COLLEGE PHYSICS
COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 14, Problem 123QAP
To determine

(a)

The amount of heat required to melt the ice.

Expert Solution
Check Mark

Answer to Problem 123QAP

The amount of heat required to melt the ice is 7.1×1020J.

Explanation of Solution

Given info:

Area covered by melted ice is, A=720000km2.

Thickness of melted ice is, l=3.0m.

Initial temperature of ice is, Ti=10°C.

Formula used:

Formula for the heat required to change the temperature is,

  Q=mcΔT

Formula for the heat required to change the phase is,

  Q=mL

Calculation:

Density of melted ice is,

  ρice=92%×ρwρice=92100×1000kg/m3ρice=920kg/m3

The mass of the melted ice can be calculated as,

  m=ρice×Vm=ρice×(A×l)m=920kg/m3×(720000×106m2×3.0m)m=19.872×1014kg

The amount of heat required to melt the ice is,

  Q=mciceΔT+mLfQ=19.872×1014×2093×(100)+19.872×1014×334×103Q7.1×1020J

Conclusion:

Thus, the amount of heat required to melt the ice is 7.1×1020J.

To determine

(b)

The amount of gasoline that contains as much energy as in part (a).

Expert Solution
Check Mark

Answer to Problem 123QAP

The amount of gasoline that contains as much energy as in part (a) is 5.46×1012gal.

Explanation of Solution

Given info:

The heat required to melt the ice is, Q=7.1×1020J.

Heat released by 1 gallon of gasoline is, Q=1.3×108J/gal.

Formula used:

Formula to calculate the amount of gasoline is,

  V=QQ

Calculation:

Substituting the values in the above equation, we get

  V=7.1×1020J1.3×108J/galV=5.46×1012gal

Conclusion:

Thus, the amount of gasoline that contains as much energy as in part (a) is 5.46×1012gal.

To determine

(c)

The amount of coal needed to be burned to produce the energy to melt the ice.

Expert Solution
Check Mark

Answer to Problem 123QAP

The amount of coal needed to be burned to produce the energy to melt the ice is 3.3×1010ton.

Explanation of Solution

Given info:

The heat required to melt the ice is, Q=7.1×1020J.

Heat produced by 1 ton of coal is, Q=21.5×109J/ton.

Formula used:

Formula to calculate the amount of gasoline is,

  m=QQ

Calculation:

Substituting the values in the above equation, we get

  m=7.1×1020J21.5×109J/tonm=3.3×1010ton

Conclusion:

Thus, the amount of coal needed to be burned to produce the energy to melt the ice is 3.3×1010ton.

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Chapter 14 Solutions

COLLEGE PHYSICS

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