Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN: 9781337399074
Author: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher: Cengage Learning
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Chapter 2, Problem 111GQ
Interpretation Introduction

Interpretation:

The given elements are needed to be arranged in order from smallest to largest mass.

Concept introduction:

Molar masses of Fe,H2, C, Si, Na, Al andCl2 are

55.8g, 2.01g, 12.01g, 28.08g, 23g, 27g and 39g  respectively.

  • Conversion formula for mass of an atom into number moles,

    Numberofmoles=MassingramsMolarmass 

  • Equation for finding number of atoms from number of moles of an atom,

    Numberofatoms=numberofmolesofatom×6.022×1023atoms/mol

Expert Solution & Answer
Check Mark

Answer to Problem 111GQ

(b)40.04gH2< (c)103gC<(f)182gAl<(d)208gSi<(e)212gNa<(a)351gFe<(g)652gCl2

Explanation of Solution

(a) 3.79×1024atomsFe

Equation for finding number of atoms from number of moles of an atom,

  Numberofatoms=MassingramsMolarmass×6.022×1023atoms/mol

Therefore,

The mass of Fe in the given amount is,   

    3.79×1024atoms6.022×1023atoms/mol×55.845g/mol=351g

(b) 19.921molH2

Conversion formula for number moles of a molecule into mass,

    Numberofmoles×Molarmass=Massingrams

Therefore,

The mass of H2 in the given amount is,

    19.921mol×2.01g/mol=40.04g

(c) 8.576molC

Conversion formula for number moles of an atom into mass,

    Numberofmoles×Molarmass=Massingrams

Therefore,

The mass of C in the given amount is,

    8.576mol×12.01g/mol=103g

(d) 7.4molSi

Conversion formula for number moles of an atom into mass,

    Numberofmoles×Molarmass=Massingrams

Therefore,

The mass of silicon in the given amount is,

    7.4mol×28.08g/mol=208g

(e) 9.221molNa

Conversion formula for number of moles of an atom into mass,

    Numberofmoles×Molarmass=Massingrams

Therefore,

The mass of sodium in the given amount is,

    9.221mol×23g/mol=212g

(f) 4.07×1024atomsAl

Equation for finding number of atoms from number of moles of an atom,

  Numberofatoms=MassingramsMolarmass×6.022×1023atoms/mol

Therefore,

The mass of Aluminum in the given amount is,   

    4.07×1024atoms6.022×1023atoms/mol×27g/mol=182g

(g) 9.2molCl2

Conversion formula for number moles of a molecule into mass,

    Numberofmoles×Molarmass=Massingrams

Therefore,

The mass of Cl2 in the given amount is,

    9.2mol×70.91g/mol=652g

Hence,

The increasing order of mass of the given elements is,

(b)40.04gH2< (c)103gC<(f)182gAl<(d)208gSi<(e)212gNa<(a)351gFe<(g)652gCl2

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Chapter 2 Solutions

Chemistry & Chemical Reactivity

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