The pump whose characteristic curves are shown in Figure 11.5.13bis used to pump water from reservoir A to reservoir B through 1000 ft of 8.00-in diameter pipe whose friction factor is 0.017 (as shoue Figure 11.5.14). Use the entrance loss coefficient of K. = 0.5 and gate valve loss of KGy=0.2. (o) win flow rate does it pump? (b) What input power is required to drive the pump?

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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The pump whose characteristic curves are shown in Figure 11.5.136 is used to pump water from resenve:
to reservoir B through 1000 ft of 8.00-in diameter pipe whose friction factor is 0.017 (as shor A
Figure 11.5.14). Use the entrance loss coefficient of Ke= 0.5 and gate valve loss of KGv=0.2. (a) Wh
flow rate does it pump? (b) What input power is required to drive the pump?
EXAMPLE 11.5.2
Elev. 50.0'
Gate valve
оpen
Elev. 30.0'
Elev. 20.0'
Pump
Gate valve
оpen
Elev. 0.0'
1000 ft
A
Figure 11.5.14 Example 11.5.2 pipe system.
Transcribed Image Text:The pump whose characteristic curves are shown in Figure 11.5.136 is used to pump water from resenve: to reservoir B through 1000 ft of 8.00-in diameter pipe whose friction factor is 0.017 (as shor A Figure 11.5.14). Use the entrance loss coefficient of Ke= 0.5 and gate valve loss of KGv=0.2. (a) Wh flow rate does it pump? (b) What input power is required to drive the pump? EXAMPLE 11.5.2 Elev. 50.0' Gate valve оpen Elev. 30.0' Elev. 20.0' Pump Gate valve оpen Elev. 0.0' 1000 ft A Figure 11.5.14 Example 11.5.2 pipe system.
Single-stage pump
Impeller diameter = 12.0 in
Operated at N = 1800 RPM
120
-System curve
example 12.5.2
Неad
System curve
example 12.5.1
100
100
Q = 4.4 cfs
H = 98 ft
E = 83%
80
80
Q = 5.7 cfs
H = 82.3 ft
E = 74%
60
60
Efficiency
40
40
1
2
4
Discharge Q (ft/sec)
(b)
Figure 11.5.13 (a) Figure for example 11.5.1. (b) Characteristic curves for examples 11.5.1 and 11.5.2.
Efficiency (%)
20
CO
20
Head (ft)
Transcribed Image Text:Single-stage pump Impeller diameter = 12.0 in Operated at N = 1800 RPM 120 -System curve example 12.5.2 Неad System curve example 12.5.1 100 100 Q = 4.4 cfs H = 98 ft E = 83% 80 80 Q = 5.7 cfs H = 82.3 ft E = 74% 60 60 Efficiency 40 40 1 2 4 Discharge Q (ft/sec) (b) Figure 11.5.13 (a) Figure for example 11.5.1. (b) Characteristic curves for examples 11.5.1 and 11.5.2. Efficiency (%) 20 CO 20 Head (ft)
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