Quiz No.3 Note: Write all solution steps: QI Using Karnaugh-map to find the minimized SOP, draw the logic eircuit diagram for minimized Z. Z(A, B, C, D)-E(0, 1, 2, 3, 7, 8, 9, 10, 11, 12, 15)
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Q: Q1 Using Karnaugh-map to find the minimized SOP, draw the logic circuit diagram for minimized Z.
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A: The solution can be achieved as follows.
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- Q1/ Draw the logic circuit after simplify the circuit show below using K. map: A Y. C- Add filo B.Logic Design courses / EE200SP21 / General / Mid Term Examination Part II (Subjecti Compute the minimal products of sum and minimal sum of products expressions for following KMAP. Show your groupings on KMAP АВ CD 1 1 1 1 0. Instructions: You have to solve the answer by hand on paper, scan/take photo and upload it as a single file. Local Disk (D:) Mid Term Examinat.Design a combinational circuit with the four inputs A,B.C, and D, and three outputs X, Y, and Z. When the binary input is odd number, the binary output is one lesser than the input. When the binary input is even number the binary output is one greate than the input. Implement the function using multiplexers with minimal input and select line.
- Excess-3 code is significant for arithmetic operations as it overcomes shortcoming encountered while using 8421 BCD code to add two decimal digits whose sum exceeds 9. Excess-3 arithmetic uses different algorithm than normal non-biased BCD or binary positional number system. An electronics company has hired your services to design a code converter that converts Binary Coded Decimal (BCD) code for it. Design the converter.SUBJECT: DIGITAL DESIGN AND LOGIC CIRCUITS FOR COMPUTER ENGINEERS TOPIC: LOGIC DESIGN USING DECODER AND MUTLIPLEXER NOTE: I need full complete solution and correct. Thanks you so much. Please help me!! 1. Implement the logic function F(A, B, C) = AB' + BC + A'C' using 3x8 Decoder. 2. Implement the logic function F(A, B, C) = AB' + BC + A'C' using multiplexer. 3. Design a combinational circuit with three inputs, x, y, and z, and three outputs, A, B, and C. When the binary input is 0, 1, 2, or 3, the binary output is one greater than the input. When the binary input is 4, 5, 6, or 7, the binary output is two less than the input. Implement your design using multiplexer.USE DIGITAL LOGIC AND DESIGN Part 1: In Figure_4; we have 4-bit Comparator using 2-bit Comparators block. You have to satisfy given condition by applying all data on figure 4. At the end, given condition should produce HIGH output and other two should be LOW. A3 A2 A1 A0 = 1101 and B3 B2 B1 B0 = 1110 Figure_4 Part 2: The serial data-input waveform (Data in) and data-select inputs (S0 and S1) are shown in Figure_5. Determine the data-output waveforms from D0 through D3. Figure_5 Part 3: Decoder can be useful when we have to decode some specific numbers from their equivalent code. Figure 6 has a concept of 3 to 8 line decoder from which you have to generate output waveform from D0 to D7 with proper relationship to input. Figure_6 Part 4: The data-input and…
- answere fast please question from DIGITAL LOGIC DESIGN TOPIC : Designing Combinational Logic You are designing a water level circuit using 74ALS151 (8 to 1 Multiplexer IC)* When input is 0000 that means tank is empty.* When input is 1111 that means tank is full.* When input is below 5, that means water level is low.* So, make a circuit using 74ALS151 Multiplexer IC that shows a "low water" indicator light(by setting an output L to 1) when the water level drops below level 5.Q5 (a) Discuss, the major dıfferences between ticld programmable gatc arrays (FPGAS) and programmable logie devices (PLDS. where an FPGA may be approprate in a streamıng TV system. Simple multiplexers can be used to mimic a number of two-input logic functions by appropriate mapping of nputs X X, and SEL Show how the multiplexer shown in figure Q5a can be used to perform the function F= AOB (b) SEL Figure Q5a Figure Q5b (over) shows the schematic of a Xilinx 3000 sennes logic cell M Label the configuration bits of the various multiplexers n the celL with zeroed configuration bits selecting the topmost input to each multuplexer. Each multiplexer has -2 ns, the combinatorial loge block is guaranteed to have WS7 ns, and the D-type flip-flops have t4 ns and r 1 ns (c) We wish to construct a two-bit counter from this logie cell. where Q, and Q are the high and low order outputs of the counter, CLK is the clock signal, AR is an asynchronous reset signal, EN enables the counter, and LD allows…(a) A logic circuit shown in Figure Q.3 has a 4-bit input A and B, three 4-bit wide 2:1 muxes, a 4-bit adder, a 4-bit output F, and a carry flag C. For the given Table Q.3, fill in the value of output F and carry flag C for the given value of A, B, S0, S1 and S2. 51 52 1001 Flag C 0011 Figure Q.3 Table Q.3 A So S1 S2 F Flag C 0001 1000 0010 1001 1 1 0011 1101 0100 1101 1110 0111 1
- Electrical Engineering Verilog Design N-bit binary counter which counts the number from 0 to 2N-1. After reaching to maximum count i.e. 2N-1, it again starts the count from 0. i. Write the description of the counter in Verilog ii. Generate the design from the listing ii. Produce the waveforms of the counterConsider the circuit below. The switches are controlled by logic variables such that, if A is high, switch A is closed, and if A is low, switch A is open. Conversely, if B is high, the switch labeled is open, and if B is low, the switch labeled is closed. The output variable is high if the output voltage is 5V, and the output variable is low if the output voltage is zero. a. Write a logic expression for the output variable. b. Construct the truth table for the circuit. A Logic 1 5V(+ B C Logic 0 RDesign the following combinational logic circuit with a four-bit input and a three-bit output. The input represents two unsigned 2-bit numbers: A1 A0 and B1 B0. The output C2 C1.C0 is the result of the integer binary division A1 A0/B1 B0 rounded down to three bits. The 3-bit output has a 2-bit unsigned whole part C2 C1 and a fraction part CO. The weight of the fraction bit CO is 21. Note the quotient should be rounded down, i.e. the division 01/11 should give the outputs 00.0 (1/3 rounded down to 0) not 00.1 (1/3 rounded up to 0.5). A result of infinity should be represented as 11.1. A minimal logic implementation is not required. (Hint: start by producing a truth table of your design).