So if i had page size 8k (which is 2^13=8k) & had a virtual address length of 32 bits and did 32 - 13, would that give the vpn or offset? <<<<<<< please specify
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So if i had page size 8k (which is 2^13=8k) & had a virtual address length of 32 bits and did 32 - 13, would that give the vpn or offset? <<<<<<< please specify
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- The memory location at address of 0X003FB01 contains 1-byte memory variable J (0010_0001), and the memory location at the address of 0X003FB02 contains 1-byte memory variable K (0001 0010), see figure below. There is a 2-byte variable M which hold binary information M (1110 0101 0000 1i11). What is the address in hexadecimal format for 2-byte memory variable M, following little Endian computer? 7 Address in Data in Hex. Format Hex. Format 0X003FBF04 1110 0101 M OX003FBF03 0000 1111 0X003FBF02 0001 0010 0X003FBF01 0010 0001 J Its address in hexadecimal is 0X003FBF02. а. Its address in hexadecimal is 0×003FBF03. O b. Its address in hexadecimal is 0X003FBF04. Its address in hexadecimal is 0×003FBF01. d.Suppose that DS=1000H, SS= 2000H, CS=3000H, ES=4000H, BP=FFH, BX=FFFFH and DI=5H.i. Which memory locations are addressed by: MOV DL, [BP]?ii. Which memory locations are addressed by: MOV EAX, [BX+DI]?Suppose a malloc implementation returns 8-byte aligned addresses and uses an implicit free list. Blocks have a 32-bit header, where the low-order bit of the header is used to indicate whether the block is allocated (1) or free (0). Furthermore, the block size (which includes the header, payload, and any necessary padding) is rounded up to the nearest multiple of 8, and this size (in bytes) is stored in the header. Assume any padding must be at the end of the block. If we call to malloc(1), what block size will be allocated, in bytes?
- Suppose we have a computer system with 44-bit logical addresses, page size of 64KiB, and 4 bytes per page table entry. b. Suppose we use two-level paging and arrange for all page tables to fit into a single page frame. How will the bits of the address be divided up? (show your work) c. Suppose we have a program with a 4GiB address space. Counting the program and all page tables, using the two-level page table scheme from the previous question, how much memory, in number of page frames, is used? (show your work)For this assignment, you are to write a MIPS assembly language program using the MARS IDE and assume a system has 31-bit virtual memory address (so no worry about negative numbers) with a 4-KB page size (4096 bytes). Write a MIPS program that accepts an integer input that represents a virtual address and outputs the page number and offset for the given address in decimal. The output should look like: The address 19986 is in: Page number = 4 Offset = 3602 Check to make certain your program works. You can use the output from 19986 given above as a test, but I will use other numbers to test it. Submit the MIPS assembly language code and a screenshot showing a test run.Suppose that you have a UNIX file system where the disk block size is 4096 bytes. Disk addresses and file block pointers take 32 bits (4 bytes), and the i-node contains 12 direct pointers, one single-indirect pointer and one double-indirect pointer. Assume an index block is the same size as a data block (both 4096 Bytes). If there is a file having 50,000 bytes of data and it is never been accessed, we only assume the file's i-node is in memory, but none of the rest of the file. If the user process wants to access to read the entire file into the memory, how many I/O operations would be needed? O a. 15 O b. 12 O c. 14 O d. 13
- Suppose a computer system uses 16-bit addresses for both its virtual and physical addresses. In addition, assume each page (and frame) has size 256 bytes. 8 bits are used for offset, 8 bits are used for page # and the max number of pages a process can have is 256. e. Translate the following virtual addresses to physical addresses, and show how you obtain the answers. (Hint: You do not need to convert hexadecimal numbers to decimal ones.) 0x0389 0xDF78 0x0245 0x8012 f) Now, suppose that the OS uses a two-level page table. Draw the page table. (Assume that frames 7 through 221 are free, so you can allocate space for the page table there.) In addition, suppose that the page-table directory storage comprises a whole number of consecutive full frames. (For examples: if the directory entry is 2 bytes, the entry’s storage comprises 1 frame; if the directory entry is 260 bytes, the entry’s storage comprises 2 consecutive frames.) g)What is the size of the two-level page table…Suppose, binary representations of random pattern are stored in AL and BL register of microprocessor 8086. Write a generalized ASM code to check the binary representation stored in AL and BL for adjacent numbers. If the binary representations are adjacent to each other, store 01 H in DL register, otherwise store 00 H. For instance, AL = 02 H and BL = 06 H will store 01 H in DL register. Adjacent: If two representations are one-bit change away from each other, they will be classified as adjacent to each other.Consider an 8-pin general purpose input/output port memory mapped to address adr_gpio_a . What does the following code do? ldr re, adr_gpio_a ldr r1, =0xfb str r1, [r®, #4] ldr r2, [r®] A. Sets pin 2 as input, the remaining pins (0,1, 3..7) as output, then reads from pin 2. B. Sets pin 2 as output, the remaining pins (0,1, 3..7) as input, then reads from every pin except pin 2. C. Writes the value Oxfb to the memory cell adjacent to the i/o port, then reads input from all of the pins in the port. D. Reads the input from the i/o port and applies a bit mask of Oxfb.
- Consider the string of data #. The ASCII value of data # is 23 H which has to be moved from source memory to destination memory. Calculate the 20 bit PA of source memory and destination memory. Assume CS=2000 H, DS=5000 H, SS=6000 H, ES=8000 H. BX=1234 H, BP=2434 H, SP=3500 H, SI=4000 H, DI=5276 H, IP=D1245 H.Q1.G 1. 2. 3. Consider a 48-bit virtual address; the page offset field is 14 bits. Answer the following: The number of bits in the virtual page number field is: The size of the memory page in bytes is: The number of entries in the page table is: If the virtual address is (0000 1ABD)16, use the Page Table below to find the complete physical address: The physical address is: ( index V 1 0 2 1 10 SAWN 3 4 5 110 Physical page number in hexadecimal 16 A B C D E FIn a computer with a 32-bit data-bus, how many 4-bit wide memory components are used? the answer to this part is 32/4 = 8 components (2-bit wide) I need the answer to part two, please If the size of each 4-bit memory component is 4 x n cells where n = 1G (i.e., 4 x n uniquely addressable locations—n : row, 4 : 2 column/width), what is the total capacity of the memory system? Show your answer in power of 2. (hint: 1000 ~ 210)