Concept explainers
Interpretation:
A line formulas for all primary, secondary, or tertiary free radicals having molecular formula
Concept introduction:
A carbon atom with three bonds and one unpaired electron is called a carbon radical.
The stability order of a carbon radical is Methyl < Primary < Secondary < Tertiary.
The methyl carbon radical is bonded to three hydrogen atoms.
The primary carbon radical is bonded to two hydrogen atoms.
The secondary carbon radical is bonded to one hydrogen atom.
The tertiary carbon radical does not have hydrogen attached.
Constitutional isomers having the same molecular formula differ in the order in which their atoms are connected.
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Chapter 10 Solutions
Organic Chemistry - Standalone book
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- Decide whether each of the molecules in the table below is stable, in the exact form in which it is drawn, at pH = 1. If you decide at least one molecule is not stable, then redraw one of the unstable molecules in its stable form below the table. (If more than one molecule is unstable, you can pick any of them to redraw.) OH O stable O unstable OH X 5 O stable O unstable O stable O stable O unstable OH O unstable OHarrow_forwardch 7 1: photosynthesis uses 690-nm light to convert CO2 and H2O into glucose and O2. claculate the frequncy of this light.arrow_forwardMany free radicals combine to form molecules that do not contain any unpaired electrons. The driving force for the radical- radical combination reaction is the formation of a new electron-pair bond. Consider the formation of hydrogen peroxide. 2 OH(g) → H₂O₂(g) Write Lewis formulas for the reactant and product species in the chemical equation. Include nonbonding electrons. OH(g) Select Draw Rings More / ||| ||| Erase Q2 Q H₂O₂(g) Select Draw Rings More 3 S H Erase Q2 Q Question Source: McQuarrie, Rock, And Gallogly 4e - General Chemistry Publisher: University Science Barrow_forward
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- Formation of ammonia from nitrogen and hydrogen is an exothermic process. Which of the following statements is true about the bonds that are broken and formed during this reaction? N2(g) + 3H2(g) ---> 2NH3(g) a.) products have lower PE because product bonds are weaker than reactants b.) products have higher PE because product bonds are stronger than reactants c.) products have higher PE because product bonds are weaker than reactants d.) products have lower PE because product bonds are stronger than reactantsarrow_forwarda) Classify the following radicals as 1o, 2o, or 3o and b) rank them in order of stability. (1 = most stable).arrow_forwardWhat's the formal charge of the central carbonarrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning