Laboratory Techniques in Organic Chemistry
Laboratory Techniques in Organic Chemistry
4th Edition
ISBN: 9781464134227
Author: Jerry R. Mohrig, David Alberg, Gretchen Hofmeister, Paul F. Schatz, Christina Noring Hammond
Publisher: W. H. Freeman
Question
Book Icon
Chapter 14, Problem 1Q
Interpretation Introduction

Interpretation:

The reason for the broader melting point range observed for second sample should be determined.

Concept introduction:

For a crystalline substance, the temperature at which the substance changes from solid phase to liquid phase is referred to as melting point. Melting point is directly associated with the presence of intermolecular forces like hydrogen bonding, dipole-dipole interactions. High molecular symmetry, large surface area, polarity is related to high melting temperature.

A pure compound melt at a narrow range and compounds with impurities have broad melting temperature. Melting points are obtained by filling the organic compound into the capillary tube with one end sealed.

Expert Solution & Answer
Check Mark

Explanation of Solution

To determine the melting point of a sample the capillary tube is filled with a sample with one end sealed. After that, the sample is heated to a temperature where the solid sample begins to convert into a liquid phase which signifies its melting point.

If too much sample is added to the capillary, the range of melting point becomes broad as more time it takes to melt the whole sample while the temperature of the sample increases with time.

Therefore the sample height of 4-5mm has a broader melting temperature range (141°C-145°C) than for the sample height of 1-2mm with melting range of (141°C-142°C) .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
A student obtained a solid product in a laboratory synthesis. To verify the identity of the solid, she measured its melting point and found that the material melted over a 10°C range. After it had cooled, she measured the melting point of the same sample again and found that this time the solid had a sharp melting point at the temperature that is characteristic of the desired product. Why were the two melting points different? What was responsible for the change in the melting point?
4. When performing a melting point on a solid compound using a melting point apparatus, two melting point determinations were made. One sample, which was 1 mm in height in the capillary, possessed a melting point of 200.0-200.5°C. The other sample was 25 mm in height. What would you expect the approximate melting point to be for this sample, assuming identical heating rates of 1°/min? (Hint: heat is applied from the bottom of the sample) (Give an actual numerical approximation!) 5. For the same solid compound as the question above, if the 1 mm sample was heated at 60° per minute on a melting point apparatus, what would you expect for an approximate melting point? (note that at this heating rate, the sample will melt rather quickly, but again give an actual numerical approximation)
What characteristics must a substance possess for it to be separated from a heterogeneous mixture by steam distillation?

Chapter 14 Solutions

Laboratory Techniques in Organic Chemistry

Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning