Principles of Biology
2nd Edition
ISBN: 9781259875120
Author: Robert Brooker, Eric P. Widmaier Dr., Linda Graham Dr. Ph.D., Peter Stiling Dr. Ph.D.
Publisher: McGraw-Hill Education
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Chapter 17.3, Problem 1CC
Summary Introduction
To analyze:
The presence of the F factor in donor as well as recipient cell post conjugation.
Introduction:
Bacteria reproduce by asexual reproduction but have genetic diversity. The bacteria transfer the genetic material to another one. The three methods by which genetic material is transferred are conjugation, transduction, and transformation.
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The following recombinants are recovered when
conjugation occurs between an a*d*g+ donor and an
adg recipient.
at d+ g+ = 84%
a d g+ = 6%
at d g+ = 10%
a dt g+ = less than 1%
What is the map distance between the a and d genes?
10 map units
74 map units
less than 1 map unit
84 map units
6 map units
The following recombinants
are recovered when
conjugation occurs between an a+d+g+ donor and an a
d'g recipient.
at dt g+= 84%
ad g+= 6%
at dg+ = 10%
ad g+= less than 1%
What is the map distance between the a and d genes?
6 map units
less than 1 map unit
10 map units
84 map units
74 map units
A series of Hfr strains that have genotype m+ n+ o+ p+ q+ r+ are mixed with an F− strain that has genotype m− n− o− p− q− r−. Conjugation is interrupted at regular intervals and the order of the appearance of genes from the Hfr strain is determined in the recipient cells. The order of gene transfer for each Hfr strain is What is the order of genes on the circular bacterial chromosome? For each Hfr strain, give the location of the F factor in the chromosome and its polarity. Hfr5 m+ q+ p+ n+ r+ o+ Hfr4 n+ r+ o+ m+ q+ p+ Hfr1 o+ m+ q+ p+ n+ r+ Hfr9 q+ m+ o+ r+ n+ p+
Chapter 17 Solutions
Principles of Biology
Ch. 17.1 - Prob. 1CCCh. 17.1 - Prob. 1BCCh. 17.1 - Prob. 1TYKCh. 17.1 - The step in the viral cycle that follows...Ch. 17.2 - Prob. 1CCCh. 17.2 - Prob. 1BCCh. 17.2 - Describe how the loop domains are held in place.Ch. 17.2 - Prob. 3CCCh. 17.2 - Prob. 4CCCh. 17.2 - Prob. 1TYK
Ch. 17.2 - Prob. 2TYKCh. 17.2 - Prob. 3TYKCh. 17.3 - Prob. 1CCCh. 17.3 - Prob. 1BCCh. 17.3 - Prob. 2CCCh. 17.3 - Prob. 1TYKCh. 17.3 - Prob. 2TYKCh. 17 - Prob. 1TYCh. 17 - Which of the following does hot describe a typical...Ch. 17 - Prob. 3TYCh. 17 - Prob. 4TYCh. 17 - Prob. 5TYCh. 17 - Genetic diversity is not maintained in bacterial...Ch. 17 - Prob. 7TYCh. 17 - Prob. 8TYCh. 17 - Prob. 9TYCh. 17 - Prob. 10TYCh. 17 - How are viruses similar to and different from...Ch. 17 - Describe the three mechanisms of gene transfer in...Ch. 17 - Prob. 3CCQCh. 17 - Prob. 1CBQCh. 17 - Conjugation is sometimes called bacterial mating....
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- Consider the following types of cells: F+, F-, Hfr, and F’ cells. Which of these four types of cells are capable of acting as a donor during conjugation? What genes does each cell that is capable of acting as a donor donate to the recipient cell?arrow_forwardA particular Hfr strain normally transmits the pro+marker as the last one in conjugation. In a cross of thisstrain with an F− strain, some pro+ recombinants are recovered early in the mating process. When these pro+cells are mixed with F−cells, the majority of the F− cellsare converted into pro+ cells that also carry the F factor.Explain these results.arrow_forwardIn a conjugation experiment, How is the time of entry determined experimentally?arrow_forward
- Eight mutant bacteriophage strains cannot lyse a certain type of bacteria that can be lysed by wild-type bacteriophages. The mutant strains were allowed to infect the bacteria in a complementation test. A "+" indicates that lysis occurred with coinfection. A "-" indicates that lysis did not occur. GKWTMAQC G- ++++- K W T M A Q C - + +++ - ++++ - + + - + - + - - + + + A cistron is defined by no complementation in the How many genes are controlling lysis in this bacteriophage? (Use a number not a word in the space) configuration.arrow_forwardAn Hfrstrain that is a *b*c*d* e*f* g *h* is mated with an F strain that is a b e d e f gh. The mating is interrupted at 5 minutes interval, and the genotypes of the F recombinants are determined. The results obtained are tabulated in Table 2. Draw the map of the Hfrchromosome and indicate the position of the origin of transfer, the direction of the transfer and the minutes between genes. Table 2:Entry time of Hfr chromosome into recipient cell. Time a d e f h 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 + + + + + + + + + + + + + + + + + + + + + + + + + + + + + + + + +arrow_forwardIn E. coli, four Hfr strains donate the following markers,shown in the order donated:Strain 1: M Z X W CStrain 2: L A N C WStrain 3: A L B R UStrain 4: Z M U R BAll these Hfr strains are derived from the same F+ strain.What is the order of these markers on the circularchromosome of the original F+?arrow_forward
- Wild-type bacteria were used as donors to transduce the following recipient genotypes with the results indicated as the number of wild type colonies: Recipient Recipient leu- phe+ his- met+ tyr+ leu- phe+ his+ met- tyr+ leu- phe+ his+ met+ tyr- leu- phe- his+ met+ tyr+ leu+ phe+ his-met- tyr+ 127 leu+ phe-his- met+ tyr+ #wild type 37 138 132 1 leu+ phe+ his- met+ tyr- leu+ phe-his+ met- tyr+ leu+ phe-hist met+ tyr- leu- phe+ his+ met+ tyr+ 22 6 leu+ phe+ his+ met- tyr- 148 31 304 leu+ phe+ his+ met+ tyr- What is the order of the genes? tyr-leu-his-phe-met O leu-met-phe-his-tyr leu-his-met-tyr-phe his-tyr-leu-phe-met #wild type 356 10arrow_forwardDuring conjugation, HFR; F+ function as DNA donors and function as DNA recipients. F+; F- F-; F+ F-; HFRarrow_forwardIn E. coli, the gene bioD+ encodes an enzyme involved in biotin synthesis, and galK+ encodes an enzyme involved in galactose utilization. An E. coli strain that contained wild-type versions of both genes was infected with P1 phage, and then a P1 lysate was obtained. This lysate was used totransduce (infect) a strain that was bioD− and galK−. The cellswere plated on a medium containing galactose as the sole carbonsource for growth to select for transduction of the galK+ gene.This medium also was supplemented with biotin. The resultingcolonies were then restreaked on a medium that lacked biotin tosee if the bioD+ gene had been cotransduced. The following resultswere obtained:What topic in genetics does this question address?arrow_forward
- In E. coli, the gene bioD+ encodes an enzyme involved in biotin synthesis, and galK+ encodes an enzyme involved in galactose utilization. An E. coli strain that contained wild-type versions of both genes was infected with P1 phage, and then a P1 lysate was obtained. This lysate was used totransduce (infect) a strain that was bioD− and galK−. The cellswere plated on a medium containing galactose as the sole carbonsource for growth to select for transduction of the galK+ gene.This medium also was supplemented with biotin. The resultingcolonies were then restreaked on a medium that lacked biotin tosee if the bioD+ gene had been cotransduced. The following resultswere obtained:What information do you know based onthe question and your understanding of the topic?arrow_forwardHow would this figure change if double-stranded DNA were incorporated into the donor cell’s chromosome?arrow_forwardIn Conjugation,Why a Donor TransfersDNA Directly to a Recipient?arrow_forward
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genetic recombination strategies of bacteria CONJUGATION, TRANSDUCTION AND TRANSFORMATION; Author: Scientist Cindy;https://www.youtube.com/watch?v=_Va8FZJEl9A;License: Standard youtube license