Principles of Foundation Engineering (MindTap Course List)
9th Edition
ISBN: 9781337705028
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 2, Problem 2.7P
To determine
Classify the given soil using the Unified soil classification system give their symbols.
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The total volume of a soil specimen is 80,000 mm^3 and has a mass of 152 g. the dry mass of the specimen is 122g, and the density of the soil is 2.65 Mg/m^3. Compute the following index properties: (a) e; (b) n; (c) S; (d) ρt; and (e) ρd. Include phase diagrams.
PROBLEM 5:
Laboratory test shows that a soil
sample has emax = 0.85 and emin =
0.55. If the porosity of the sample is
43%, compute the density index.
a. 26%
C. 45%
b. 32%
d. 28%
U
B. (
A Soil Specimen has the following characteristics:
% passing No.4 sieve = 85
% passing No.200 sieve = 11
D60 = 2 mm
D30 = 0.35 mm
D₁0 = 70 μm
L.L = 36%
P.L = 31%
D8 = 2 µm
1. Classify the specimen according to the Unified Soil Classification System
(USCS). Assign the group name and the group symbol.
2. Determine the soil activity.
3. Determine the soil Liquidity index and consistency index if we = 26%.
Chapter 2 Solutions
Principles of Foundation Engineering (MindTap Course List)
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- Question 8 (1) - Oedometer test What are the boundary conditions applied to a soil sample tested in an Oedometer? Z H a) Pore water pressure at z = H (top of the sample) is PH = Yw. H b) Ez = Ex c) &z=&v (₂ is the volumetric strain of the sample) d) At time t=0, 4p = 0arrow_forwardQ # 1. Organic soils are typically characterized by high void ratio, low specific gravity, and high compressibility. Following are the results of a consolidation test on a sample of organic soil. Pressure, o (kN/m2) Change in dial reading, AH (mm) 0.284 12 0.150 24 0.315 48 0.564 100 0.823 200 2.25 400 5.34 Given that the initial height of the specimen = 20.6 mm, mass of dry specimen = 12 g, area of specimen = 31.67 cm2 and G, = 2.49. Plot the e, log o' curve. b. Determine the preconsolidation pressure. a.arrow_forwardThe same soil sample has a natural moisture content of 30% and was subject to the Atterberg Limits test. The plastic limit was measured as 27 while the liquid limit test shows the results in the table below. Number of Blows 42 26 10 Moisture Content 20 32 45 a. Determine the liquid limit of the soil sample. Show and briefly explain how you got the answer. b. Solve and describe the Plasticity Index of the soil sample. c. Determine value and soil state of the liquidity index of the soil sample. d. Determined and describe the clay activity of the soil sample.arrow_forward
- Permeability tests were performed on a soil sample, under different void ratio and different temperatures and the following results were obtained. Test No. 1 2 Void ratio (e) 0.65 1.02 Temperature °℃ 25° 40⁰ Estimate the coefficient of permeability at a temperature of 20°C for a voids ratio of 0.80. Given the following physical properties of water: At 20°C, n = 10.09 × 10+ and p„ = 0.998 g/cm³ At 25°C, n = 8.95 × 104 g sec/cm² and p k(cm/s) 0.4x10 1.9x10-¹ At 40° C, n = 6.54 × 10-¹ g sec/cm² and p $0.997 g/cm³ = = 0.992 g/cm³arrow_forwardA soil profile is shown in Figure P3.3 along with the standardpenetration numbers in the clay layer. Use Eqs. (3.8b)and (3.9) to determine the variation of cu and OCR withdepth. What is the average value of cu and OCR?arrow_forwardSr B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30=0.35 mm D₁0 = 70 μm D8=2 μm L.L = 36% P.L = 31% 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if wc = 26%.arrow_forward
- The following results were obtained from an oedometer test on a specimen of saturated clay: 54 107 214 429 214 107 54 27 Pressure (kPa): 1.024 1.012 1.001 0.994 1.068 1.144 1.217 1.243 Void ratio: A layer of this clay 8 m thick lies below a 4 m depth of sand, the water table being at the surface. The saturated unit weight for both soils =19 kN/m3=19 kN/m3. A 4 m depth of fill, unit weight =21 kN/m3=21 kN/m3, is placed on the sand over an extensive area. Determine the final settlement due to consolidation of the clay. If the fill were to be removed some time after the completion of consolidation, what heave would eventually take place due to swelling of the clay?arrow_forwardThe consistency limits of a soil sample are: LL=52%, PL=35%, SL=17%. If a specimen of this soil shrinks from a volume of 10 cc at liquid limit to 6.1 cc at plastic limit, determine the specific gravity of solids. Answer should be Gs=2.65.arrow_forwardThe grain-size characteristics of soil re given in the following table. Use Table 2.3 for the analysis. Size (mm) Percent finer 0.425 100 0.1 79 0.04 57 0.02 48 0.01 40 0.002 35 0.001 33 Table 2.3 Particle-Size Classifications Grain size (mm) Name of organization Gravel Sand Silt Clay Massachusetts Institute of Technology (MIT) >2 2 to 0.06 0.06 to 0.002 2 <0.002 76.2 to 2 2 to 0.075 0.075 to 0.002 <0.002 Fines (i.e., silts and clays) <0.075 76.2 to 4.75 4.75 to 0.075 Note: Sieve openings of 4.75 mm are found on a U.S. No. 4 sieve; 2-mm openings on a U.S. No. 10 sieve; 0.075-mm openings on a U.S. No. 200 sieve. See Table 2.5. i.) What is the percentages of gravel, sand, silt and clay according to the MIT system. a.) Gravel – 0%; Sand – 38%; Silt – 30%; Clay – 35% b.) Gravel – 0%; Sand – 37%; Silt – 30%; Clay – 35% c.) Gravel – 0%; Sand – 36%; Silt – 30%; Clay – 35% d.) Gravel – 0%; Sand – 35%; Silt – 30%; Clay – 35% e.) None of the abovearrow_forward
- The grain-size characteristics of soil re given in the following table. Use Table 2.3 for the analysis. Size (mm) Percent finer 0.425 100 0.1 79 0.04 57 0.02 48 0.01 40 0.002 35 0.001 33 Table 2.3 Particle-Size Classifications Grain size (mm) Name of organization Gravel Sand Silt Clay Massachusetts Institute of Technology (MIT) >2 2 to 0.06 0.06 to 0.002 2 <0.002 76.2 to 2 2 to 0.075 0.075 to 0.002 <0.002 Fines (i.e., silts and clays) <0.075 76.2 to 4.75 4.75 to 0.075 Note: Sieve openings of 4.75 mm are found on a U.S. No. 4 sieve; 2-mm openings on a U.S. No. 10 sieve; 0.075-mm openings on a U.S. No. 200 sieve. See Table 2.5. What is the percentages of gravel, sand, silt and clay according to the USDA system a.) Gravel – 0%; Sand – 38%; Silt – 26%; Clay – 35% b.) Gravel – 0%; Sand – 38%; Silt – 27%; Clay – 33% c.) Gravel – 0%; Sand – 38%; Silt – 26%; Clay – 34% d.) Gravel – 0%; Sand – 38%; Silt – 27%; Clay – 35% e.) None of the abovearrow_forwardA liquid limit test on a clay was performed with the following results. The natural water content of the clay is 38% and plastic limit is 21%. Number of Blows 6 12 20 28 32 Water content (%) 52.5 47.1 42.3 38.6 37.5 What is the liquidity index of this clay? (Use Interpolation) Group of answer choices 0.895 0.96 1.08 0.90 Please answer this asap. For upvote. Thanksarrow_forward5. The results of a particle size analysis of a soil are given in the following table. The Atterberg limit tests yielded LL=62, PL = 20. Sieve Opening (mm) Percent Coarser by Weight Sieve No. 4.75 5.1 10 2.00 10.0 20 0.85 0.425 40.7 40 70.2 84.8 90.5 60 0.25 100 0.15 200 Pan 0.075 100 a) Draw the gradation curve for this soil b) Determine the uniformity coefficient and the coefficient of curvature c) Classify the soil using USCS and ASSHTO d) Rate this soil as a subgrade for highway constructionarrow_forward
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