Astronomy Today (9th Edition)
9th Edition
ISBN: 9780134450278
Author: Eric Chaisson, Steve McMillan
Publisher: PEARSON
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Question
Chapter 2, Problem 3P
To determine
The time taken by the spacecraft to travel from Earth to Venus if it has an orbit that just grazes Earth's orbit at aphelion and Venus's orbit at perihelion, assuming that Earth and Venus are in the right places at right time.
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Like all planets, the planet Venus orbits the Sun in periodic motion and simultaneously spins about its axis. Just as on Earth, the time to make one complete orbit (i.e., the period of orbit) is what defines a year. And the time to make one complete revolution about its axis (i.e., the period of rotation) is what defines a day. The period of orbit for the Earth is 365.25 days and the period of rotation is 24 hours (1.00 day). But when these same values for Venus are expressed relative to Earth, it is found that Venus has a period of orbit of 225 days and a period of rotation of 243 days. So for Venus inhabitants, a day would last longer than a year! Determine the frequency of orbit and the frequency of rotation (in Hertz) on Venus.
Solve the problem:
Given: Distance of Venus to sun is 1.08×1011 m and the distance of mars to sun is 2.3×1011 m (688 days). Find period or time mercury to make a complete orbit revolution?
Suppose that a planet were discovered between the Sun and Mercury, with a circular
orbit of radius equal to 2/3 of the average orbit radius of Mercury. What would be the
orbital period of such a planet? (Such a planet was once postulated, in part to explain
the precession of Mercury's orbit. It was even given the name Vulcan, although we now
have no evidence that it actually exists. Mercury's precession has been explained by
general relativity.)
Chapter 2 Solutions
Astronomy Today (9th Edition)
Ch. 2 - Prob. 1DCh. 2 - Prob. 2DCh. 2 - Prob. 3DCh. 2 - Prob. 4DCh. 2 - Prob. 5DCh. 2 - Prob. 6DCh. 2 - Prob. 7DCh. 2 - Prob. 8DCh. 2 - Prob. 9DCh. 2 - Prob. 10D
Ch. 2 - Prob. 11DCh. 2 - Prob. 12DCh. 2 - Prob. 13DCh. 2 - Prob. 14DCh. 2 - Prob. 15DCh. 2 - Prob. 1MCCh. 2 - Prob. 2MCCh. 2 - Prob. 3MCCh. 2 - Prob. 4MCCh. 2 - Prob. 5MCCh. 2 - Prob. 6MCCh. 2 - Prob. 7MCCh. 2 - Prob. 8MCCh. 2 - Prob. 9MCCh. 2 - Prob. 10MCCh. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8P
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- The semimajor axis of Mars orbit is about 1.52 astronomical units (au), where an au is the Earth's average distance from the Sun, meaning the semimajor axis of Earth's orbit is 1 au. To go from Earth to Mars and use the least energy from rocket fuel, the orbit has a semimajor axis of 1.26 au and an eccentricity of about 0.21. Starting at Earth's orbit, to follow this path we give the spacecraft an orbital velocity of 40 km/s. Which of the following describes this best? It arrives at Mars orbit at the same moment that Mars is there, and must speed up to go into an orbit next to Mars or else drop back into perihelion (closest to the Sun) at Earth's orbit. It arrives at Mars orbit at the same moment that Mars is there, and must slow down to go into an orbit next to Mars or else drop back into perihelion (closest to the Sun) at Earth's orbit. It flys past Mars on its trajectory unless it is braked by accelerating toward the Sun. It which leaves Earth when…arrow_forwardSuppose that a planet were discovered between the Sun and Mercury, with a circular radius equal to 3.86 x 1010 m (two-thirds of the orbit radius of Mercury). What would be the orbital period of such a planet?arrow_forwarda person leaves planet b-25 and constructs a small rocket. the person has a mass of 20 kg, the rocket has a mass of 480 kg, and the planet has a mass of 100,000 kg along with a radius of of 50 m. what is the force of gravity between the person and the planet when the person is standing on it? what us the value for the acceleration due to gravity at this point?arrow_forward
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