed (ft/sec) and t is the time (0sec).What is the acceleration in meter per second after 25 seconds?arrow_forwardA car is traveling around a circular track of 660-ft radius. If the magnitude of its total acceleration is 6.2 ft/sec² at the instant when its speed is 32 mi/hr, determine the rate at at which the car is changing its speed. Answer: at = ± ft/sec²arrow_forward
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