Nitrous oxide N2O decomposes in a closed batch reactor at a temperature of1163 K into nitrogen and oxygen.The initial pressure of N2O in the reactor was 101.3 kPa. Calculate how long ittakes for the pressure in the reactor to rise to 141.3 kPa, if the decompositiontakes place with second-order kinetics, the gases behave ideally and the ratedecomposition constant has the value kc(N2O) = 0.977 dm³ mol-1 s-1 at the giventemperature.

To solve this problem, we can use the second-order rate equation for the decomposition of…

Answered: Nitrous oxide N2O decomposes in a…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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For the decomposition rate constant of methyl acetoxypropionate (=A) CH3COOCH(CH3)COOCH3(g) → CH3COOH(g) + CH2=CHCOOCH3(g) a value 0.0317 s-1 was found at 610 K. The decomposition is carried out at this temperature in a closed vessel having a volume of 20 dm³. This reactor initially contained 0.4 moles of pure acetoxypropionate. Assuming ideal gas phase behaviour, calculate: a) what will be the composition of the reaction mixture (in mole%) after 90 s from the start of the reaction, b) reactor pressure at this time.
In a study of the gas phase decomposition of dinitrogen pentoxide at 335 KN2O5(g)2 NO2(g) + ½ O2(g)the concentration of N2O5 was followed as a function of time.It was found that a graph of ln[N2O5] versus time in seconds gave a straight line with a slope of -6.20×10-3 s-1 and a y-intercept of -2.02 .Based on this plot, the reaction is order in N2O5 and the rate constant for the reaction is s-1.
In a study of the gas phase decomposition of dinitrogen pentoxide at 335 K N2O5(g) 2 NO2(g) + ½ O2(g) the concentration of N,O5 was followed as a function of time. It was found that a graph of In[N½O5] versus time in seconds gave a straight line with a slope of -7.29×103 s and a y-intercept of -1.44. Based on this plot, the reaction is v order in N,Og and the rate constant for the reaction is Submit Answer Try Another Version 2 item attempts remaining
In a study of the gas phase decomposition of dinitrogen pentoxide at 335 K N2O5(g)2 NO,(g) + ½ O2(g) the concentration of N2O5 was followed as a function of time. It was found that a graph of In[N,O3] versus time in seconds gave a straight line with a slope of -7.38×10-3 s and a y-intercept of -3.13. Based on this plot, the reaction is | order in N2O5 and the half life for the reaction i | seconds.
In a study of the gas phase decomposition of dinitrogen pentoxide at 335 K N2O5(g)2 NO2(g) + ½ O2(g) the concentration of N2O3 was followed as a function of time. It was found that a graph of In[N,05] versus time in seconds gave a straight line with a slope of -6.82×103 s and a y-intercept of -2.58 . Based on this plot, the reaction is first v order in N20z and the half life for the reaction is seconds.
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The Eºcell = 0.135 V for the reaction 31₂(s) + 5Cr₂O7²-(aq) + 34H*(aq) ? 6103¯ (aq) + 10Cr³+ (aq) + 17H₂O What is Ecell if [Cr₂O72] = 0.027 M, [H+] = 0.21 M, [103] = 0.00028 M, and [Cr³+] = 0.0030 M?
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[References) Use the References to access important values if needed for this question. In a study of the gas phase decomposition of dimethyl ether at 500 °C CH;OCH;(g)- →CH4(g) + H2(g) + CO(g) the concentration of CH,OCH, was followed as a function of time. It was found that a graph of In[CH,OCH] versus time in seconds gave a straight line with a slope of -6.28x10s and a y-intercept of -3.50 Based on this plot, the reaction i Đ order in CH,OCH, and the rate constant for the reaction is zero first second Submit Answer Try Another Version 2 item attempts remaining (Previous 12 étv ll MacBook Air 80 DII DD F2 F3 F4 F5 F6 F7 F8 F9 F10 F11 @ #3 $ & * 4 6. 7 8 W E R Y { S G J K く C V ...- ~の * 00 ラエ B
Writing the rate law implied by a simple mechanism Suppose the formation of tert-butanol proceeds by the following mechanism: step elementary reaction rate constant 1 (CH,),CBr(aq) → (CH3),C"(aq) + Br (aq) 2 (CH3),C"(aq) + OH (aq) → (CH3),COH(aq) kz Suppose also k,»k,. That is, the first step is much faster than the second. olo Write the balanced chemical equation for the overall chemical reaction: Write the experimentally- observable rate law for the overall chemical reaction. rate = k I Note: your answer should not contain the concentrations of any intermediates. Express the rate constant k for the overall chemical reaction in terms of k1, k2, and (if necessary) the rate constants k-1 and k.2 for k = the reverse of the two elementary reactions in the mechanism. olo ||

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