Part 1: Let M = 4 2 5 -5 48] 5 -15 -5 12 and let b 15 60 Part 2: Use the fact that = [24] 6 .There is a very obvious 3 1 solution to M = b that you should be able to find by inspection. What is it? is a basis for the null space of A, together with your previous answer to write down all the solutions of Mu= b in parametric vector form.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.4: Plane Curves And Parametric Equations
Problem 39E
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4
5
2
5
0
-15 15 60
solution to M = b that you should be able to find by inspection. What is it?
Part 1: Let M =
Part 2: Use the fact that
-5 48
-5 12 and let b
=
24
6
3
. There is a very obvious
is a basis for the null space of A, together with your
previous answer to write down all the solutions of MV = in parametric vector
form.
Transcribed Image Text:4 5 2 5 0 -15 15 60 solution to M = b that you should be able to find by inspection. What is it? Part 1: Let M = Part 2: Use the fact that -5 48 -5 12 and let b = 24 6 3 . There is a very obvious is a basis for the null space of A, together with your previous answer to write down all the solutions of MV = in parametric vector form.
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