Chapter 12.7, Problem 12.17P

a.

Interpretation Introduction

Interpretation:

The oxidation of ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}\text{SH}$ gives disulfide has to be drawn.

Oxidation and reduction of thiols:

Thiols are organic compounds which contain a sulfhydryl group (SH group) bonded to a tetrahedral carbon. Thiols differ from alcohols, as they are incapable of intermolecular hydrogen bonding. This gives thiols lower boiling points and melting points than alcohols even though having the same size and shape.

Oxidation of thiols:

In the presence of oxygen, thiols are oxidized and it converted into disulfides by removal of H₂ molecule.

Reduction of thiols:

In the presence of hydrogen, disulfides are reduced to thiols by gaining hydrogen atoms.

b.

Interpretation Introduction

Interpretation:

The product formed on the reduction of ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{SSCH}}_{\text{2}}{\text{CH}}_{\text{3}}$ has to be drawn.

Concept introduction:

Refer to part a.