C How to Program (8th Edition)
C How to Program (8th Edition)
8th Edition
ISBN: 9780133976892
Author: Paul J. Deitel, Harvey Deitel
Publisher: PEARSON
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Chapter 18, Problem 18.6E

(Memory Allocation and Deallocation Operators) Compare and contrast dynamic memory allocation and deallocation operators new, new [], delete and delete []:

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Program Plan Intro

To compare and contrast dynamic memory allocation and deallocation operators new, new[], delete and delete[].

Explanation of Solution

The following table shows the differences.

    S. No. NewDelete New[]Delete[]
    1.Dynamically allocates memory for a variable or object. Dynamically de-allocates memory for a variable or object. Dynamically allocates memory for an array.Dynamically de-allocates memory for an array.
    2.Arguments passed to initialize class constructorNo arguments needed to be passed to call destructorArguments passed to initialize array size (bytes).No arguments needed to be passed to call destructor.
    3.Memory de-allocation must be done using delete operator.Memory allocation must be done using new operator. Memory deallocation must be done using delete[] operator.Memory allocation must be done using new[] operator.
    4.Returns address of allocated object. Returns void() and sets memory to NULL.Returns address of first element of allocated array.Returns void() and sets all memory to NULL.
    5.For example,
    int *xPtr;
    xPtr= new int;
    For example,
    delete xPtr;
    For example,
    int *xPtr;
    xPtr= new int[10];
    For example,
    Delete[] xptr;

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(Memory Allocation and Deallocation Operators) Compare and contrast dynamic memoryallocation and deallocation operators new, new [], delete and delete [].
15. The only way to access data stored in heap memory is through pointer variables malloc () allocation tables а. b. С. d. a buffer memory
Language:C Write the function that produces the largest and smallest elements of an integer array sent to it, in accordance with the main function below. (Access to array elements should be done according to offset-address increment notation.)Sample Run:Biggest : 23Smallest : 0Sample Main................................/*prototip*/int main(){int array[5]={23, 4, 2, 0, 8};int biggest;int smallest;bigSmallFind(.............................)printf("Biggest : %d \n", biggest);printf("Smallest : %d \n", smallest);return 0; }

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