Basics Of Engineering Economy
2nd Edition
ISBN: 9780073376356
Author: Leland Blank, Anthony Tarquin
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Chapter 1, Problem 69APQ
To determine
Calculate the
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Suppose that $30,000 is borrowed today at 12% interest. The loan is to be repaid by uniform annual payments for 5 years,
beginning 1 year from now. Calculate the annual payment.
A) $500 per year
$8,322 per year
C
$108,140 per year
D) $3603.00 per year
2. How long does it takes a principal of P25,000 at a simple interest rate of 5% per year to become P30,000? Draw the cash flow diagram.
Please try to solve it in 20 minute
How much money would you pay in interest if you borrowed $1,600 for 3 years at a compound interest of 14% per annum?
Chapter 1 Solutions
Basics Of Engineering Economy
Ch. 1 - Prob. 1PCh. 1 - Which of the following would be considered...Ch. 1 - Prob. 3PCh. 1 - Prob. 4PCh. 1 - Prob. 5PCh. 1 - Prob. 6PCh. 1 - Prob. 7PCh. 1 - Prob. 8PCh. 1 - Prob. 9PCh. 1 - What is meant by the term time value of money?
Ch. 1 - Prob. 11PCh. 1 - Of the fundamental dimensions length, mass, time,...Ch. 1 - Prob. 13PCh. 1 - When an interest rate statement does not include a...Ch. 1 - Prob. 15PCh. 1 - Prob. 16PCh. 1 - Prob. 17PCh. 1 - Prob. 18PCh. 1 - Prob. 19PCh. 1 - Prob. 20PCh. 1 - Prob. 21PCh. 1 - Prob. 22PCh. 1 - Prob. 23PCh. 1 - Prob. 24PCh. 1 - Prob. 25PCh. 1 - Prob. 26PCh. 1 - Prob. 27PCh. 1 - Prob. 28PCh. 1 - How many years does it take for an investment of...Ch. 1 - Prob. 30PCh. 1 - Prob. 31PCh. 1 - Prob. 32PCh. 1 - Prob. 33PCh. 1 - Prob. 34PCh. 1 - Prob. 35PCh. 1 - Prob. 36PCh. 1 - Prob. 37PCh. 1 - Prob. 38PCh. 1 - Prob. 39PCh. 1 - Prob. 40PCh. 1 - Prob. 41PCh. 1 - Prob. 42PCh. 1 - Prob. 43PCh. 1 - Prob. 44PCh. 1 - At 9% per year simple interest, 1000 is equivalent...Ch. 1 - Prob. 46PCh. 1 - Prob. 47PCh. 1 - Prob. 48PCh. 1 - Prob. 49PCh. 1 - Prob. 50PCh. 1 - Prob. 51PCh. 1 - Prob. 52PCh. 1 - Prob. 53PCh. 1 - Prob. 54PCh. 1 - Prob. 55PCh. 1 - Prob. 56PCh. 1 - Prob. 57PCh. 1 - Prob. 58PCh. 1 - Prob. 59PCh. 1 - Prob. 60PCh. 1 - Prob. 61PCh. 1 - Prob. 62PCh. 1 - Prob. 63PCh. 1 - Prob. 64PCh. 1 - Prob. 65PCh. 1 - Prob. 66PCh. 1 - Prob. 67PCh. 1 - Prob. 69APQCh. 1 - Prob. 70APQCh. 1 - Prob. 71APQCh. 1 - Prob. 72APQCh. 1 - An investment of 8,000 nine years ago has...Ch. 1 - Prob. 74APQCh. 1 - Prob. 75APQCh. 1 - Prob. 76APQCh. 1 - Prob. 77APQ
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- It is estimated that a copper mine will produce 10,000 tons of ore during the coming year. Production is expected to increase by 5% per year thereafter in each of the following six years. Profit per ton will be $14 for years one to seven. a. Draw a cash flow diagram for this copper mine operation from the company's viewpoint. b. If the company can earn 10% per year on its capital, what is the equivalent of the coppermines cashflow in year seven?arrow_forwardFor the following cash flow diagram, the equation that represents the equivalent at the end of (year 4) at 8% per year interest is: $3,500 $3,500 $3,500 $3,500 1 4 6. Years $24,000 Ā· a. -24,000(F/P,8%,5)+3,500+3,500(P/A,8%, Š°. O b. -24,000(F/P,8%,5)+3,500(P/A,8%,4) O c. -24,000(F/P,8%,4)+3,500(P/A,8%,4) Š Ń. d. -24,000(F/P,8%,4)+3,500+3,500(P/A,8%,arrow_forwardA firm has borrowed $5,000,000 for 5 years at 10% per year compound interest. The firm will make no payments until the loan is due, when it will pay off the interest and principal in one lump sum. What is the total payment? Assume that your answer is in units of $. Only input the numeric value of your calculation.arrow_forward
- How much money would you need to deposit today at 9% annual interest compounded monthly to have $12000 in the account after 6 years? A) $7,007 B) $20,550 $20,125 D) $7,155arrow_forwardAnika wants to invest $200 a month at 4.25%/a compounded monthly for 10 years. a) b) c) What will be the total amount of her investments at the end of 10 years? How much of that money will be interest? If Anika paid $250 per month instead, how much more would she have at the end of 10 years?arrow_forwardIf you borrow $4000 and you have to return it after 3 years , in case of compound interest rate of 2% ,the loan will be at the end of second year is: Select one: a. $4244 b. $4080 c. $4161 d. $4240arrow_forward
- Income from sales of by-products at a local meatpacking plant has been increasing by 10% each year. If the sales in year 1 were $22,000, what is the present worth of sales for years 1 thru 8 at an interest rate of 10% per year? a.$200,000 b.$160,000 c.$220,000 d.$180,000arrow_forwardHow much should be put in an investment with a 10% effective annual rate today to have $10000 in five years?arrow_forward1. An investment company advertises accounts that actually yields 13% interest per year when compounded semiannually. What is the nominal interest rate per year?arrow_forward
- 1.20 At an interest rate of 8% per year, $50,000 one year hence is equivalent to how much now? outflows in his account as follows: Year 0 Amount 10,000 +2,000 2 +2,000 3 -3,000 4 -3,000 The account is expected to earn 7% per year. a. How much would James have in this account at the end of Year 4? b. How much would James have in this account at the end of Year 2? c. What is the equivalent Present Value of this account? d. If James does not deposit or withdraw another dollar from this account, how much would be in this account after Year (10)?arrow_forward2.6) What is the present worth of an expenditure of $25,000 in year 8 if the interest rate is 10% per year?arrow_forward3. What is the Uniform Series Present Worth factor for an interest rate of 5.5% over 20 years?arrow_forward
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