In Figure 4C, we see the inhibition of LRRK2 kinase activity by nanobody 1 (Nb1).  Using the Lineweaver-Burke plot,  estimate the Km of LRRK2 in the absence of Nb1.  Show your work and provide your answer with the correct units.

Curren'S Math For Meds: Dosages & Sol
11th Edition
ISBN:9781305143531
Author:CURREN
Publisher:CURREN
Chapter14: Formula Method
Section: Chapter Questions
Problem 3.1P
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In Figure 4C, we see the inhibition of LRRK2 kinase activity by nanobody 1 (Nb1).  Using the Lineweaver-Burke plot,  estimate the Km of LRRK2 in the absence of Nb1.  Show your work and provide your answer with the correct units.

A
Arm
Ank LRR
Arm
Ank
LRR
2527
2527
Roc! COR
Kinase WD
Roc! COR
Kinase
WD
Rab P
1.54
: peptide substrate
1.5-
1.0-
1.0-
0.5-
0.5-
0.0
0.0
C
E
Nb1
Nb6
120-
Nb23
120-
宽1201
100-
100-
80-
80-
80-
60-
60-
60
40-
S 40-
40-
20-
|C50
20-
20-
IC 50= 8 ± 2 µM
IC 50= 14 ± 3 µuM
0-
65 μΜ
-2
-1
1
2
3
-3
-2
-1
1
2
-2
-1
1
2
3
Log [Nb1] (uM)
Log [Nb6] (uM)
Log [Nb23] (µM)
KaPP= 16 ± 4 µM
K
app= 5±1 µM
Kapp= 9 + 1 uM
40000-
100000-
a = 1.8 ± 0.5
a = 1.6 ± 0.4
a = 8 ± 2
40000-
30000-
75000-
30000-
50000-
20000-
20000 -
25000-
10000-
10000-
200
400
600
800
1000
200
400
600
800
1000
200
400
600
800
1000
[ATP] (uM)
[AΤΡΙ (μΜ)
[AΤPΙ (μΜ)
0.00010
0.0008
0.0006-
0.00005-
0.0004-
0.0003-
-0.02
-0.01
0.01
0.02
0.03
-0.02
0.01
0.01
0.02
0.03
-0.02
-0.01
0.01
0.02
0.03
[1/ATP] (µM1)
[1/ATP] (µM1)
[1/ATP] (µM^1)
-- (0 μΜ)
- (2.5 µM)
(5 μΜ)
(20 μΜ)
(50 μΜ)
(0 μΜ)
(2.5 μΜ )
(5 µM)
(20 μΜ)
(50 μΜ)
- (0 μΜ)
(10 μΜ)
( 30 μΜ)
(60 μΜ)
(100 μΜ)
Nb17
% Activity
Nb36
Nb38
Nb39
Nb42
relative velocity
Nb1
Nb6
Nb22
Nb23
Nb40
1/rel. velocity
MLi-2
No Nb
% Activity
relative velocity
Nb17
Nb36
Nb38
1/rel. velocity
Nb39
Nb42
Nb1
3
Nb6
% Activity
Nb22
Nb23
Nb40
relative velocity
MLi-2
No Nb'
1/rel. velocity
Transcribed Image Text:A Arm Ank LRR Arm Ank LRR 2527 2527 Roc! COR Kinase WD Roc! COR Kinase WD Rab P 1.54 : peptide substrate 1.5- 1.0- 1.0- 0.5- 0.5- 0.0 0.0 C E Nb1 Nb6 120- Nb23 120- 宽1201 100- 100- 80- 80- 80- 60- 60- 60 40- S 40- 40- 20- |C50 20- 20- IC 50= 8 ± 2 µM IC 50= 14 ± 3 µuM 0- 65 μΜ -2 -1 1 2 3 -3 -2 -1 1 2 -2 -1 1 2 3 Log [Nb1] (uM) Log [Nb6] (uM) Log [Nb23] (µM) KaPP= 16 ± 4 µM K app= 5±1 µM Kapp= 9 + 1 uM 40000- 100000- a = 1.8 ± 0.5 a = 1.6 ± 0.4 a = 8 ± 2 40000- 30000- 75000- 30000- 50000- 20000- 20000 - 25000- 10000- 10000- 200 400 600 800 1000 200 400 600 800 1000 200 400 600 800 1000 [ATP] (uM) [AΤΡΙ (μΜ) [AΤPΙ (μΜ) 0.00010 0.0008 0.0006- 0.00005- 0.0004- 0.0003- -0.02 -0.01 0.01 0.02 0.03 -0.02 0.01 0.01 0.02 0.03 -0.02 -0.01 0.01 0.02 0.03 [1/ATP] (µM1) [1/ATP] (µM1) [1/ATP] (µM^1) -- (0 μΜ) - (2.5 µM) (5 μΜ) (20 μΜ) (50 μΜ) (0 μΜ) (2.5 μΜ ) (5 µM) (20 μΜ) (50 μΜ) - (0 μΜ) (10 μΜ) ( 30 μΜ) (60 μΜ) (100 μΜ) Nb17 % Activity Nb36 Nb38 Nb39 Nb42 relative velocity Nb1 Nb6 Nb22 Nb23 Nb40 1/rel. velocity MLi-2 No Nb % Activity relative velocity Nb17 Nb36 Nb38 1/rel. velocity Nb39 Nb42 Nb1 3 Nb6 % Activity Nb22 Nb23 Nb40 relative velocity MLi-2 No Nb' 1/rel. velocity
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