In the preparation of 60 mL Magnesium citrate in the laboratory, you are required to:calculate for the volume of Carbon dioxide released from the hydrated double salt of Magnesium carbonate when reacted with Citric acid if 2.57 g of Magnesium carbonate is used. MW of Magnesium carbonate = 485.65 g/mol H3C6H5O7 = 192.12 g/mol Equations: (MgCO3)4 .Mg(OH)2 .5H2O + 5H3C6H5O7 → 5MgHC6H5O7 + 4CO2 + 11H2O 3KHCO3 + H3C6H5O7 → K3C6H5O7 + 3CO2 + 3H2O Reacting ratio: 1mol (MgCO3)4 .Mg(OH)2 .5H2O = 4 mol CO2 1 mol of any gas at STP occupies a volume of 22.4 L or 22, 400 mL Choices: a 385.71 mL b 496.23 mL c 365.20 mL d 474.15 mL
In the preparation of 60 mL Magnesium citrate in the laboratory, you are required to:calculate for the volume of Carbon dioxide released from the hydrated double salt of Magnesium carbonate when reacted with Citric acid if 2.57 g of Magnesium carbonate is used. MW of Magnesium carbonate = 485.65 g/mol H3C6H5O7 = 192.12 g/mol Equations: (MgCO3)4 .Mg(OH)2 .5H2O + 5H3C6H5O7 → 5MgHC6H5O7 + 4CO2 + 11H2O 3KHCO3 + H3C6H5O7 → K3C6H5O7 + 3CO2 + 3H2O Reacting ratio: 1mol (MgCO3)4 .Mg(OH)2 .5H2O = 4 mol CO2 1 mol of any gas at STP occupies a volume of 22.4 L or 22, 400 mL Choices: a 385.71 mL b 496.23 mL c 365.20 mL d 474.15 mL
Introductory Chemistry: A Foundation
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ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter15: Solutions
Section: Chapter Questions
Problem 121AP: Calcium carbonate, CaCO3, can be obtained in a very pure state. Standard solutions of calcium ion...
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In the preparation of 60 mL Magnesium citrate in the laboratory, you are required to:calculate for the volume of Carbon dioxide released from the hydrated double salt of Magnesium carbonate when reacted with Citric acid if 2.57 g of Magnesium carbonate is used.
MW of Magnesium carbonate = 485.65 g/mol H3C6H5O7 = 192.12 g/mol
Equations:
(MgCO3)4 .Mg(OH)2 .5H2O + 5H3C6H5O7 → 5MgHC6H5O7 + 4CO2 + 11H2O
3KHCO3 + H3C6H5O7 → K3C6H5O7 + 3CO2 + 3H2O
Reacting ratio: 1mol (MgCO3)4 .Mg(OH)2 .5H2O = 4 mol CO2
1 mol of any gas at STP occupies a volume of 22.4 L or 22, 400 mL
Choices:
a |
385.71 mL |
|
b |
496.23 mL |
|
c |
365.20 mL |
|
d |
474.15 mL |
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