Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
Question
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Chapter 17.1, Problem 8SSC
Interpretation Introduction

Interpretation:

The relation of size of equilibrium constant with amount of products is to be discussed.

Concept introduction:

The equilibrium constant expresses the relationship between product and reactants of a reaction at equilibrium.

The equilibrium constant is denoted by 'KC'.

a)A+BC+D.

ReactantsProducts

KC for this reaction

KC=[C][D][A][B]

b)aA+bBcC+dD.

KC=[C]c[D]d[A]a[B]b

In this reaction [A][B][C][D] are the equilibrium concentration of the reactant and product. Therefore, KC=[Product][Reactant]

Expert Solution & Answer
Check Mark

Answer to Problem 8SSC

If KC>1, amount of product formed is more than reactant.

If KC<1, amount of product formed is less than reactant.

Explanation of Solution

For the reaction:

A+BC+D.

ReactantsProducts

KC for this reaction is given by:

KC=[C][D][A][B]

Thus KC>1, product of concentration of products is more than reactants.

KC<1, product of concentration of products is less than reactants.

if KC is very large in size, the reaction proceeds near to completion.

H2(g)+Cl2(g)2HCl(g)

At 300K has

KC=4.0×1031

On the other hand,

If KC<1 reactant predominates.

Conclusion

Thus size of equilibrium constant is related to amount of products.

Chapter 17 Solutions

Chemistry: Matter and Change

Ch. 17.1 - Prob. 11SSCCh. 17.1 - Prob. 12SSCCh. 17.2 - Prob. 13SSCCh. 17.2 - Prob. 14SSCCh. 17.2 - Prob. 15SSCCh. 17.2 - Prob. 16SSCCh. 17.2 - Prob. 17SSCCh. 17.3 - Prob. 18PPCh. 17.3 - Prob. 19PPCh. 17.3 - Prob. 20PPCh. 17.3 - Prob. 21PPCh. 17.3 - Prob. 22PPCh. 17.3 - Prob. 23PPCh. 17.3 - Prob. 24PPCh. 17.3 - Prob. 25PPCh. 17.3 - Prob. 26PPCh. 17.3 - Prob. 27SSCCh. 17.3 - Prob. 28SSCCh. 17.3 - Prob. 29SSCCh. 17.3 - Prob. 30SSCCh. 17.3 - Prob. 31SSCCh. 17.3 - Prob. 32SSCCh. 17 - Prob. 33ACh. 17 - Prob. 34ACh. 17 - Prob. 35ACh. 17 - Prob. 36ACh. 17 - Prob. 37ACh. 17 - Prob. 38ACh. 17 - Prob. 39ACh. 17 - Prob. 40ACh. 17 - Prob. 41ACh. 17 - Prob. 42ACh. 17 - Prob. 43ACh. 17 - Prob. 44ACh. 17 - Prob. 45ACh. 17 - Prob. 46ACh. 17 - Prob. 47ACh. 17 - Prob. 48ACh. 17 - Prob. 49ACh. 17 - Prob. 50ACh. 17 - Prob. 51ACh. 17 - Prob. 52ACh. 17 - Prob. 53ACh. 17 - Prob. 54ACh. 17 - Prob. 55ACh. 17 - Prob. 56ACh. 17 - Prob. 57ACh. 17 - Prob. 58ACh. 17 - Prob. 59ACh. 17 - Prob. 60ACh. 17 - Prob. 61ACh. 17 - Prob. 62ACh. 17 - Prob. 63ACh. 17 - Prob. 64ACh. 17 - Why are compounds such as sodium chloride usually...Ch. 17 - Prob. 66ACh. 17 - Prob. 67ACh. 17 - Prob. 68ACh. 17 - Prob. 69ACh. 17 - Prob. 70ACh. 17 - Prob. 71ACh. 17 - Prob. 72ACh. 17 - Prob. 73ACh. 17 - Prob. 74ACh. 17 - Prob. 75ACh. 17 - Prob. 76ACh. 17 - Prob. 77ACh. 17 - Prob. 78ACh. 17 - Evaluate this statement: A low value for Keq means...Ch. 17 - Prob. 80ACh. 17 - Prob. 81ACh. 17 - Prob. 82ACh. 17 - Prob. 83ACh. 17 - Prob. 84ACh. 17 - Prob. 85ACh. 17 - Prob. 86ACh. 17 - Prob. 87ACh. 17 - Prob. 88ACh. 17 - Prob. 89ACh. 17 - Prob. 90ACh. 17 - Prob. 91ACh. 17 - Prob. 92ACh. 17 - Prob. 93ACh. 17 - Prob. 94ACh. 17 - Prob. 95ACh. 17 - Prob. 96ACh. 17 - Prob. 97ACh. 17 - Prob. 98ACh. 17 - Prob. 99ACh. 17 - Prob. 100ACh. 17 - Prob. 101ACh. 17 - Prob. 102ACh. 17 - Prob. 103ACh. 17 - Prob. 104ACh. 17 - Prob. 105ACh. 17 - Prob. 1STPCh. 17 - Prob. 2STPCh. 17 - Prob. 3STPCh. 17 - Prob. 4STPCh. 17 - Prob. 5STPCh. 17 - Prob. 6STPCh. 17 - Prob. 7STPCh. 17 - Prob. 8STPCh. 17 - Prob. 9STPCh. 17 - Prob. 10STPCh. 17 - Prob. 11STPCh. 17 - Prob. 12STPCh. 17 - Prob. 13STPCh. 17 - Prob. 14STPCh. 17 - Prob. 15STPCh. 17 - Prob. 16STPCh. 17 - Prob. 17STPCh. 17 - Prob. 18STP
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