General Physics, 2nd Edition
General Physics, 2nd Edition
2nd Edition
ISBN: 9780471522782
Author: Morton M. Sternheim
Publisher: WILEY
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Chapter 24, Problem 1RQ
To determine

The image distance for a plane mirror.

Expert Solution & Answer
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Answer to Problem 1RQ

The image distance for a plane mirror is equals the object distance.

Explanation of Solution

General Physics, 2nd Edition, Chapter 24, Problem 1RQ

The ray incident along normally to the mirror gets reflected directly back along the normal. So it appears to have originated behind the mirror on the normal. The light ray that strikes the mirror at an angle ϕ to the normal is reflected at an equal angle and appears to come from somewhere behind the mirror along the dashed projection of the outgoing ray.

The two projected paths cross behind the mirror at point t, the image position. The two right triangles have a common side x and an equal angle ϕ. Hence the triangles are congruent. and all their angles and sides are equal. This means that the object distance d and the image distance d are the same.

Conclusion:

Therefore, the image distance for a plane mirror is equals the object distance.

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The mirror equation relates the object distance, d0, the image distance, di, and the focal length, f, of a mirror as1 / d0 + 1 / di = 1 / fWhile in other topics, distance and length are strictly non-negative, in optics we introduce the following sign conventions: Object distance is positive for a real object and negative for a virtual object. Image distance is positive for a real image and negative for a virtual image. Focal length is positive for a converging mirror and negative for a diverging mirror (a) Select the best choice to complete this statement. A real object placed in front of a converging mirror creates a real image  under all circumstances. under no circumstances. when the object is between the focal point and the mirror. when the object is farther than the focal length from the mirror. (b) Select the best choice to complete this statement. A real object placed in front of a diverging mirror creates a virtual image  under all circumstances. under no circumstances.…

Chapter 24 Solutions

General Physics, 2nd Edition

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