Physical Chemistry
Physical Chemistry
2nd Edition
ISBN: 9781133958437
Author: Ball, David W. (david Warren), BAER, Tomas
Publisher: Wadsworth Cengage Learning,
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Chapter 19, Problem 19.35E
Interpretation Introduction

Interpretation:

The mean free path of Ne at 300.0K and 0.987bar is to be calculated.

Concept introduction:

The mean distance traveled by the same particle between two consecutive collisions is termed as mean free path. The value of the mean free path of a gas depends on the pressure and temperature of the system. The mean free path of gas is represented as,

λ=kT2πd2p …(1)

Where,

T represents the temperature.

dcollision diameter of a gas.

p represents the pressure.

k represents the Boltzmann constant with value 1.381×1023J/K.

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Chapter 19 Solutions

Physical Chemistry

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