II.7- Saponification, initial rates and half-lifeAn esterification reaction is studied at 350 K under conditions where the reaction is complete:ROH + R'COOH→ R'COOR + H20For the same initial alcohol concentration, and variable acid concentrations, we obtain the followingcurves of evolution of the acid concentration versus time:[R'COOH] (mol L'')-0.8-0.6-0.4--0.2406080100120140160180200The rate v of this reaction follows the law v = k[R°COOH]ª [ROH]F.1) Explain how to graphically determine an instantaneous velocity (rate) at time t.20

A esterification reaction is a reaction between an alcohol and a carboxylic acid that results in the…

Answered: II.7- Saponification, initial rates and…

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter11: Chemical Kinetics: Rates Of Reactions

Section: Chapter Questions

Problem 113QRT

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Define stability from both a kinetic and thermodynamic perspective. Give examples to show the differences in these concepts.
11.48 The following data were collected for the decomposition of NT),-: Time, f (min) [N2Os] (mol L-1) 0 0.200 5 0.171 10 0.146 15 0.125 20 0.106 25 0.0909 30 0.0777 35 0.0664 40 0.0570 Use appropriate graphs to determine the rate constant for this reaction. Find the half-life of the reaction.
Two mechanisms are proposed for the reaction 2NO(g)+O2(g)2NO2(g)Mechanism 1: NO+O2NO3(fast) NO3+NO2NO2(slow) Mechanism 2: NO+ON2O2(fast) N2O2+O22NO2(slow) Show that each of these mechanisms is consistent with the observed rate law: rate=k[ NO2 ]2[ O2 ].
Some bacteria are resistant to the antibiotic penicillin because they produce penicillinase, an enzyme with a molecular weight of 3104 g/mol that converts penicillin into inactive molecules. Although the kinetics of enzyme-catalyzed reactions can be complex, at low concentrations this reaction can be described by a rate equation that is first order in the catalyst (penicillinase) and that also involves the concentration of penicillin. From the following data: 1.0 L of a solution containing 0.15 g ( 0.15106 g) of penicillinase, determine the order of the reaction with respect to penicillin and the value of the rate constant. [Penicillin] (M) Rate (mol/L/min) 2.0106 1.01010 3.0106 1.51010 4.0106 2.01010
A proposed mechanism for the gas-phase chlorination of methane is Cl2+CH4CH4Cl+ClCH4ClCH3+HClCH3+Cl2CH3Cl+ClCl+CH4CH3+HCl Suppose the first step is the RDS. What is the expected rate law in terms of the original reactants, Cl2 and CH4? How would you determine if this mechanism might be a potentially correct or, for that matter, a potentially incorrect one?
Determine a rate law for the chlorination of methane assuming that the second step is the rate-determining step and that the first step can be approximated by the steady-state approximation. What is the difference between the answer here and the answer for the previous exercise?
Can a reaction mechanism ever be proven correct? Can it be proven incorrect?
The reaction NO(g) + O,(g) — NO,(g) + 0(g) plays a role in the formation of nitrogen dioxide in automobile engines. Suppose that a series of experiments measured the rate of this reaction at 500 K and produced the following data; [NO] (mol L ’) [OJ (mol L 1) Rate = -A[NO]/Af (mol L_1 s-1) 0.002 0.005 8.0 X 10"'7 0.002 0.010 1.6 X 10-'6 0.006 0.005 2.4 X IO-'6 Derive a rate law for the reaction and determine the value of the rate constant.
For the past 10 years, the unsaturated hydrocarbon 1, 3-butadiene (CH2 = CH - CH = CH2) has ranked 38th among the top 50 industrial Chemicals. It is used primarily for the manufacture of synthetic rubber. An isomer exists also as cyclobutene: The isomerization of cyclobutene to butadiene is first-order and the rate constant has been measured as 2.0104s1 at 150 C in a 0.53-L ?ask. Determine the partial pressure of cyclobutene and its concentration after 30.0 minutes if an isomerization reaction is carried out at 150 C with an initial pressure of 55 torr.
The hydrolysis of the sugar sucrose to the sugars glucose and fructose, C12H22O11+H2OC6H12O6+C6H12O6 follows a first-order rate equation for the disappearance of sucrose: Rate =k[C12H22O11] (The products of the reaction, glucose and fructose, have the same molecular formulas but differ in the arrangement of the atoms in their molecules.) (a) In neutral solution, k=2.11011s1 at 27 C and 8.51011s1 at 37 C. Determine the activation energy, the frequency factor, and the rate constant for this equation at 47 C (assuming the kinetics remain consistent with the Arrhenius equation at this temperature). (b) When a solution of sucrose with an initial concentration of 0.150 M reaches equilibrium, the concentration of sucrose is 1.65107M . How long will it take the solution to reach equilibrium at 27 C in the absence of a catalyst? Because the concentration of sucrose at equilibrium is so low, assume that the reaction is irreversible. (c) Why does assuming that the reaction is irreversible simplify the calculation in pan (b)?
The gas-phase reaction of nitrogen monoxide with chlorine proceeds to form nitrosyl chloride. 2NO(g)+Cl2(g)2NOCl(g)rate=k[NO]2[Cl]2 Evaluate the following proposed mechanism to determine whether it is consistent with the experimental results, and identify intermediates, if any. 2NOk1k1N2O2Fast,reversibleN2O2(g)+Cl2(g)2NOCl(g)Slow(rate-limiting)step
Pyrolysis involves heating compounds to break them into smaller molecules, and typically involves free-radical chain reactions. Pyrolysis of crude oil fractions is a common method of making smaller hydrocarbons from large-chain hydrocarbons. Pyrolysis of ethane, C2H6, forms ethylene and hydrogen gases C2H4 and H2 as the primary products. Suggest a mechanism for this pyrolysis reaction, labeling your reactions as initiation, propagation, and termination steps.

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