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The surface integral is rewritten incorrectly. F((x, y)) is incorrect. The tangent vectors T, and T, are incorrect. The normal vector N is incorrect. No errors exist in the work shown. Compute f F d.S for the given oriented surface. F = (y, z, x), plane 5x - 6y + z = 1, 0 ≤ x ≤ 1, 0 ≤ y ≤ 1, upward-pointing normal (Express numbers in exact form. Use symbolic notation and fractions where needed.)

The surface integral is rewritten incorrectly. F((x, y)) is incorrect. The tangent vectors T, and T, are incorrect. The normal vector N is incorrect. No errors exist in the work shown. Compute f F d.S for the given oriented surface. F = (y, z, x), plane 5x - 6y + z = 1, 0 ≤ x ≤ 1, 0 ≤ y ≤ 1, upward-pointing normal (Express numbers in exact form. Use symbolic notation and fractions where needed.)

Trigonometry (MindTap Course List)
Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
Chapter6: Topics In Analytic Geometry
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The surface integral is rewritten incorrectly. F(Þ(x, y)) is incorrect. The tangent vectors T, and T, are incorrect. The normal vector N is incorrect. No errors exist in the work shown. Compute fFdS for the given oriented surface. F = (y, z, x), plane 5x − 6y + z = 1, 0 ≤ x ≤ 1, 0 ≤ y ≤ 1, upward-pointing normal (Express numbers in exact form. Use symbolic notation and fractions where needed.) ffs F ds =
Transcribed Image Text:The surface integral is rewritten incorrectly. F(Þ(x, y)) is incorrect. The tangent vectors T, and T, are incorrect. The normal vector N is incorrect. No errors exist in the work shown. Compute fFdS for the given oriented surface. F = (y, z, x), plane 5x − 6y + z = 1, 0 ≤ x ≤ 1, 0 ≤ y ≤ 1, upward-pointing normal (Express numbers in exact form. Use symbolic notation and fractions where needed.) ffs F ds =
Compute f F d.S for the given oriented surface. F = (y, z, x), plane 5x − 6y + z = 1, 0 ≤ x ≤ 1, 0 ≤ y ≤ 1, upward-pointing normal Consider the shown work. аф Tx = = əx Ty - аф dy = ə -(x, y, 1 - 5x + 6y) = (1,0,-5) dx д -(x, y, 1 − 5x + 6y) = (0, 1,6) dy ij k Tx x Ty = 1 0 -5 = 5i - 6j + k = (5, −6, 1) 0 1 6 Because the plane is oriented with upward-pointing normal, the normal vector is N = (5, -6, 1). F(Q(x, y)) = (x, y, 1 − 5x + 6y) F(Þ(x, y)) · N = (x, y, 1 − 5x + 6y) · (5, −6, 1) = 5x − 6y + 1 − 5x + 6y = 1 [], ds = [' L' FdS 1 dx dy Identify the first error in the work shown. The surface integral is rewritten incorrectly.
Transcribed Image Text:Compute f F d.S for the given oriented surface. F = (y, z, x), plane 5x − 6y + z = 1, 0 ≤ x ≤ 1, 0 ≤ y ≤ 1, upward-pointing normal Consider the shown work. аф Tx = = əx Ty - аф dy = ə -(x, y, 1 - 5x + 6y) = (1,0,-5) dx д -(x, y, 1 − 5x + 6y) = (0, 1,6) dy ij k Tx x Ty = 1 0 -5 = 5i - 6j + k = (5, −6, 1) 0 1 6 Because the plane is oriented with upward-pointing normal, the normal vector is N = (5, -6, 1). F(Q(x, y)) = (x, y, 1 − 5x + 6y) F(Þ(x, y)) · N = (x, y, 1 − 5x + 6y) · (5, −6, 1) = 5x − 6y + 1 − 5x + 6y = 1 [], ds = [' L' FdS 1 dx dy Identify the first error in the work shown. The surface integral is rewritten incorrectly.
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