Plz solve correctly The physical length of the ruler as a fraction of the circumference of the big circle is the same as the angular length of the ruler as a fraction of360°:lengthcircumference=0360°Since circumference = 2π X radius and the radius of the big circle is the distance to the ruler/planet:length=2π × distance0360°Solving for the physical length of the ruler yields:Ꮎlength = 2 × distance x360°This general equation can be used along with the distance to your planet to work out a conversion factor that will convert your moon's orbitalsemi-major axis from arcseconds to AU; i.e. in the above equation, we will setlength= a [AU],0= a["],and calculateconversion factor ["/AU] :=2πT360°1°3600"× distance.conversion factor = type your answer..."/AU.Note: in order for units to work out, we had to multiply by the number of degrees per arcsecond (") in the above formula.

We have to find the conversion factor

The physical length of the ruler as a fraction of the circumference of the big circle is the same as the angular length of the ruler as a fraction of 360°: length circumference 0 360° Since circumference = 2π X radius and the radius of the big circle is the distance to the ruler/planet: length 2π × distance Ꮎ 360° Solving for the physical length of the ruler yields: length = 2 × distance x 0 360° This general equation can be used along with the distance to your planet to work out a conversion factor that will convert your moon's orbital semi-major axis from arcseconds to AU; i.e. in the above equation, we will set length = a [AU], 0=a"], and calculate conversion factor ["/AU] = 2πT 360° 1° 3600" × distance. conversion factor = type your answer... "/AU. Note: in order for units to work out, we had to multiply by the number of degrees per arcsecond (") in the above formula.

The physical length of the ruler as a fraction of the circumference of the big circle is the same as the angular length of the ruler as a fraction of 360°: length circumference 0 360° Since circumference = 2π X radius and the radius of the big circle is the distance to the ruler/planet: length 2π × distance Ꮎ 360° Solving for the physical length of the ruler yields: length = 2 × distance x 0 360° This general equation can be used along with the distance to your planet to work out a conversion factor that will convert your moon's orbital semi-major axis from arcseconds to AU; i.e. in the above equation, we will set length = a [AU], 0=a"], and calculate conversion factor ["/AU] = 2πT 360° 1° 3600" × distance. conversion factor = type your answer... "/AU. Note: in order for units to work out, we had to multiply by the number of degrees per arcsecond (") in the above formula.