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Genetics Q2
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- In mice, the green eye gene (g) are on the same chromosome as the long tail gene (1). The dominant alleles are brown eyes (G) and short tail (L) You take a mouse that has green eyes and a short tail and cross it to one that has brown eyes and a long tail. (These mice are homozygous for all traits) Hint the first mouse can be written gl/gL and the second one GI/GI 1. Draw what the chromosomes of an offspring of this cross will look like at prophase 1 of meiosis before crossing over has taken place. Indicate the alleles on your image.In cattle, the gene for hornless (H) is dominant to the gene for horned (h), the gene for black (B) is dominant to that of red (b), and the gene for white face, or Hereford spotting, (S) is dominant to that for solid color (s). A cow (female) that is heterozygous for all traits is inseminated by a bull (male) of the genotype bbhhSs. What is the probability of obtaining a calf that is a black, hornless bull with Hereford spotting?The pedigree concerns eye phenotypes in Tribolium beetles. The solid symbols represent black eyes, the open symbols represent brown eyes, and the cross symbols (X) represent the "eyeless" phenotype, in which eyes are totally absent. Assume that these three phenotypes are the result of three alleles of a single gene, E, where E' is black, g? is brown, and is eyeless. Assign a genotype to each individual in generation II. 1 2 3 II 4 7 8 II 9 10 | 11 12 IV 13 Grifths, et al, Introduction to Genetic Analysis 12e © 2020 Macmillan Leaning Answer Bank E'? E'E What is the mode of inheritance of the eyeless phenotype? autosomal dominant X-linked recessive X-linked dominant autosomal recessive CO
- A true breeding male fly with eosin eyes (CCXw-eY) is crossed to a red-eyed female who is heterozygous for both the cream (C) and eosin eyes (Xw-e) allele. What will be the phenotypic ratio of their offspring?In Drosophila the genes forked bristles (f and f+) and vermilion eyes (v and v+) are ~24 m.u. apart on the X chromosome. From a cross of f v / f+ v+ females with f v / y males, what % of the progeny do you expect to have the f+ v+ phenotypes? (Don’t let the X chromosome throw you off – this question is essentially asking what % of the female’s gametes will be f+ v+).Another recessive mutation in Drosophila, ebony (e), is on anautosome (chromosome 3) and causes darkening of the bodycompared with wild-type flies. What phenotypic F1 and F2 maleand female ratios will result if a scalloped-winged female withnormal body color is crossed with a normal-winged ebony male?Work this problem by both the Punnett square method and theforked-line method.
- In flies, long wings (W) are dominant to short wings (w). Two homozygous recessive flies are crossed.The process known as (FILL IN THE BLANK) of the (FILL IN THE BLANK) chromosome in some female cats results in a calico In Rare cases, males can express the calico fur pattern. what would the be genetic explanation for this?With regard to scurs in cattle ( a sex influenced trait) a cow with no scurs whose mother had scurs had offspring with a bull with scurs whose father had no scurs. What are their probabilities of having the following combinations?a. their first offspring will not have scursb. their first offspring will be a male with no scursc. their first three offspring will be females with no scurs step by step explain in details please!!!!
- A recessive maternal effect mutant in zebrafish, called ichabod, results in embryos lacking heads that are non-viable. You have been instructed to identify females that are homozygous for the ichabod mutant allele. At your disposal are a tank of wild-type fish (males and females), a tank of male and female parental fish that are all heterozygous for the ichabod mutant allele (ichabod/+), and a tank of F1 fish derived from a cross between a heterozygous male and heterozygous female (ichabod/+). Which of the following would be a way to identify females that are homozygous mutant, i.e. ichabod/ichabod? Select all answers that would work.You are studying tail length in a species of mice, where some mice have long tails and some have short tails.Preliminary results show that long tail is dominant, but you think the trait may be X-linked. Give the expectedoffspring phenotypic ratio for each cross if the trait is X- linked or if it is autosomal and answer the question atthe end. Make sure your phenotypic ratio is labeled with the complete phenotype (all relevant details). Cross #1: true-breeding long-tailed male x true-breeding short tailed female• Expectation if X-linked?• Expectation if autosomal?Cross #2: true-breeding long-tailed female x true-breeding short tailed male• Expectation if X-linked?• Expectation if autosomal?Compare the four results listed above. Briefly, why is a reciprocal cross is necessary to determine X (or Z)linkage?IN DROSOPHILA, AN X-LINKED RECESSIVE MUTATION, Xm CAUSES MINIATURE WINGS. LIST THE F₂ PHENOTYPIC RATIOS IF: A MINIATURE-WINGED FEMALE IS CROSSED WITH A NORMAL MALE AND A MINIATURE-WINGED MALE IS ● ● CROSSED WITH A NORMAL FEMALE. WHAT WOULD THE PHENOTYPIC RATIO FROM (A) BE IF THE MINIATURE- WINGED GENE WERE AUTOSOMAL? ASSUME IN ALL CASES THAT THE P1 INDIVIDUALS ARE TRUE-BREEDING.