(e) Show that va € R, Ve > 0,38 >0 such that f((a-8,a+5)) (f(a)- e. f(a)+c) is equivalent Ao the definition of f is continuous everywhere.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.1: Inverse Functions
Problem 18E
icon
Related questions
Question
100%

Please answer this question in the red circle

For this problem, let f: R→ R be a function. We say that a non-empty set UCR is ajar if
Vu EU, 3r> 0 such that (u-r, u + r) CU.
(a) Show that (0, 2) is ajar.
(b) Find a set that is not ajar. You don't need to prove it.
My set is
In the following parts, we will use the follow two definitions.
For A CR, we define f(A) = {f(a): a € A}.
For BCR, we define f¹(B) := {r € R: f(r) € B} .
Note that f(A) and f-¹(B) are both sets.
(c) Show that va € R, Ve > 0,36 >0 such that f((a-d, a +5)) (f(a)- e, f(a) + e) is equivalent
to the definition of f is continuous everywhere.
Transcribed Image Text:For this problem, let f: R→ R be a function. We say that a non-empty set UCR is ajar if Vu EU, 3r> 0 such that (u-r, u + r) CU. (a) Show that (0, 2) is ajar. (b) Find a set that is not ajar. You don't need to prove it. My set is In the following parts, we will use the follow two definitions. For A CR, we define f(A) = {f(a): a € A}. For BCR, we define f¹(B) := {r € R: f(r) € B} . Note that f(A) and f-¹(B) are both sets. (c) Show that va € R, Ve > 0,36 >0 such that f((a-d, a +5)) (f(a)- e, f(a) + e) is equivalent to the definition of f is continuous everywhere.
Expert Solution
steps

Step by step

Solved in 3 steps with 2 images

Blurred answer
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage
Calculus For The Life Sciences
Calculus For The Life Sciences
Calculus
ISBN:
9780321964038
Author:
GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:
Pearson Addison Wesley,