Sketch the reaction mechanism (including the final product) corresponding to the following description of; 2-bromo-4-methylpentane is being reacted with sodium cyanide in diethyl ether (set up the reaction – next you will get a description of the mechanism to draw). A lone pair of electrons from the cyanide attacks the carbon bonded to bromine, forming a new carbon-carbon bond. At the same time, the carbon-bromine bond breaks with the electron pair from the carbon-bromine bond moving toward the bromine to form a bromide ion. This will form the product 2,4-dimethylpentanenitrile and sodium bromide.
Sketch the reaction mechanism (including the final product) corresponding to the following description of; 2-bromo-4-methylpentane is being reacted with sodium cyanide in diethyl ether (set up the reaction – next you will get a description of the mechanism to draw). A lone pair of electrons from the cyanide attacks the carbon bonded to bromine, forming a new carbon-carbon bond. At the same time, the carbon-bromine bond breaks with the electron pair from the carbon-bromine bond moving toward the bromine to form a bromide ion. This will form the product 2,4-dimethylpentanenitrile and sodium bromide.
Chapter1: Lewis Structures
Section: Chapter Questions
Problem 73EQ
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Sketch the reaction mechanism (including the final product) corresponding to the following description of;
2-bromo-4-methylpentane is being reacted with sodium cyanide in diethyl ether (set up the reaction – next you will get a description of the mechanism to draw).
A lone pair of electrons from the cyanide attacks the carbon bonded to bromine, forming a new carbon-carbon bond. At the same time, the carbon-bromine bond breaks with the electron pair from the carbon-bromine bond moving toward the bromine to form a bromide ion. This will form the product 2,4-dimethylpentanenitrile and sodium bromide.
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