Astronomy Today (9th Edition)
9th Edition
ISBN: 9780134450278
Author: Eric Chaisson, Steve McMillan
Publisher: PEARSON
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Chapter 1, Problem 4MC
To determine
The correct option, from the following options, for the effecton the solar dayas compared with a sidereal day, of the situation when Earth orbited the Sun in 9 months instead of 12.
(a) longer.
(b) shorter.
(c) unchanged.
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Students have asked these similar questions
What is the difference between a sidereal month and a synodic month? Which is longer?
Why?
The earth revolves around the sun in exactly 365 1/4 days which is equivalent to 1 year. To make up for the loss of 1/4 day, the calendar was adjusted so that we have a leap year for every 4 years. If the earth were to speed in its motion slightly so that a year would be completed in exactly 365 days and 6 hours, how often would we need to have a leap year?
The Earth covers about 1° per day in its orbit about the Sun, and the solar
day is slightly longer than the sidereal day. If Earth spun in a retrograde
direction like Venus but it still had the same sidereal period (23 hr 56
min), how long would the solar day be?
The solar day would be
72 hr and
min.
Chapter 1 Solutions
Astronomy Today (9th Edition)
Ch. 1 - Prob. 1DCh. 1 - Prob. 2DCh. 1 - Prob. 3DCh. 1 - Prob. 4DCh. 1 - Prob. 5DCh. 1 - Prob. 6DCh. 1 - Prob. 7DCh. 1 - Prob. 8DCh. 1 - Prob. 9DCh. 1 - Prob. 10D
Ch. 1 - Prob. 11DCh. 1 - Prob. 12DCh. 1 - Prob. 13DCh. 1 - Prob. 14DCh. 1 - Prob. 15DCh. 1 - Prob. 1MCCh. 1 - Prob. 2MCCh. 1 - Prob. 3MCCh. 1 - Prob. 4MCCh. 1 - Prob. 5MCCh. 1 - Prob. 6MCCh. 1 - Prob. 7MCCh. 1 - Prob. 8MCCh. 1 - Prob. 9MCCh. 1 - Prob. 10MCCh. 1 - Prob. 1PCh. 1 - Prob. 2PCh. 1 - Prob. 3PCh. 1 - Prob. 4PCh. 1 - Prob. 5PCh. 1 - Prob. 6PCh. 1 - Prob. 7PCh. 1 - Prob. 9P
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- Consider a planet of radius 10 x 106 m for which the length of a sidereal day is 5 x 104 s. Calculate the speed you would have with respect to the center of the planet, in m/s, if you were at a latitude of 5 degrees north. (Please answer to the fourth decimal place - i.e 14.3225)arrow_forwardThe sidereal day is one rotation of the Earth relative to the The day is longer by 4 minutes. O Sun; stars; solar O Stars; sun; solar O Sun; stars; sidereal O Stars; sun; sidereal while the solar day is one rotation of the Earth relative to thearrow_forwardWhat is the difference between a sidereal month and a synodic revolution for the Earth?arrow_forward
- Right Ascension and Declination is a coordinate system for objects in the sky, and is analogous to longitude and latitude coordinates, respectively, for objects on Earth. Right ascension (RA) coordinates are given in hours (h), minutes (m), and seconds (s). Declination (DEC) coordinates are given in degrees (°), arcminutes ('), and arcseconds ("). Sirius is the brightest star in the night sky. Its RA and DEC coordinates are 6h 45 m 7.96 s and -16° 44' 78.6". Using unit conversion, find the RA coordinate only in hours and round the coordinate to 5 significant figures.arrow_forwardTonight you see a waning crescent in the night sky. A few (n) days later, the night is once again clear and you see a waning crescent. How many degrees did the Moon advance in its orbit during this time frame?arrow_forwardThe planet Earth has a semi-major axis of a = 1.00 AU and an orbital period of P= 1 sidereal year = 365.25 days = 3.156 x 10^7 s. Compute the orbital periods of bodies orbiting the Sun with each of the following semi-major axes. a) a = 0.1 AU b) a = 10 AU c) a = 100 AU d) a = 1000 AU e) a = 10,000 AU 1 AU = 1.496 x 10^8 km = 1.496 x 10^11 m = 1.496 x 10^13 cm. GM(sun) = 1.327 x 10^20 m^3/s^2 = (Newton's Constant) x (Mass of Sun) %3D %3Darrow_forward
- An arcminute is what fraction of a degree?arrow_forwarda. Describe the concept of "sphere of influence" and how it is estimated. b. Calculate the SOI for the Moon relative to the Earth. c. Would a single lone star have a computed sphere of influence, as defined in this class, which could be calculated? If no, why not? If yes, how would you do it?arrow_forwardIf city is located in 2.8° north latitude and 46.0° east longitude. From there, you want to fly to a city in 7° north latitude and 52° east longitude. How much is the arc length of the big circle at 11000 m when the earth's radius is 6370 km? The arc length is 14223 km. Give your answer rounded to one kilmetre. Your last answer was interpreted as follows: 14223 XAnswer is incorrect. Keep centre of Earth as origin and define vectors to cities. Try again.arrow_forward
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