This is the general mechanism of nucleophilic addition of aldehydes and ketones. H–Nu Nu: Nu-C- Nu-C-ö-H + Nu: Represent the mechanism with the energy diagram showing the transition states and the intermediate
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- CH3 CH3 Br- Br2 .CH3 CH2Cl2 CH3 H3C H3C Br Electrophilic addition of bromine, Brɔ, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH,Cl,. In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions CH3 CH3 CH3 CH3 H3C H3C :Br: :Br:For each reaction in question 20, sketch a reaction coordinate energy diagram indicating the starting materials, transition states and any intermediates, if present, in the reaction. Don't worry about the absolute energy of starting materials and products but you can assume that the product is more stable than the starting materials.H3C CH3 H3C NA C→XT Br Br₂ CH₂Cl₂ H3C Electrophilic addition of bromine, Br₂, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH₂Cl₂. CH3 Br In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions Br CH3 H3C CH3
- In the elimination reaction of an alkyl halide, what happens to the leaving group and what’s the product?Vhich of the following statements is incorrect? * 3 p Hammond-Leffler Postulate states that there is a strong resemblance between the transition state and the product in an endothermic reaction. Hammond-Leffler Postulate states that there is a strong resemblance between the transition state and the reactants in an exothermic reaction. The presence of more electron-donating alkyl groups ineffectively delocalize the positive charge in an organic molecule, making it less stable. The dehydration of primary alcohol proceeds via E2 mechanism. All of the abovęExplain Allylic Carbocations in Biological Reactions ?
- What about the second step in the electrophilic addition of HCl to an alkene-the reaction of chloride ion with the carbocation intermediate? Is this step exergonic or endergonic? Does the transition state for this second step resemble the reactant (carbocation) or the product (alkyl chloride)? Make a rough diagram of what the transition state may look like?What is the slow, rate-determining step, in the acid-catalyzed dehydration of 2- butanol? Loss of a b-hydrogen from the carbocation to form an alkene. Protonation of the alcohol to form an oxonium ion. Loss of water from the oxonium ion to form a carbocation. The simultaneous loss of a B-hydrogen and water from the oxonium ion.10. Draw an energy diagram for the addition of HBr to 1-pentene. Let one curve on your diagram show the formation of 1-bromopentane product and another curve on the same diagram show the formation of 2- bromopentane product. Draw and label the positions for all reactants, intermediates, and products. Which curve has the higher-energy carbocation intermediate? Which curve has the higher-energy first transition state?
- 2-chloropropane is a major product of the reaction of chlorine with propane under ultraviolet light. Write the mechanism for this reaction including the initiation step and the two propagation steps.The rate of hydration of 2-butene and 2-methylpropene differ by several orders of magnitude. Whcih alkene is more rapidly hydrated and why?H 0=f=0 OH о-н Н ?