The following functions are all intended to check whether a string contains any lowercase letters, but at least some of them are wrong. For each function, describe what the function actually does (assuming that the parameter is a string)
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Ex. 8.4) The following functions are all intended to check whether a string contains any lowercase letters, but at least some of them are wrong. For each function, describe what the function actually does (assuming that the parameter is a string).
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- function performTask () { var valuel; valuel - document.getElementById ("FirstBox").value; if (valuel == "Yes") { document.getElementById ("paragraphl").innerHTML = "Agreed"; ) else if (valuel =- "No") { document.getElementById ("paragraphl").innerHTML = "Sorry"; ) else ( alert ("Error") Describe the purpose of the following JavaScript statements from the function performTask (). i. alert("Error"), ii. value1 = document.getElementByld("FirstBox").value; iii. document.getElementByld("paragraph1").innerHTML = "Agreed";Cyclops numbersdef is_cyclops(n):A nonnegative integer is said to be a cyclops number if it consists of an odd number of digits so that the middle (more poetically, the “eye”) digit is a zero, and all other digits of that number are nonzero. This function should determine whether its parameter integer n is a cyclops number, and return either True or False accordingly n Expected result 0 True 101 True 98053 True 777888999 False 1056 False 675409820 FalseIn Python, grades_dict = {'Wally': [87,96,70], 'Eva': [100,87,90], 'Sam': [94,77,90], 'Katie': [100,81,82], 'Bob': [83,65,85]} Write your own describe function that produces the same 8 statistical results, for each one of the columns, that the built-in describe() function does. Note 1: Use the sample standard deviation formula (that is, the denominator is: N-1) Note 2: Your algorithm should work for any number of columns not just for 5 Note 3: You can use the np.percentile() for the 25% and 75% percentile as well as the sort() built-in functions
- def calculate_growth_cycle(plant_name): if(plant_name == "strawberry"): print("### The life cycle of a strawberry ###\nA seed takes 110 days to reach maturity.") elif(plant_name == "cucumber"): print("### The life cycle of a cucumber ###\nA seed takes 76 days to reach maturity.") elif(plant_name == "potato"): print("### The life cycle of a potato ###\nA seed takes 120 days to reach maturity.") else: print('Your plant is available, please try "strawberry", "cucumber" or "potato"') Plants Growth Cycle Learning Objectives In this lab, you will practice: Defining a function to match the given specifications Calling the function in your program Using if statements (can combine them with dictionaries) Instructions For every plant, there is a growth cycle. The number of days that it takes starting from being a seed and ending in being a fruit is what is called the growth cycle. Write a function that takes a plant's name as an argument and…Integer userValue is read from input. Assume userValue is greater than 1000 and less than 99999. Assign tensDigit with userValue's tens place value. Ex: If the input is 15876, then the output is: The value in the tens place is: 7 2 3 public class ValueFinder { 4 5 6 7 8 9 10 11 12 13 GHE 14 15 16} public static void main(String[] args) { new Scanner(System.in); } Scanner scnr int userValue; int tensDigit; int tempVal; userValue = scnr.nextInt(); Your code goes here */ 11 System.out.println("The value in the tens place is: + tensDigit);In Python, grades_dict = {'Wally': [87,96,70], 'Eva': [100,87,90], 'Sam': [94,77,90], 'Katie': [100,81,82], 'Bob': [83, 65, 85]} write your own describe function that produces thesame 8 statistical results, for each one of the columns, that the built-in describe() function does.Note 1: Use the sample standard deviation formula (that is, the denominator is: N-1)Note 2: Your algorithm should work for any number of columns not just for 5Note 3: You can use the np.percentile() for the 25% and 75% percentile as well as the sort()built-in functions
- Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eaxhi can you explain these functions to me def encode(message):encode_dict = {'A': '.-', 'B': '-...', 'C': '-.-.','D': '-..', 'E': '.', 'F': '..-.','G': '--.', 'H': '....', 'I': '..','J': '.---', 'K': '-.-', 'L': '.-..','M': '--', 'N': '-.', 'O': '---','P': '.--.', 'Q': '--.-', 'R': '.-.','S': '...', 'T': '-', 'U': '..-','V': '...-', 'W': '.--', 'X': '-..-','Y': '-.--', 'Z': '--..', ' ': '.....'}encoded = ' '.join(encode_dict[i] for i in message.upper())return encodeddef decode(message):encode_dict = {'A': '.-', 'B': '-...', 'C': '-.-.','D': '-..', 'E': '.', 'F': '..-.','G': '--.', 'H': '....', 'I': '..','J': '.---', 'K': '-.-', 'L': '.-..','M': '--', 'N': '-.', 'O': '---','P': '.--.', 'Q': '--.-', 'R': '.-.','S': '...', 'T': '-', 'U': '..-','V': '...-', 'W': '.--', 'X': '-..-','Y': '-.--', 'Z': '--..', ' ': '.....'}decode_dict = {v: k for k, v in encode_dict.items()}decoded = ''.join(decode_dict[i] for i in message.split())return decodeddef process_lines(filename, mode):with…PLEASE HELP ME! ? Maximize and use alternative method to this code! package com.btech.pf101; import java.io.bufferedreader; import java.io.inputstreamreader; import java.util.calendar; import java.util.date; public class pawnshopcode { private static final bufferedreader br = new bufferedreader(new inputstreamreader(system.in)); private static string name; private static int age; private static string address; private static string contactno; private static int itemtype; private static string itemtypename; private static final int itemtype_gagdet = 1; private static final int itemtype_jewelry = 2; private static final int itemtype_musicinstrument = 3; private static final int itemtype_homeequipment = 4; private static final int itemtype_landtitle = 5; private static string itemdescription; private static int periodtype; private static string periodtypename; private static final int periodtype_days = 1; private…
- write also in c# Write an application that displays the result of dividing two numbers and displays anyremainder. The main() method prompts the user for values and sends them to the dividingmethod; the dividing method performs the calculation and displays the results. Save theapplication as Divide.csA class object can encapsulate more than one [answer].Bulgarian solitaire def bulgarian_solitaire(piles, k): You are given a row of piles of pebbles, all identical, and a positive integer k so that the total number of pebbles in these piles equals k*(k+1)//2, the arithmetic sum formula that equals the sum of positive integers from 1 to k. Almost as if intended as a metaphor for the bleak daily life behind the Iron Curtain, all pebbles are identical and you don't have any choice in your moves. Each move picks up one pebble from each pile (even if doing so makes that pile vanish), and creates a new pile from the resulting handful. For example, starting with[7, 4, 2, 1, 1], the first move turns this into [6, 3, 1, 5]. The next move turns that into [5, 2, 4, 4], which then turns into the five-pile configuration [4, 1, 3, 3, 4], and so on. This function should count how many moves are needed to convert the given initial piles into the goal state where each number from 1 to k appears as the size of exactly one pile, and return that count. These…