Neterence Nitrobenzene, C6 H5 NO2, an important raw material for the dye industry, is prepared from benzene, C6 H6 (molar weight 78.1 g/mol), and nitric acid, HNO3 according to the following chemical equation: C6 H6 (1) + HNO3 (1) → C6H5NO2 (1) + H2O(1) a. When 22.8 g of benzene and an excess of nitric acid are used, what is the theoretical yield of nitrobenzene (molar weight 123.1 g/mol)? Theoretical yield = b. If 32.3 g of nitrobenzene is recovered, what is the percentage yield? Percentage yield =

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Chapter5: Stoichiometry
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(References]
Nitrobenzene,
C6 H5 NO2, an important raw material for the dye industry, is prepared from benzene,
C6 H6 (molar weight 78.1 g/mol), and nitric acid,
HNO3 according to the following chemical equation:
C6 H6 (1) + HNO3 (1) → C,H5NO2 (1) + H2 O(1)
a. When 22.8 g of benzene and an excess of nitric acid are used, what is the theoretical yield of nitrobenzene (molar weight 123.1 g/mol)?
Theoretical yield =
b. If 32.3 g of nitrobenzene is recovered, what is the percentage yield?
Percentage yield =
%
Transcribed Image Text:(References] Nitrobenzene, C6 H5 NO2, an important raw material for the dye industry, is prepared from benzene, C6 H6 (molar weight 78.1 g/mol), and nitric acid, HNO3 according to the following chemical equation: C6 H6 (1) + HNO3 (1) → C,H5NO2 (1) + H2 O(1) a. When 22.8 g of benzene and an excess of nitric acid are used, what is the theoretical yield of nitrobenzene (molar weight 123.1 g/mol)? Theoretical yield = b. If 32.3 g of nitrobenzene is recovered, what is the percentage yield? Percentage yield = %
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