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Reduction Half-reaction Half-cell E (V) Oxidizing Agent F(g) + 2e HO, (aq) + 2 H*(aq) + 2 e" PhOs) + so; (aq) + 4 H"(aq) + 2e – PbSO,(s) + 2 H,O(e) Au"(aq) + 3e Reducing Agent - 2F(aq) 2 HO() F(g)|F"(aq)|Pt H,O(aq). H" (aq), H,0()|PI +287 +1.763 ) PBO(s)|So (aq). H"(aq)|PhSO,(s)|Pb +1.690 - Au(s) - Mn"(aq) + 4 H,O() 2 Cr*(aq) + 7 H,0(0) 2 CI (aq) 2 HO() Au"(ag)| Au(s) Mno, (aq), H*(aq). Mn"(aq)|Pt Cr,0"(aq). H*(aq). c*(aq>|Pt +1.52 MnO, (aq) + 8 H (aq) + 5e CrO (aq) +14 H*(aq) + 6e C(g) + 2e O,ig) +4 H"(aq) + 4e Br() + 2e" NO5 (aq) + 4 H*(aq) + 3e OCI"(aq) + H,O(() + 2e Hg"(aq) + 2e Ag"(ag) + e" Hg (aq) + 2e Fe"(ag) +e 1,(s) + 2e Og) + 2 H,O() + 4e Cu*(aq) + 2e Sn* (aq) + 2e 2 H*(aq) + 2e Sn" (aq) + 2e Ni"(aq) + 2e" PhSO,(s) + 2 e Cd* (aq) + 2e Fe"(aq) + 2e Zn*(aq) + 2 e" 2 H,O() + 2e Al"(aq) + 3e" Mg"(aq) + 2e" Na"(aq) +e K*iaa) +e +1.51 +1.36 +1.358 +1.229 2 Br (aq) NO(g) +2 H,0(O Cr"(aq) + 2 OH"(aq) - Hg() - Agis) 2 Hg(€) Fe" (aq) BrgO|Br"(aq)|P NO, (aq), H"(ag)|NO(g)|P Ocr (aq), C"(aq). OH"(aq|P Hg" (ap|Hg(6) Ag (aq)|Ag(s) Hg3 (aq)|Hg (C) Fe" (aq), Fe"(aq)|PI +1.066 +0.96 +0.89 +0.8535 +0.7991 +0.7960 +0.771 +0.535 21(aq) 4 OH (aq) - Cus) Sn*(aq) H(g) +0.401 ld|(bw)_HO|(o Cu“(aq)|Cu(s) Sn*(aq), Sa*(ag|PI +0.340 +0.15 Sn"(aq)|Sn(s) Ni" (aq)|Ni(s) PhSO,(s)|So;"(aq)|Pb(s) Ca*(aq|Cd(s) Fe" (aq)|Fets) Za"(aq)|Zn(s) H,O(), OH" (aq|H;(g)|Pt Al* (aq)|Al(s) Mg*"(aq)|Mg (s) Na*(aq|Na(s) Sn(s) -0.1375 - Ni(s) Pb(s) + So;"(aq) - Cd(s) - Fe(s) -0.25 -0.3505 -0.403 -0.44 Zn(s) -0.763 H(g) + 2 OH"(aq) -0.8277 Al (s) -1.676 Mg(s) -2.356 Na(s) -2.714 Kisi -2.925 1. Can Aluminium solid reduce Au3+? Yes or No. Please simply explain your answer. 2. According to above given E0 values, which one is the strongest reducing agent? 3. According to above table can K+ be reducded with any reducing agent? if your answer is Yes, provide what you can use to reduce K+ into K(s). If your answer is No, explain why.

Reduction Half-reaction Half-cell E (V) Oxidizing Agent F(g) + 2e HO, (aq) + 2 H*(aq) + 2 e" PhOs) + so; (aq) + 4 H"(aq) + 2e – PbSO,(s) + 2 H,O(e) Au"(aq) + 3e Reducing Agent - 2F(aq) 2 HO() F(g)|F"(aq)|Pt H,O(aq). H" (aq), H,0()|PI +287 +1.763 ) PBO(s)|So (aq). H"(aq)|PhSO,(s)|Pb +1.690 - Au(s) - Mn"(aq) + 4 H,O() 2 Cr*(aq) + 7 H,0(0) 2 CI (aq) 2 HO() Au"(ag)| Au(s) Mno, (aq), H*(aq). Mn"(aq)|Pt Cr,0"(aq). H*(aq). c*(aq>|Pt +1.52 MnO, (aq) + 8 H (aq) + 5e CrO (aq) +14 H*(aq) + 6e C(g) + 2e O,ig) +4 H"(aq) + 4e Br() + 2e" NO5 (aq) + 4 H*(aq) + 3e OCI"(aq) + H,O(() + 2e Hg"(aq) + 2e Ag"(ag) + e" Hg (aq) + 2e Fe"(ag) +e 1,(s) + 2e Og) + 2 H,O() + 4e Cu*(aq) + 2e Sn* (aq) + 2e 2 H*(aq) + 2e Sn" (aq) + 2e Ni"(aq) + 2e" PhSO,(s) + 2 e Cd* (aq) + 2e Fe"(aq) + 2e Zn*(aq) + 2 e" 2 H,O() + 2e Al"(aq) + 3e" Mg"(aq) + 2e" Na"(aq) +e K*iaa) +e +1.51 +1.36 +1.358 +1.229 2 Br (aq) NO(g) +2 H,0(O Cr"(aq) + 2 OH"(aq) - Hg() - Agis) 2 Hg(€) Fe" (aq) BrgO|Br"(aq)|P NO, (aq), H"(ag)|NO(g)|P Ocr (aq), C"(aq). OH"(aq|P Hg" (ap|Hg(6) Ag (aq)|Ag(s) Hg3 (aq)|Hg (C) Fe" (aq), Fe"(aq)|PI +1.066 +0.96 +0.89 +0.8535 +0.7991 +0.7960 +0.771 +0.535 21(aq) 4 OH (aq) - Cus) Sn*(aq) H(g) +0.401 ld|(bw)_HO|(o Cu“(aq)|Cu(s) Sn*(aq), Sa*(ag|PI +0.340 +0.15 Sn"(aq)|Sn(s) Ni" (aq)|Ni(s) PhSO,(s)|So;"(aq)|Pb(s) Ca*(aq|Cd(s) Fe" (aq)|Fets) Za"(aq)|Zn(s) H,O(), OH" (aq|H;(g)|Pt Al* (aq)|Al(s) Mg*"(aq)|Mg (s) Na*(aq|Na(s) Sn(s) -0.1375 - Ni(s) Pb(s) + So;"(aq) - Cd(s) - Fe(s) -0.25 -0.3505 -0.403 -0.44 Zn(s) -0.763 H(g) + 2 OH"(aq) -0.8277 Al (s) -1.676 Mg(s) -2.356 Na(s) -2.714 Kisi -2.925 1. Can Aluminium solid reduce Au3+? Yes or No. Please simply explain your answer. 2. According to above given E0 values, which one is the strongest reducing agent? 3. According to above table can K+ be reducded with any reducing agent? if your answer is Yes, provide what you can use to reduce K+ into K(s). If your answer is No, explain why.

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter17: Electrochemistry And Its Applications
Section: Chapter Questions
Problem 38QRT
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Standard Half-cell Potentials in Aqueous Solution at 25 °C* E* (V) Reduction Half-reaction Half-cell Reducing Agent - 2F"(aq) 2 H,O() PbSO,(s) + 2 H,Oo(e) Oxidizing Agent F(g) + 2e HO;(aq) + 2 H*(aq) + 2 e" PbO,(s) + So;"(aq) + 4 H"(aq) + 2e" Au"(aq) + 3e" Mno, (aq) + 8 H"(aq) + 5e Cr.O"(aq) +14 H*(aq) + 6e Cl(g) + 2e O,g) +4 H*(aq) + 4e Br() + 2e" NO, (aq) + 4 H*(aq) + 3e OCI"(aq) + H,O() + 2e Hg"(aq) + 2e Ag*(aq) +e Hg (aq) + 2e Fe"(aq) +e 1,(s) + 2e O,(g) + 2 H,O(O + 4e Cu*(aq) + 2 e" Sn* (aq) + 2e 2 H*(aq) + 2e Sn" (aq) + 2 e Ni"(aq) + 2e" PhSo,(s) + 2 e- Ca*(aq) + 2 e Fe"(aq) + 2 e Zn*(aq) + 2 e +2.87 d|(be).|(31 H,O,(aq), H"(aq), H,O(e)|P PBO,(s)|So; (aq). H"(aq)|PbSO,(s)|Pb Au"(aq)|Au(s) MnO, (aq), H*(aq). Mn*(aq>|Pt Cr,0;"(aq). H*(aq). Cr"(aq)|Pt Cl(g)|CI"(aq)|Pt 0,()|H" (ag) |Pt Brg|Br"(aq)|Pt NO, (aq). H*(aq)|NO(g)|P OcI (aq), C"(aq). OH"(aq|Pt Hg" (ag)| Hg (6) Ag (aq)|Ag(s) Hg3"(aq)|Hg(() Fe" (aq), Fe*(aq)|Pt 1,(s)|1"(aq)|P +1.763 +1.690 Au(s) +1.52 Mn"(aq) + 4 H,O(e) 2 Cr"(aq) + 7 H,0() 2 Cr (aq) 2 H,O() 2 Br"(aq) NO(g) + 2 H,0(0 CI"(aq) + 2 OH"(aq) Hg(f) - Ag(s) -- 2 Hg(() Fe"(aq) +1.51 → " +1.36 +1.358 +1.229 +1.066 +0.96 +0.89 +0.8535 +0.7991 +0.7960 +0.771 21(aq) +0.535 -4 OH"(aq) +0.401 (be)_HO d|(be).HO|(3)o Cu*(aq|Cu(s) Sn*(aq), Sa*(aq)|Pt Cu(s) +0.340 Sn*(aq) +0.15 H,(g) d|(3)H|(be),H Sn*"(aq)|Sn(s) Ni" (aq|Ni(s) PbSO,(s)|So; (aq)| Pb(s) Ca*(aq)|Cd(s) Fe* (aq)|Fe(s) Za" (aq)|Zn(s) H,O(0), OH"(aq)|H;(g)|Pt Al"(aq)|Al(s) Mg*(ag)|Mg (s) Na*(aq)|Na(s) Sn(s) -0.1375 -0.25 Ni (s) Pb(s) + So; (aq) - Cd(s) -0.3505 -0.403 Fe(s) -0.44 - Zn(s) H,(g) + 2 OH"(aq) -0.763 2 H,O() + 2 e" Al*(aq) + 3 e Mg"(aq) + 2e" Na*(aq) + e -0.8277 Al (s) -1.676 Mg(s) Na(s) -2.356 -2.714 K*iaa) + e" - Kisi -2.925 1. Can Aluminium solid reduce Au3+? Yes or No. Please simply explain your answer. 2. According to above given E0 values, which one is the strongest reducing agent? 3. According to above table can K+ be reducded with any reducing agent? if your answer is Yes, provide what you can use to reduce K+ into K(s). If your answer is No, explain why.
Transcribed Image Text:Standard Half-cell Potentials in Aqueous Solution at 25 °C* E* (V) Reduction Half-reaction Half-cell Reducing Agent - 2F"(aq) 2 H,O() PbSO,(s) + 2 H,Oo(e) Oxidizing Agent F(g) + 2e HO;(aq) + 2 H*(aq) + 2 e" PbO,(s) + So;"(aq) + 4 H"(aq) + 2e" Au"(aq) + 3e" Mno, (aq) + 8 H"(aq) + 5e Cr.O"(aq) +14 H*(aq) + 6e Cl(g) + 2e O,g) +4 H*(aq) + 4e Br() + 2e" NO, (aq) + 4 H*(aq) + 3e OCI"(aq) + H,O() + 2e Hg"(aq) + 2e Ag*(aq) +e Hg (aq) + 2e Fe"(aq) +e 1,(s) + 2e O,(g) + 2 H,O(O + 4e Cu*(aq) + 2 e" Sn* (aq) + 2e 2 H*(aq) + 2e Sn" (aq) + 2 e Ni"(aq) + 2e" PhSo,(s) + 2 e- Ca*(aq) + 2 e Fe"(aq) + 2 e Zn*(aq) + 2 e +2.87 d|(be).|(31 H,O,(aq), H"(aq), H,O(e)|P PBO,(s)|So; (aq). H"(aq)|PbSO,(s)|Pb Au"(aq)|Au(s) MnO, (aq), H*(aq). Mn*(aq>|Pt Cr,0;"(aq). H*(aq). Cr"(aq)|Pt Cl(g)|CI"(aq)|Pt 0,()|H" (ag) |Pt Brg|Br"(aq)|Pt NO, (aq). H*(aq)|NO(g)|P OcI (aq), C"(aq). OH"(aq|Pt Hg" (ag)| Hg (6) Ag (aq)|Ag(s) Hg3"(aq)|Hg(() Fe" (aq), Fe*(aq)|Pt 1,(s)|1"(aq)|P +1.763 +1.690 Au(s) +1.52 Mn"(aq) + 4 H,O(e) 2 Cr"(aq) + 7 H,0() 2 Cr (aq) 2 H,O() 2 Br"(aq) NO(g) + 2 H,0(0 CI"(aq) + 2 OH"(aq) Hg(f) - Ag(s) -- 2 Hg(() Fe"(aq) +1.51 → " +1.36 +1.358 +1.229 +1.066 +0.96 +0.89 +0.8535 +0.7991 +0.7960 +0.771 21(aq) +0.535 -4 OH"(aq) +0.401 (be)_HO d|(be).HO|(3)o Cu*(aq|Cu(s) Sn*(aq), Sa*(aq)|Pt Cu(s) +0.340 Sn*(aq) +0.15 H,(g) d|(3)H|(be),H Sn*"(aq)|Sn(s) Ni" (aq|Ni(s) PbSO,(s)|So; (aq)| Pb(s) Ca*(aq)|Cd(s) Fe* (aq)|Fe(s) Za" (aq)|Zn(s) H,O(0), OH"(aq)|H;(g)|Pt Al"(aq)|Al(s) Mg*(ag)|Mg (s) Na*(aq)|Na(s) Sn(s) -0.1375 -0.25 Ni (s) Pb(s) + So; (aq) - Cd(s) -0.3505 -0.403 Fe(s) -0.44 - Zn(s) H,(g) + 2 OH"(aq) -0.763 2 H,O() + 2 e" Al*(aq) + 3 e Mg"(aq) + 2e" Na*(aq) + e -0.8277 Al (s) -1.676 Mg(s) Na(s) -2.356 -2.714 K*iaa) + e" - Kisi -2.925 1. Can Aluminium solid reduce Au3+? Yes or No. Please simply explain your answer. 2. According to above given E0 values, which one is the strongest reducing agent? 3. According to above table can K+ be reducded with any reducing agent? if your answer is Yes, provide what you can use to reduce K+ into K(s). If your answer is No, explain why.
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