Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
9th Edition
ISBN: 9781133949640
Author: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher: Cengage Learning
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Chapter 22, Problem 1PS

(a)

Interpretation Introduction

Interpretation:

The electronic configuration of Cr3+ ion and the magnetic property of the ion have to be identified.

Concept introduction:

The electron configuration tells us in which orbitals the electrons for an element are located. Three rules are,

  • Electrons fill orbitals staring with lowest n and moving upwards(Aufbau principle)
  • No two electrons can fill one orbital with the same spin(Pauli Exclusion Principle)
  • For orbitals within the same subshell, the electrons fill each orbital singly before any orbital gets a second electron (Hund’s rule).

Para magnetism refers to the magnetic state of an atom with one or more unpaired electrons.

Diamagnetism has no unpaired electrons (electrons are paired).

(a)

Expert Solution
Check Mark

Answer to Problem 1PS

The electronic configuration of Cr3+ is 1s22s22p63s23p63d34s0 and Cr3+ is paramagnetic in nature.

Explanation of Solution

The electronic configuration of chromium is 1s22s22p63s23p63d54s1. The electronic configuration of Cr3+ is 1s22s22p63s23p63d34s0. Therefore there are three unpaired electrons are there so the Cr3+ is paramagnetic in nature.

(b)

Interpretation Introduction

Interpretation:

The electronic configuration of V2+ ion and the magnetic property of the ion has to be identified.

Concept introduction:

The electron configuration tells us in which orbitals the electrons for an element are located. Three rules are,

  • Electrons fill orbitals staring with lowest n and moving upwards(Aufbau principle)
  • No two electrons can fill one orbital with the same spin(Pauli Exclusion Principle)
  • For orbitals within the same subshell, the electrons fill each orbital singly before any orbital gets a second electron (Hund’s rule).

Para magnetism refers to the magnetic state of an atom with one or more unpaired electrons.

Diamagnetism has no unpaired electrons (electrons are paired).

(b)

Expert Solution
Check Mark

Answer to Problem 1PS

The electronic configuration of V2+ is 1s22s22p63s23p63d34s0 and V2+ is paramagnetic in nature.

Explanation of Solution

The electronic configuration of vanadium is 1s22s22p63s23p63d34s2. The electronic configuration of V2+ is 1s22s22p63s23p63d34s0. Therefore there are three unpaired electrons are there so the V2+ is paramagnetic in nature.

(c)

Interpretation Introduction

Interpretation:

The electronic configuration of Ni2+ ion and the magnetic property of the ion has be identified.

Concept introduction:

The electron configuration tells us in which orbitals the electrons for an element are located. Three rules are,

  • Electrons fill orbitals staring with lowest n and moving upwards(Aufbau principle)
  • No two electrons can fill one orbital with the same spin(Pauli Exclusion Principle)
  • For orbitals within the same subshell, the electrons fill each orbital singly before any orbital gets a second electron (Hund’s rule).

Para magnetism refers to the magnetic state of an atom with one or more unpaired electrons.

Diamagnetism has no unpaired electrons (electrons are paired).

(c)

Expert Solution
Check Mark

Answer to Problem 1PS

The electronic configuration of Ni2+ is 1s22s22p63s23p63d84s0 and Ni2+ is paramagnetic in nature.

Explanation of Solution

The electronic configuration of nickel is 1s22s22p63s23p63d84s2. The electronic configuration of Ni2+ is 1s22s22p63s23p63d84s0. Therefore there are two unpaired electrons are there so the Ni2+ is paramagnetic in nature.

(d)

Interpretation Introduction

Interpretation:

The electronic configuration of Cr3+ ion and the magnetic property of the ion has to be identified.

Concept introduction:

The electron configuration tells us in which orbitals the electrons for an element are located. Three rules are,

  • Electrons fill orbitals staring with lowest n and moving upwards(Aufbau principle)
  • No two electrons can fill one orbital with the same spin(Pauli Exclusion Principle)
  • For orbitals within the same subshell, the electrons fill each orbital singly before any orbital gets a second electron (Hund’s rule).

Para magnetism refers to the magnetic state of an atom with one or more unpaired electrons.

Diamagnetism has no unpaired electrons (electrons are paired).

(d)

Expert Solution
Check Mark

Answer to Problem 1PS

The electronic configuration of Cu+ is 1s22s22p63s23p63d104s0 and Cu+ is diamagnetic in nature.

Explanation of Solution

The electronic configuration of copper is 1s22s22p63s23p63d104s1. The electronic configuration of Cu+ is 1s22s22p63s23p63d104s0. Therefore there is no unpaired electrons are there so the Cu+ is diamagnetic in nature.

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Chapter 22 Solutions

Chemistry & Chemical Reactivity

Ch. 22.3 - 2. What is the oxidation number of the metal in...Ch. 22.3 - Prob. 3RCCh. 22.3 - Prob. 4RCCh. 22.4 - What types of isomers are possible for the...Ch. 22.4 - Prob. 1RCCh. 22.4 - Prob. 2RCCh. 22.4 - Prob. 3RCCh. 22.4 - Prob. 4RCCh. 22.4 - Prob. 1QCh. 22.5 - Prob. 1CYUCh. 22.5 - Prob. 1RCCh. 22.5 - Prob. 2RCCh. 22.6 - Prob. 1QCh. 22.6 - Prob. 2QCh. 22.6 - Prob. 3QCh. 22.6 - Prob. 4QCh. 22.6 - Prob. 1CYUCh. 22.6 - Prob. 1RCCh. 22.6 - How are the d electrons of Pt distributed in a...Ch. 22.6 - What are the electron configurations for Nd and...Ch. 22.6 - Prob. 3CSCh. 22.6 - Prob. 4CSCh. 22.6 - Prob. 5CSCh. 22 - Prob. 1PSCh. 22 - Prob. 2PSCh. 22 - Identify a cation of a first series transition...Ch. 22 - Match up the isoelectronic ions on the following...Ch. 22 - Prob. 5PSCh. 22 - Prob. 6PSCh. 22 - Which of the following ligands is expected to be...Ch. 22 - One of the following nitrogen compounds or ions is...Ch. 22 - Prob. 9PSCh. 22 - Prob. 10PSCh. 22 - Prob. 11PSCh. 22 - Prob. 12PSCh. 22 - Prob. 13PSCh. 22 - Prob. 14PSCh. 22 - Prob. 15PSCh. 22 - Prob. 16PSCh. 22 - Give the name or formula for each ion or compound,...Ch. 22 - Prob. 18PSCh. 22 - Prob. 19PSCh. 22 - Prob. 20PSCh. 22 - Prob. 21PSCh. 22 - Prob. 22PSCh. 22 - Prob. 23PSCh. 22 - Prob. 24PSCh. 22 - Prob. 25PSCh. 22 - Prob. 26PSCh. 22 - Prob. 27PSCh. 22 - Prob. 28PSCh. 22 - Prob. 29PSCh. 22 - Prob. 30PSCh. 22 - In water, the titanium(III) ion, [Ti(H2O)6]3+, has...Ch. 22 - Prob. 32PSCh. 22 - Prob. 33GQCh. 22 - Prob. 34GQCh. 22 - How many unpaired electrons are expected for...Ch. 22 - Prob. 36GQCh. 22 - Which of the following complex ions is (are)...Ch. 22 - Prob. 38GQCh. 22 - How many geometric isomers are possible for the...Ch. 22 - For a tetrahedral complex of a metal in the first...Ch. 22 - Prob. 41GQCh. 22 - Prob. 42GQCh. 22 - Prob. 43GQCh. 22 - A platinum-containing compound, known as Magnuss...Ch. 22 - Prob. 45GQCh. 22 - Prob. 46GQCh. 22 - Prob. 47GQCh. 22 - How many geometric isomers of the complex ion...Ch. 22 - Prob. 49GQCh. 22 - Prob. 50GQCh. 22 - Prob. 51GQCh. 22 - The square-planar complex Pt(en)Cl2 has chloride...Ch. 22 - The complex [Mn(H2O)6]2+ has five unpaired...Ch. 22 - Experiments show that K4[Cr(CN)6] is paramagnetic...Ch. 22 - Give a systematic name or the formula for the...Ch. 22 - When CrCI3 dissolves in water, three different...Ch. 22 - Prob. 57GQCh. 22 - The glycinate ion, H2NCH2CO2, formed by...Ch. 22 - Prob. 59GQCh. 22 - Nickel and palladium both form complexes of the...Ch. 22 - The transition metals form a class of compounds...Ch. 22 - Cerium, as noted in Applying Chemical Principles:...Ch. 22 - Prob. 64GQCh. 22 - Two different coordination compounds containing...Ch. 22 - Prob. 71SCQCh. 22 - Prob. 69SCQCh. 22 - Prob. 70SCQ
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